Find all possible values of X | Triangle Inequality Theorem | Important math skills explained

[@blank3580]

Beautifully explained thanks

[@PreMath]

Glad you liked it Thanks for your feedback! Cheers! You are awesome. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@gopalsamykannan2964]

Good question and good solution. Depiction is superb !

[@PreMath]

Excellent! Glad you think so! Thanks for your feedback! Cheers! You are awesome, Kannan. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@rudychan8792]

Case 4: *all side must be positif* b & c are fine, but 'a' > 0 4x - 5 > 0 ➡ x > 5/4 Luckily x > 5/3 is above 5/4. 😉

[@animalfarm7467]

Correct. Glad to see someone is paying attention.

[@uniquetalentinjamaican]

Let me make it clear that I love your teaching love your voice and love your channel ... I am a math teacher who love learning new ways to teach math

[@allanflippin2453]

Another limit is that x > 5/4. If not, side BC would go negative. However, the x > 5/3 limit overrides this.

[@KAvi_YA666]

Thanks for video.Good luck sir!!!!!!!!!!!!!

[@yalchingedikgedik8007]

Thats nice and useful Thanks Sir .

[@theoyanto]

Love this one, logical rather than mathematical, interesting the inequalities give results.. very interesting, never knew this, thanks for filling in the gaps.... In my head 😃👍🏻

[@MrPaulc222]

Nicely done. I workred differently. I assigned values to x and went with trial and error (improvement). I got the

[@PreMath]

No worries! Thanks for your feedback! Cheers! You are awesome. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@zplusacademy5718]

Welcome to you tube world ❤️🙏 sir always milestone presentation ❤️🙏🙏🙏great greetings from India ❤️🙏🙏🙏

[@PreMath]

Many many thanks You are awesome. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@susennath6035]

Nice

[@RexBoggs]

I thought about using Heron's formula, but I don't think it is necessary. If x = 5/3 then the 3 side lengths are 19/3, 14/3 and 5/3. x must be larger than 5/3 and if it is larger then each of the sides is larger and hence the area is larger. So Heron's formula won't give any values of x that further restrict the possible values of x. What do you reckon?

[@rafaelliman8167]

I wanna add that obviously all sides must be of positive value, so x>-3/2, x>-3, x>5/4 must all be fulfilled too. But 5/3 is bigger than all of them, so this is redundant.

[@weiweiwang2527]

Can you tell me what software you are using ? This software works very well to draw any contents when you are talking.

[@matteovolonghi1981]

What about saying that a side of the triangle must be greater than the difference of the other two and lower than the sum of the other two and examinating only one case?

[@alster724]

Very easy Math problem

[@shadmanhasan4205]

Do we use Heron's Formula here?

[@tompeled6193]

What about plugging the values into Heron's formula?

[@fyroboi2053]

Possible but it's gonna be soo complex

[@rambabuprasad2888]

I am first

[@arpittttt]

To

[@PreMath]

Excellent! Thank you! Cheers! You are awesome. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@gabetheminerofficial]

How do you tell which one is a b or c?

[@yashveersingh1858]

Hello sir how can i send you more questions?

[@barbazzo]

By using Heron's formula, it turns out that side b is the height. So this is actually a right triangle, where a^2+b^2=c^2. The solution is then x=(23+2*sqrt(51))/13. I didn't consider x=(23-2*sqrt(51))/13 a solution since it's less than 1. BTW, I thought it a bit strange that side b (x+3) looks longer than side c (2x+3).

[@bienvenidos9360]

Wow that's awesome! I'm not sure how to use Heron's formula to solve for this, I only thought it was only used to find the area of a triangle. But it looks like that is a solution for x for a right triangle. I tried with Pythagorean theorem to find solutions for a right triangle. I found 2 possible solutions but it turns out they didn't work because the value for the hypoteneuse in the equation wasn't the largest value. I wonder why I couldn't get that value with the Pythagorean theorem. It reminds me how sometimes I failed to get an answer with the method I chose that led to nowhere. Edit: I used the wrong equations the first time around, that's why I ended up with the wrong answers. I ended up with 2 solutions for x that worked that would make it a right triangle. See comment below.

[@bienvenidos9360]

Actually I messed up with Pythagorean theorem earlier that's why I didn't get a working solution. I also got x= (23+2sqrt51)/13 using Pythagorean theorem this time with side AB as the hypoteneuse. I also got a second solution for a right triangle with side BC as a hypoteneuse with Pythagorean theorem. x = (29+sqrt764)/11

[@राजनगोंगल]

👍👍👍👍👍👍

[@BigfistJP]

Once you had x>5/3, the x>1 was a non-factor is solving this.

[@PreMath]

Thanks for your feedback! Cheers! You are awesome. Keep it up 👍 Love and prayers from the USA! 😀 Stay blessed 😀

[@adgf1x]

3x+6>4x-5=>x,11 > x>1

[@AdityaKumar-gv4dj]

Or you can write it as x ∈ (5/3,11)

[@NITINCHAUHA62]

Hi sir I try to solve it.. What is your real name.. Sir

[@NITINCHAUHA62]

Could you shout out me please... Sir

[@adgf1x]

Possible values of x are greater than equal 1and less than 11.

[@johnalvero7250]

What if the x =0

[@uniquetalentinjamaican]

Its so sad that I was never exposed to this theorem... I would almost believe that this is not possible

[@bb55555555]

huh?

[@amicoresongs4159]

I didn't understand

[@dgnash]

Please try to stop saying "go ahead and ...".