I needed so much of clarity and this video really helped a lot! Thank you so much for the help😊
@alejrandom65924 жыл бұрын
thanks a lot!!! I had a lot of questions about limits and you have answered all of them!
@KOMATH4 жыл бұрын
Glad it was helpful!
@YAYAMEDIA-su8up6 ай бұрын
Am from Ethiopia even if after u launch this video it goes to tri years still it is working for us 10q
@djijspeakerguy462815 күн бұрын
for the examples with the radical in the numerator, what if I have an integer inside the radical?? example: (sqrt(11+6x^2))/3+8x
@djijspeakerguy462815 күн бұрын
I thought I figured it out on my own but got an incorrect answer. I would've simplified the top to (sqrt((sqrt(11)/x)+6). Since x=infinity, I'm pretty sure (sqrt(11)/x) cancels out to zero. The entire thing then simplified to 6/8 or 3/4, which isn't correct. what did I do wrong?
@djijspeakerguy462815 күн бұрын
I missed a step. Oops! I didn't implement the square root into my final answer. It's actually (sqrt(6)/8), not 6/8.
@nadineahmed12493 жыл бұрын
This video is so so so so so so so helpful and awesome!!! Thank you so much :)
@KOMATH3 жыл бұрын
Glad it helped!
@changchang68063 жыл бұрын
Came here in search of the 3:15 part. Thanks
@KOMATH3 жыл бұрын
Glad it helped!
@millerchow12 жыл бұрын
Awesome video, except I was confused by the last two examples; which was the same limit except for the fact that first x approached positive infinity and then in the second, x approached negative infinity...why did you use intuition on the last example? Why did you not use the conjugate, then add the neg sign to get -1/10. If you used intuition on the last example to get infinity as the answer, why didn't you use intuition on the second to last problem also? Thank you for your excellent video...
@KOMATH2 жыл бұрын
When we compute limits, it is helpful to use intuition before we compute them algebraically. The second to the last problem is indeterminate so we need to do more stuff like rationalizing (multiplying by the conjugate) to determine the limit. The last problem is not indeterminate as the limit is in the form infinity minus negative infinity which clearly goes to infinity. To clearly see that the radicand goes to infinity, you may write it as x^2(25+1/x). I hope that helps!=)
@marioivanovivanov42482 жыл бұрын
just a quick question..for the last limit can't i just take out 1/x to solve the limit? How can i be sure that i'm using the right technique to solve the limit. Is there a way to figure it out or it's just a matter of exercise before you learn?
@naomiwilliams1313 жыл бұрын
You teach it just like my professor
@douaamoussaid94623 жыл бұрын
hey , thank u and can we know if we solved a limit the right way because we'll use them on derivates and during my exams i get anxious by not beeing sure if it's right ?
@KOMATH3 жыл бұрын
Yes, finding limit the right way is important to find derivatives using the limit definition. However, the examples in the video are limits at infinity so you won't encounter such limits when finding derivatives. I have a video about finding limits using limit definition, check it out.
@douaamoussaid94623 жыл бұрын
@@KOMATH sure i'll do thank u a looot u r so helpful but i'm not talking about how to solve , but after solving and while revising our paper ;id there a way to make sure that the limit is right ,and thank u one more time
@KOMATH3 жыл бұрын
@@douaamoussaid9462 Glad to help!
@مهديالعراقي-ه5خ3 жыл бұрын
Thank you for your help
@ssyapp3 жыл бұрын
Thank you! Thank you! And thank you! ✨
@melir43363 жыл бұрын
Why don't we put a negative sign on x .on the denominator? Since x is from -infinity
@KOMATH3 жыл бұрын
Which part are you referring to? At what time in the video? When x goes to negative infinity, we know that x=- sqrt of x^2 or sqrt of x^2 = -x.
@melir43363 жыл бұрын
At 3:53 why cant we say over -x to the denominator
@KOMATH3 жыл бұрын
We divide the numerator by x which is equal to negative square root of x^2 so we have to divide the denominator by x as well.
@melir43363 жыл бұрын
@@KOMATH thank you i get it now
@Raphael-bq1fc2 жыл бұрын
@@KOMATH i still don't get it. Please can you go over it again
@ibokimcaesar54274 жыл бұрын
Can I request a video for the basic concepts of Calculus, beginner level stuff and some answers sheet so that we can test our newly gained knowledge. Thank you in advance
@KOMATH4 жыл бұрын
Thanks for the request. I will consider that in my future videos.
@ibokimcaesar54274 жыл бұрын
Thank you, you're videos are really helpful and I'm sharing this with my friends
@KOMATH4 жыл бұрын
@@ibokimcaesar5427 Much appreciated!
@axeldaliramirezgonzalez18302 жыл бұрын
How do I evaluate a limit at infinity when the numerator and denominator have roots and the highest power of x is x?
@KOMATH2 жыл бұрын
I think this video will answer your question: kzbin.info/www/bejne/b4izoJmkZ7-Ne5I. If not, let me know the exact function.
@axeldaliramirezgonzalez18302 жыл бұрын
@@KOMATH Thank you so much for your help! .Here is the function if you're interested (sqrt(x+1)-sqrt(x))/(sqrt(3x+5)-sqrt(3x+1)) .I've been trying to resolve without a softwere but it's really complicated it always give me 0 (when the answer must be sqrt(3)/4 ).
@KOMATH2 жыл бұрын
@@axeldaliramirezgonzalez1830 For your problem, just use the technique for the 3rd problem in this video where you commented but you have to compute the limit of the numerator and denominator separately.
@searacha56043 жыл бұрын
Thank you!!!! Very helpful
@KOMATH3 жыл бұрын
Glad it helped!
@ainnadhrah98512 жыл бұрын
THANK YOU SO MUCH ❤
@Concon-bu4bp3 жыл бұрын
Thank you so much.
@cece83092 жыл бұрын
thank you sir!!!
@somethingthatexists4797 Жыл бұрын
tysm😭😭!!
@itsmemags47783 жыл бұрын
What if the function is at cube root
@KOMATH3 жыл бұрын
If in the fractions, the numerator is cube root instead of square root, then follow the same technique but replacing x by cube root of x^3 for both limits. For the limit of difference, you may watch the following video to get some idea on how to rationalize a cube root: kzbin.info/www/bejne/eJywf4SpapWUotU
@ajlei3 жыл бұрын
why is it over x squared?
@KOMATH3 жыл бұрын
Can you give the time in the video? Probably you are referring to the over x that became over x squared when we put it inside the radical. This is because x= square root of x^2 when x goes to infinity (as x>0).