FE Exam Review - Fluid Mechanics - Impulse and Momentum - FE Exam Tutor

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[@evanarbo]

Thanks a lot brother!

[@moritzribic6494]

Brilliant stuff, very helpful. Thanks for the effort!

[@directhubfeexam]

You're welcome! Thanks for watching.

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/fYvQmpSDj9tknZo . .

[@nicobriceno732]

equations in handbook still help. Its the same thing you wrote, but set pressures =0 & W=0, and you can solve for resultant forces in x and y directions

[@nicobriceno732]

f=-(.126)(999.7)(25cos(135)-25)= 5375 in the direction dictated by the handbook(+), which in the problem is negative

[@somethingdifferent1910]

This was a quite helpful video ...Such a pinpoint material for my fluid mechanics I exam ....Best for practice

[@directhubfeexam]

Nice! I am glad to see it help. Keep up the good work!

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/fYvQmpSDj9tknZo ...

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/fYvQmpSDj9tknZo

[@irinaperepelitsa4810]

amazing videos !!!!!

[@directhubfeexam]

Thank you!

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/fYvQmpSDj9tknZo

[@Eng.Hamza-Kuwait]

💛💚👌👌👌❤️❤️

[@slagwolf7]

Post more of all subjects!

[@directhubfeexam]

I try my best sorry.

[@slagwolf7]

@@directhubfeexam wasn't meaning in a rude way these are very helpful videos

[@directhubfeexam]

@@slagwolf7 Thank you so much!

[@danithaman4610]

What page are those tables on? 4:27

[@directhubfeexam]

Hi Dani, just use this link here it will direct you to the page in FE Handbook 10.0.1 ----> www.cee.msstate.edu/wp-content/uploads/fe-handbook-10-0-1.pdf#page=203

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/fYvQmpSDj9tknZo

[@MN-qc9fn]

Why you didn't use the continuity equation to solve it?

[@directhubfeexam]

How would you do that? Genuinely curious