Find Area of the shaded region | Square on Median | Medium Hard | PRMO RMO INMO NMTC NTSE IBPS

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MathsSmart

MathsSmart

Күн бұрын

Пікірлер: 8
@hmm9803
@hmm9803 4 жыл бұрын
Hi your content is very good but your views are decreased to very low as compared to last year you can follow certain algos to increase them , hashtags and social media links and many much interesting stuff but again I'm repeating your stuff is beautiful no doubt but it has to spread, all the best keep doing, more power to you ❤💥
@ZeeshanAhmad-pb6pr
@ZeeshanAhmad-pb6pr 4 жыл бұрын
Nice mam
@englishedgebys.k.vidyarthi2319
@englishedgebys.k.vidyarthi2319 4 жыл бұрын
maam please have a complete course on inmo
@kaliprasadguru1921
@kaliprasadguru1921 2 жыл бұрын
Mam , BAC is a right angled triangle .with A as 90° . Hence median AM is half of hypotenuse = 10 .Area of Triangle AMC = half of area of Triangle BAC= 1/2 X 1/2 X12X16 = 48 . Why going in for . Heron formula . Regards .
@AshishYadav-gc4ol
@AshishYadav-gc4ol 2 жыл бұрын
Some problems are really good
@AshishYadav-gc4ol
@AshishYadav-gc4ol 2 жыл бұрын
I'm enjoying
@shivamshaw_07
@shivamshaw_07 4 жыл бұрын
Nice video but has low views 😒
@dainiusb1114
@dainiusb1114 2 жыл бұрын
BM=MA=MC=R=10. Draw perpendicular from M to AF, mark H. MH^2=10^2-8^2. tg(MAF)=MH/HA=FM/MA. S=10*10-0.5*10*MF.
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