80% of such proofs are division by zero; 10% are flipping around square root (case here); 5% summing divergent series.
@merlinkestrel7716Ай бұрын
I think there are 5% missing there brotha
@Prof-Joe-HАй бұрын
@@merlinkestrel7716 Rightly so: The remaining 5% are about messing around with percentages. 😉
@asdfqwerty14587Ай бұрын
@@merlinkestrel7716 There are lots of weird ways to create these kinds of false proofs, a full list of them would be excessively long.
@scarletevans4474Ай бұрын
I petition for extra 5% for false proofs using complex numbers, like: e^(2i𝜋) = 1 = sqrt(1) = sqrt(e^(2i𝜋)) = e^(2i𝜋/2) = e^(i𝜋) = -1 Thus, 1 = -1.
@sanamiteАй бұрын
@@merlinkestrel7716It's not exhaustive, that would take years to find all the similar proofs ever made (ok maybe more than years, and probably impossible)
@j.n.-fr5uhАй бұрын
the mistake is the part where it says 2+2=5
@NavieddamoocАй бұрын
I am the mistake
@volodyanarchistАй бұрын
Then this proves that 2+2 4
@NavieddamoocАй бұрын
@@volodyanarchist yesir
@farhanrejwanАй бұрын
what basically happened here is, by assuming -1/2 = 1/2, they 'proved' that from 2+2=4 we can get 2+2=5.
@johnjeffreys6440Ай бұрын
Ya, it's not really a mistake, it's just false.
@9adam4Ай бұрын
"Let's start at the bottom, because the mistake is at the top and I want a longer video."
@FredThe-d1qАй бұрын
Yeah, it's the first step that's so obviously wrong.
@Warcraft_TravelerАй бұрын
@@FredThe-d1q Nothing wrong with the 1st step. You can add and substract the same number to anything and you end up with the same result. The 2nd step however ...
@FredThe-d1qАй бұрын
@@Warcraft_Traveler Ok, 2nd step.
@potatomudkipАй бұрын
@@FredThe-d1qTo be fair, its technically correct in the same way that squares are technically rectangles. Yea, but conventionally no.
@pettrovichАй бұрын
My thoughts exactly
@msdppdsmАй бұрын
This proof goes something like this: 4 = 4-4.5+4.5 = |4-4.5| + 4.5 = |4.5-4| + 4.5 = 4.5-4+4.5= 5
@Patrik6920Ай бұрын
the promplem is it ty to proove that -2 = √(-2)², √(-2)² = i√(2)² =i√4 = i2 ≠ -2
@chriswebster24Ай бұрын
That’s a pretty big promplem, if you ax me.
@grumpysanta6318Ай бұрын
Yes, it only works for very large values of 2.
@1tubaxАй бұрын
🤣🤣
@volodyanarchistАй бұрын
Or even values of 5... except when it is 6.
@simonmesserli7426Ай бұрын
😂😂😂😂😂😂
@Vex-MTGАй бұрын
This exactly. 2 is not 2.0
@jssamp4442Ай бұрын
Perfect! Only when 2 >> 2.
@OrangeDinoRBLXАй бұрын
hear me out guys: if you put 2 and 2 together it’s 22. what’s the 22nd letter of the alphabet? V. What is that in Roman Numerals? 5. Point proven.
@MasterTMOАй бұрын
This answer is more valid...
@mikeguilmette7765 күн бұрын
Rocky V plus Rocky II equals . . . Rocky VII, Adrian's Revenge!
@darksidegaming9806Ай бұрын
POV of an Engineer : 2 + 2 = 5 Cause, 2 = e => e = π => π = 3 ==> 2 + 2 = 2 + 3 = 5 Or More is better than getting in problem if the calculation is mistaken.
@scarletevans4474Ай бұрын
e+e = 2e 2.something + 2.something = 5.something so approximately: 2 + 2 = 5
@farhanrejwanАй бұрын
@@scarletevans4474 math students back then : e + e = 2e math students now : e + e = eeeeeeeeeeeeeeee
This reminds me of the electrical engineer who tried to tell me that the reciprocal of zero is infinity . . . because zero has an infinitesimal value. I asked him how many fires he's started.
@yensteel5 күн бұрын
I actually recently read about how NASA wasted $327 Million dollars for their mars space probe mission because their different departments were using the Metric and Imperial system simultaneously and assumed the other departments were aligned. So acceleration was way off and the probe crashed.
@DanielWalvinАй бұрын
The problem is simply that squaring is not an invertible function, "√(x²) = x" is only true for positive numbers and 0, not negative ones. So the error comes in already on the second line: 4 - 9/2 = -1/2, √((4 - 9/2)²) = √((-1/2)²) = √(1/4) = 1/2, -1/2 ≠ 1/2. Donezo.
@MichaelPizАй бұрын
I'm going to use "donezo" instead of Q.E.D. from now on.
@DanielWalvinАй бұрын
@@MichaelPizHeehee, love to hear it! XD
@ryanbiАй бұрын
❤😊
@aristokatclaude3413Ай бұрын
Ah! now we have a proof for -1/2 = 1/2
@Bill_W_CipherАй бұрын
What I do when I see these kinds of fake proofs is that I compute the value of each of these, and find when the value changes. Then I look at that step and direct all my attention to it and try to figure out why its wrong.
@gavindeane3670Ай бұрын
Exactly. Once you've done that for a few of them, it becomes clear they tend to use the same fallacy. Divide by zero is a common one. Another common one, as here, is doing √(x²) = x with a negative value for x. Once you're used to the common errors it's easy to identify them.
@foogod4237Ай бұрын
Easy: They're using square roots. Find the step where they're taking the square root of the square of a negative number. That's the mistake. That's _always_ the mistake. (as it happens, if you go top to bottom, it's the very first step that has a square root in it)
@plonksterАй бұрын
I didn't even see the number was negative. I just saw the square root of the squared term and immediately knew they are banking on having two roots.
@logicplagueАй бұрын
Been a while since college, but isn't this where imaginary numbers come in? (oh, the irony)
@steffenjensen422Ай бұрын
I kept looking for the part where they sneakily divide by zero and completely missed that they messed up the square root instead.
@gavindeane3670Ай бұрын
@@logicplagueNo. Imaginary numbers come in when you are taking the square root of a negative number. That's not what the "proof" is doing here. The "proof" is doing √(x²) with a negative value of x. Imaginary numbers come into it when you do √x with a negative value of x.
@gavindeane3670Ай бұрын
Quite often the mistake in these "proofs" is dividing by zero.
@bhaskar_yoursАй бұрын
My teachers taught me to never cross out square and square roots when you see them together. Here's what he taught me to do instead: f(x) = √(x²) = | x | which results in for example: f(1) = 1 which follows x = x as x is +ve f(-1) = 1 which follows x = - x as x is -ve
@R00KIE_GUYАй бұрын
As an engineer, 2+2 does equal 5. 2+2=4 plus 1 for safety, which gives us 5. ¯\_(ツ)_/¯
@queefyg490Ай бұрын
Square root of square implies absolute value this means they add the 0.5 to 4.5 instead of subtracting. Step 2
@m3tz-05Ай бұрын
2 + 2 = 5 Proof by Radiohead
@balorpriceАй бұрын
I came to the comments section to ensure everyone's been paying attention, paying attention, paying attention
@yeetusfetusdeletusАй бұрын
i really want your comment to get to the top grrr
@kenmore01Ай бұрын
My biggest wonder is why anyone would go through such a lengthy and time consuming process to prove something they know is not true.
@wildgurgs3614Ай бұрын
For the meeeeeeeeeemes
@extremecentrism9796Ай бұрын
Some people just want to watch the world burn
@bjornfeuerbacher5514Ай бұрын
It's an elaborate form of trolling.
@velisvideos6208Ай бұрын
Who says this isn't true? The Deep State is trying to force us believe that old 2+2 = 4 trope. No more! Probably George Soros is involved somehow.
@trueriver1950Ай бұрын
To see if they can find a counter example. This would then make the whole of number theory inconsistent, but just think of the fame if you were the one to find it...
@akashgarg5770Ай бұрын
in 1 line, all they did is replaced (4-9/2)^2 = (5-9/2)^2 i.e. (-0.5)^2 = (0.5)^2
@marcusscience23Ай бұрын
I have an interesting story about square-root functions: When we were learning about quadratic functions in Math class, we were taught that a parabola could intersect the x-axis at 2 points, 1 point, or 0 points. When asked what happens with the y-axis, my Math teacher actually challenged us to make a parabola that didn’t cross the y-axis. I knew she didn’t expect any of us to get it, since any quadratic function y = ax^2 + b^x + c necessarily intersects the y-axis at (0 , c), so it will always intersect the y-axis once. But I quickly realized what she hasn’t: parabolas could be rotated. I graphed out x = y^2 + 1 , a rotated parabola that evidently did not cross the y-axis. It would have been some sort of a square-root function. After showing it to her, my teacher was confused at first, but admitted I had beaten the challenge. Later, when we were learning about functions, she showed my parabola to the class as an example of a graph which wasn’t a function (as it failed the vertical line test), and explained that it was actually two functions side-by-side: one with the positive square root of (x - 1) and the other with the negative square root of (x - 1). So, the point is that a square root graph is a relation, but not a function. However, it can be split into 2 separate functions, one with the positive square root and the other with the negative square root. You just need to make sure you know which one to use, so you can avoid errors like this false proof.
@trueriver1950Ай бұрын
Square roots are sometimes described as a mapping rather than a relation. I'm personally unclear about whether that's saying the same thing or something subtly different but, ummmm, related
@PoppySuzumi1223Ай бұрын
A positive number has a positive and a negative square root; the positive root is called the principal root (Absolute root |x|) , the negative root is called the imaginary root (Complex root ix). When you know that, everything's will be clearer to understand. e.g. √16 = +4 only, as the rule of principal root, i.e. √16 = |±4| = 4 But both 4 and - 4, when squaring them, both are 16 as it is what *Squaring* means.
@Prof-Joe-HАй бұрын
In between you are mixing up a negative root (-x) with an imaginary root (ix). The given problem is about the squaring of real numbers not being injective, which is intelligible in the real numbers domain without involving complex numbers. Yet, in the complex domain, there is a similar situation regarding the square root of a negative real number, where +ix and -ix (positive imaginary and negative imaginary) will be considered. 🤓
@thomaslangbein297Ай бұрын
What have imaginary numbers got to do with negative numbers? You certainly mean the right thing, but you have to work on your argumentation line. Principal roots is a terminus of complex algebra. The (positive) sqr of a positive numbers is always positive (per definitionem). It’s as simple as that. And a square of any real number (unless 0) is positive.
@Firelordthe64thАй бұрын
This is positive number supremacy and lies told by big math
@argoneumАй бұрын
Absolute value extends to complex numbers as modulus. The absolute length of a vector, no matter the direction 😸
@coreyyanofskyАй бұрын
you can skip checking line by line for all the manipulations under the radical: at the top you have (-0.5)² and at the bottom you have (0.5)² and these are obviously equal
@cookiesandcream7Ай бұрын
literally 1984
@Warcraft_TravelerАй бұрын
Mistake on the 3rd line. On the 2nd line, 4-9/2 makes -1/2. On the 3rd, because of the squareroot-squaring we end up with +1/2. 1/2-(-1/2)=1, so we have a difference of 1 with the original statement.
@williamzeng464Ай бұрын
from 0:46 i can already see the problem; roots always have positive and negative answers, people are ignoring the negative one and using it as an absolute value function, which is wrong
@abysslight2490Ай бұрын
The big takeaway from this is that while we think of square and square root as inverse operations, "cancelling the operation out" using function composition does not work both ways. Normally, for any function f(x), f(f⁻¹(x)) = x AND f⁻¹(f(x)) = x. However, for squares and square roots, this is not the case. if f(x) = x², and f⁻¹(x) = √x, f(f⁻¹(x)) = x, meaning (√x)² = x, but f⁻¹(f(x)) = |x|, meaning √x² = |x|, not just x. If you take the square root first, it works. If you square first, it only works if your number is positive. 4 - 9/2 is not positive.
@thomaslangbein297Ай бұрын
That’s too easy. 4-9/2 is negative. The sqr of its square is positive. Magicians have to hide there tricks better.
@ZorligАй бұрын
It's so nice of them to put the error in the very first (second?) line so it doesn't take much effort to solve.
@Peter_1986Ай бұрын
Basically, the solution steps turned 4 - 9/2 into its absolute value.
@GRACFUL1Ай бұрын
Don't let the math control you, you control the math.
@Herby-1620Ай бұрын
The other trick is to divide by zero in some form of variable pair or some such.
@aComedicPianistАй бұрын
This is also why you should simplify on each step if you can, make the radical and power into a fractional exponent, and definitely simplify the fractional exponent, e.g. 2/2 = 1. You should also do the root first (after simplifying the fractional exponent) to prevent problems like this from arising.
@mirandahotspring4019Ай бұрын
This is one of those, "Let's make the problem look so complicated no one will bother to check it." solutions.
@robinlindgren6429Ай бұрын
the issue lies in taking the square root of the square of x and equating it to x. sqrt(x^2) is not x. it is the absolute value of x. 4-9/2 = -0.5 sqrt((4-9/2)^2) = 0.5 sqrt((5-9/2)^2) = 0.5 5-9/2 = 0.5
@teelo12000Ай бұрын
Note that if we denote that we're taking the secondary (negative) root of the square root in the original proof, the end result becomes the expected 4.
@abhirupkundu2778Ай бұрын
The biggest mistake in this problem is assuing square root returns negative values when it is clearly defined to be a one-one function with unique outputs(positive real numbers) when any thing is put as an input in its domain(positive numbers once again)
@XxProGamerUSAxXАй бұрын
"whatever stretches the video the furthest" -this man making the video
@hkcprivate6977Ай бұрын
this was SO obvious and I'm at 0:45 and I figured it out. 4 - 4.5 is -0.5, but taking the square root of a squared number takes the abs so that's like saying -0.5 = 0.5
@---Sasha---Ай бұрын
bro started from the bottom for more watch time, not mad at him tho
@catakuri6678Ай бұрын
the mistake is the line that said: 2+2=4 because that's not what they're trying to prove
@waulbrychi_schparkuАй бұрын
The third step is wrong (sqrt((4-9/2)²)+9/2) , bc sqrt of square is an absolute value
@ThePowerfulOne07Ай бұрын
I’ve debated with people about taking the square root of a number squared. Gotta be careful!
@kenmore01Ай бұрын
Cool party vibe!! 😁
@trueriver1950Ай бұрын
sqrt ( x^2 ) simplifies to abs (x), for any real x, as by definition sqrt always returns the positive root This trick is used indirectly by electrical engineers when they calculate the RMS of a sine wave
@susanarendasАй бұрын
Why would you put this on KZbin? And going backwards to prove this is inaccurate and just a silly waste of time, and more thoroughly confusing to the student who is truly trying to learn. Find a better hobby!
@VaresBonneАй бұрын
7:54 why not use the bottom side of the equation then? why top side?
@alanalvarado8896Ай бұрын
I’m pretty sure it’s bc the equation of the inverse function is x = sqrt(y), and if y was negative (if we used the bottom side of the equation), we would have imaginary numbers for x.
@handanyldzhan9232Ай бұрын
Well, finding the square root of a square can lead to "wizardry" like that.
@ai314159Ай бұрын
Alternatively, the second step makes the choice of the negative branch of the square root. Then we also have to take the negative branch in the penultimate step, getting 9/2 - 5 + 9/2 = 4.
@sr6424Ай бұрын
One lesson here. When you solving an algebraic problem. It might be good to square both sides and apply the root later. You need to take the plus and minus roots. Then check the answers in the original equation!
@Maths_WonderlandАй бұрын
Where is the ending music? 🧐🧐🧐
@Neodynium.the_permanent_magnetАй бұрын
My guess is some royalties issue?
@deadshot9982Ай бұрын
8:34 I don’t understand how the graph disproves anything. (-2)^2 = 4, 2^2 = 4, sqr(4) = +-2. It can’t get any simpler than that. Am I just supposed to believe that your method is right even though there’s no reason for mine to be wrong?
@sicknerd2929Ай бұрын
I think the problem lies in the way square root is defined in lower classes. It is simply described as a number which when squared gives us the desired number But that is not how we use it during real calculations. We don't see x^2 = a and write x=sqrt(a). We write x=+-sqrt(a). Which means sqrt (a) alone does not cover all the values which when squared give a. It only refers to the positive value that when squared gives a. So the real definition of a square root should be: A **positive value** that when squared gives us the desired number. In this new light it is incorrect to write 4-9/2 as sqrt(4 -9/2) ^2 since sqrt(4-9/2) ^2 is not 4-9/2 but the positive quantity 9/2-4. Hope it helps
@gavindeane3670Ай бұрын
The "proof" is using the √ symbol. √4 is not ±2. √4 is 2. ±√4 is ±2
@ismailshtewi8560Ай бұрын
i spent so long on this hunting for a point where they hid a division by zero
@Elleander1Ай бұрын
Spotted the mistake immediately, I feel pretty nice
@cpsofАй бұрын
Binary search is a lot more effective way to find the mistake. Compute the value in the middle and if it's 4, the mistake is later, and if it's 5, the mistake is earlier. Then you can repeat this for the upper or lower half and keep halving the search range until the mistake is found.
@22dolls19Ай бұрын
"The mistake is that I did nothing wrong, no reason to be dragged inside minilove"
@PeacefulCommuniteeАй бұрын
Well thats why Axioms and Postulates are there..❤
@baxtermullins1842Ай бұрын
Star Wars quote:”It’s a trap!”
@timschommer8548Ай бұрын
I see he took feedback on board from the last video that handled square roots. Apprciated. Also makes me giggle a little bit, because it is fun to see those things evolve.
@ravikiranpalaparthi61523 күн бұрын
√[4-(9/2)]² has the error. 4-(9/2) = 4-4.5 = -0.5, square root cannot be applied to negative numbers.
@marxcarton3858Ай бұрын
Order of operations is allways the biggest mistake. Expanding a numerical value as if it is a quadratic then adding together the numerical value to get another value is like saying (x+2)^2 = x^2 + 4x + 4 and 4x+4=8☠☠
@henke37Ай бұрын
My gut called it being a squaring negatives issue. And that the error was at the beginning.
@joeschmo622Ай бұрын
2 + 2 = 5, for sufficiently large values of 2.
@abcde_5949Ай бұрын
It's always the negative root trick
@nonroutineganit7682Ай бұрын
√(4 - 9/2)² = | 4 - 9/2 | At the 2nd step you are wrong
@bundzsiАй бұрын
By definition sqrt(x^2) = |x| and not just x. This is where this proof fails
@kaydenlimpert2779Ай бұрын
i looked through the proof and saw that 4-9/2 was negative which would mean you need a - at the beginning
@dulcinealee3933Ай бұрын
Where did the 9 come from?
@MaryMusatАй бұрын
De sub radical de scoate in modul : 9/2-5+9/2=9-5=4
@nycholdАй бұрын
4 - 9/2 is negative, so just pulling it into a radical is a violation even as a square, as it would require a negative number coming out of a square root, which is technically impossible.
@aryangupta211Ай бұрын
At timestamp 5:15 You are wrong .... Because as you would explain later √(x *x) = x , sign will the decided by value of x. Here, although it is indeed √(1/4) but is actually √((-1/2)(-1/2)) hence, it will be (-1/2) and not (+1/2). The actual mistake lies in the second last line while factoring. Where a grouping of squared term is done the wrong way. For example, (a² - 2ab + b² ) = (a-b)² . But how can you so sure that it is not (b-a)² . There, the mistake is the same wrong interpretation of this additive identity.
@josephwest124Ай бұрын
It's been many a year since I took a math class but my biggest question is "Where did the value of '-9/2 + 9/2' come from in the initial step?" Why not use "-16/9 + 16/9" or "-22/7 + 22/7" instead? I mean, simply inserting a "sum" of fractions to an equation is not something I recall from any of my algebra, geometry, trig or calculus classes. (I do remember the old "proof" of "2 + 2 = 5" by resorting to the mathematically illogical step of dividing by zero--it's been years and I don't recall the specifics of that "proof"--but, at least that "proof" didn't start off by adding extraneous material to the original equation.)
@gavindeane3670Ай бұрын
There is absolutely nothing wrong with the 2+2 = 4-9/2+9/2 line. The problem is the next line.
@fabiog627Ай бұрын
A function has only one value if you define it in the real domain, in the complex domain functions can have more than one value.
@MonochromeWenchАй бұрын
Square root giving only the positive result would be why we explicitly use ± before the square root in the Quadratic formula. If Square root could give positive or negative the ± would not be needed.
@MDPeetjeАй бұрын
Why does it have to remain a function when inversing it? I understand that this is the convention and i also only consider the positive square root when i see it like this. But in my opinion it would be much simpler to have the convention be considering both solutions and if you should only consider the negative or positive one then put a minus or plus sign above the root. Simply because y² = x isn't an function doesn't mean that there is only 1 solution for x but somehow for y = √x then there is only 1 solution? This choice for the convention has always seen to be an subjective choice to me instead of a logical/objective one.
@franklee663Ай бұрын
The second step is already wrong, if you apply squares and sqrt, you cannot selective choose terms but have to apply to all on one side.
@swoldogeАй бұрын
No outtro music? 🥺
@Rick_MacKenzieАй бұрын
Would have been interesting to demonstrate that computation would be correct if you take the negative root of (4-9/2)^2 instead of the principle square root.
@proboiz_50Ай бұрын
I knew it! My instincts told me at the start of the video that the 3rd line is incorrect
@arnavthescientist1149Ай бұрын
Ok 4-(9/2) is negative hence it can't be squared and then square rooted. 0:47
@PhilipMurphy8Ай бұрын
The smartest people would notice the mistake straight away
@cmilkauАй бұрын
These are really easy to spot if you calculate the intermediate results.
@ShawnF6FHellcatАй бұрын
I love math, but my most hated mathematical phrase is "prove it"...
@YaztromoXАй бұрын
My refutation of this “proof” is that you can’t start a proof with “2 + 2 = 4” and finish with “2 + 2 = 5”. If this “proof” didn’t _have_ a mistake, then at best all that was proven is that “2 + 2” is either non-computable, or that it satisfies every possible value (similar to the solution of “x - x = 0”). But you can’t posit that 2 + 2 = 4 as your starting point, come up with a ‘5’, and then state that it proves that “2 + 2 = 5”, as the result refutes your starting point.
@onradioactivewavesАй бұрын
He used large values of 2, the mistake was not stating that
@YaztromoXАй бұрын
@ - I get this is a joke, but the point is that all this proof proves is that there is a contradiction, and if not for the error it would simply show that the predicate they started with is wrong, and not that 2 + 2 = 5. Even for very large values of 2.
@Cuber_Man1Ай бұрын
You basically took the absolute value of a negative number in the very first step. In others words, your saying that -0.5=0.5
@PowerStar004Ай бұрын
(sqrt (4-(9/2)^2))+(9/2) = 5 The "mistake" is that by squaring and rooting everything EXCEPT the +(9/2) the value is changed.
@pk2712Ай бұрын
When you go from = 4-9/2+ 9/2 to = sqrt((4-9/2)^2) +9/2 , there is an error because the assumption is made that 4-9/2= sqrt((4-9/2)^2) --- this is wrong . 4-9/2 = --1/2 , and sqrt((4-9/2)^2) = absolutevalueof(4-9/2)=1/2 .
@TheSecondB-nn2vtАй бұрын
-1/2≠sqrt((-1/2)^2 )
@williamstraub3844Ай бұрын
A square root always has two roots, plus and minus, unless the number is zero or negative.
@fillforkedАй бұрын
you can just check if it equals 4 and it doesnt. it equals root 4.75, what else is there to it?
@sicknerd2929Ай бұрын
What happened to the outro music? Does anyone know?
@AlejandroMira-r9vАй бұрын
People that enjoy learning math / want to understand the gaps that are often left in school: Do you care about the historical context of why a math concept was created or began to be useful? Or do you care about how you can arrive to those same conclusions by your own means? Or other? Or all of them? I want to hear you :)
@battlesheep2552Ай бұрын
4:45 well it's false because of the proof by contradiction we went over
@tntdude999Ай бұрын
What I would do, is evaluate the value of every expression and the see which step it changes.
@demise0Ай бұрын
Can generally figure it out by doing the math at each step. As soon as the square and square root went up in line 2, I saw a negative (4 - 9/2) = -1/2, suddenly become a positive 1/2 after squaring and (positive root) square rooting. Right there in step 2, the right side jumped from 4 to 5. The rest of the steps were all obfuscation.
@jannegreyАй бұрын
my guess - either division by zero or using square roots in wrong way. But I didn't even look on the problem yet.
@DrHenry1987Ай бұрын
When I hear "convention", I always ask "according to who?". Where is this codified? We have those in chemistry too, and I irritate when asking the same questions, although some are now studying some "conventions" for their appropriateness.
@StevothehumanАй бұрын
A false proof straight from Room 101
@ChristofAbsolutionАй бұрын
Damn. I thought the problem happened when they added 2 + 3 on accident.
@blablablabla4418Ай бұрын
Sqrt((4 - 9/2)^2) is .5 when it should be -0.5. Ez spot.
@MrJavierSC1Ай бұрын
After the second line, which is incorrect since that radical represents the absolute value, you get 1/2 + 9/2 = 5. All the other steps seem unnecessary and likely aim to create confusion. Kind of sad these things get viral.
@applerd209Ай бұрын
Sqrt(x^2)=abs(x)
@treush8471Ай бұрын
In fact when you say that a number is the squareroot of itself always check that it is positive (common mistake)
@bobbyheffley4955Ай бұрын
The mistake is taking the wrong sign of the square root.
@devedrakumarvshah9288Ай бұрын
Sqrt of a number can be + or -. So the last step should have been 9/2 -5 +9/2 = 4
@randomthings1325Ай бұрын
remember peps: "messing with powers like that is sus (sometimes)"
@ThrillzrobloxbedwarsАй бұрын
The only problem is the second line says 2+2=4 then uses that to prove that its 5 which is not logically consistent as 2+2 cant be both 4 and 5 it has to have one answer.