Finite Element Analysis on TRUSS Elements | FEM problem on trusses| Truss Problems in FEM

Very Important problem. New method to solve truss problems.
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One Dimensional Bar Elements :
1. • Thermal Load Problems ... ( Forces are applied towards left i.e opposite )
2. • Basic Steps in the Fin... ( Basic Steps in FEA)
3. • Composite bar formulat... ( Two bars parallel with spring attachment)
4. • 1D Finite Element Anal... ( Two bars parallel with spring attachment)
5. • Structural Analysis of... ( Gap between the bar and wall problem)
6. • Structural Analysis of... ( Gap between the bar and wall problem)
7. • FEM Thermal Analysis |... ( Step bar both ends fixed )
8. • FEM Bar Elements Probl... ( Tapered bar)
9. • Finite Element Analysi... ( Uniform bar with gap between bar and wall)
10. • Finite Element Methods... ( Very Important problem on bar)
11. • FEM Bar Problems |Fini... ( One End is fixed )
12. • FEM bar problem | FEA ... ( One end is fixed load applied at the another end)
Truss Elements Problems
1. • Connectivity table for... ( Three elements, connectivity table)
2. • Boundary conditions in... ( Boundary conditions )
3. • Trusses Method for Beg... ( two elements, one roller support & one hinged support )
4. • Analysis of Trusses Us... ( Two elements both end are fixed )
5. • Analysis of TRUSSES Wi... ( Three elements)
6. • Finite Element Analysi... ( Three elements, two hinged and one roller support)
7. • FEM truss problems | F... ( Two elements, One roller support )
8. • FEM Truss Problems| Fi... ( one hinged support and one roller support)
9. • FEM TRUSS PROBLEM | Ca... ( Four elements , two loads at different nodes)
Constant Strain Triangle ( CST Elements ):
1. • Isoparametric triangul...
2. • Problem 3_CST problem ...
3. • Problem 2 _ CST Elemen...
4. • Stiffness matrix for t... ( Stiffness matrix calculation )
5. • Problem 1_ CST Element...
6. • Constant Strain Triang...
7. • Two Dimensional CST El...
8. • Strain Displacement Re... ( Strain- displacement derivation )
9. • Constant Strain Triang...
Beam Element Problems:
1. • Reaction forces on a b... ( More details about Reaction forces calculation)
2. • Nodal forces and Bendi... ( SF and BM formula for different loading conditions)
3. • Find the Deflection an... ( Beam with Spring support)
4. • Analysis of Beams in F... ( UDL load entire the span of beam)
5. • Beam Problem in Finite... ( Concentrated loads )
6. • Structural Analysis fo... ( Cantilever beam )
7. • FEM beam problems | Fi... ( Cantilever beam with roller support at end, point load)
8. • Beam problem in Finite... ( Continuous cantilever beam with two supporters)
Your Suggestion
Please feel free to Contact
Email: [e-mail]

[@satyasrikar4677]

Mr Gadwantikar, your explanations have really helped me a lot. In fact, a mountainous amount of guidance I would say. You have explained way more clearer than my lecturers and finding a channel that would have all the videos of finite element method readily is a big rarity. Keep going ahead with more good stuff. Thank you very much.

[@MaheshGadwantikar]

Thank You So Much 🙏 Srikar

[@naveenkumarnani5725]

Sir I'm so happy because of you I learn fem easily... I subscribed your channel along with my 20+ friends

[@MaheshGadwantikar]

Thank you so much nani

[@naveenkumarnani5725]

@@MaheshGadwantikar it's my pleasure sir..

[@MaheshGadwantikar]

Thanks for your kind words and it's inspiring me lot

[@aqmalariif2722]

Keep it up, your explaination really make me understand this subject easily

[@MaheshGadwantikar]

Thank you for your support ariif bro

[@amiduallie6225]

You're genius at your work bro. You make things much easier. Thanks a lot for your help.

[@a38preethishn56]

your explanations has really super in the way of teaching is god keep rocking sir

[@MaheshGadwantikar]

Thank you sister 🙏

[@chandrahasdeepak438]

Sir verygood explaination and with Goodhand Writing ❤️! Thank you sir

[@MaheshGadwantikar]

Thank You

[@basim17609]

Sir , we have skewed support so v3 is not zero, so we need to use stiffness matrix K* =T K T transpose

[@difnadir2361]

Yes V3 is not 0,but V'3 =0

[@user-qc6oc2no5d]

you save my fem grade thank you so much sir!

[@syedinayatshah7700]

Thankyou sir 🙏.Tomorrow is my paper and I learned from you alot

[@MaheshGadwantikar]

Thank you bhai

[@MaheshGadwantikar]

& all the best

[@a38preethishn56]

your teaching is Nice sir Thank you very much

[@MaheshGadwantikar]

My pleasure 😊

[@mertovski8793]

maaannn this is gooood. i'll take an exam tomorrow. best regards from turkeyyyy

[@a38preethishn56]

truss proble is simple to understand in the teaching sir

[@MaheshGadwantikar]

🙏

[@gurkiratsingh-fn1fo]

sir in the element 3 support is inclined so i think we need to transform the displacement components from local to global axis.coz the stiffness matrix written in ur solution is for global axis

[@rhishikeshjadhav1772]

I'm also concerned about the same problem...... In the book by Daryl L. Logan, the solution is given (most probably correct one)

[@prof.dr.sadiqs.muhsunal_ji6353]

Dir sir. The form of stiffness matrix already deals with global coordinates x @ y . So u3 and v3 must be considered in x and y and not as indicate by the mister . Therefore u3 and v3 have a displacements tword x and y . I.e, v3 not zero. Thanks

[@ammydeep6354]

Thanks sir I got seventy% marks with the help of your vedio

[@MaheshGadwantikar]

My pleasure 🙏

[@akshitdhiman7494]

Exact video i was looking for...thanku so much sir😍

[@MaheshGadwantikar]

Thank You

[@mohammedabdullah7134]

This is wrong answer sir check book " A first course in the finite element method" Daryl L. LOGAN

[@just2minutesevery]

absoluelty you are right

[@zainabjawad122]

Right

[@haha-uu9ws]

Definitely

[@a38preethishn56]

super teaching

[@MaheshGadwantikar]

Thank you

[@vadicherlapraveen]

the angle was you taken 45 but sin & cos 45 value is 0.707..... so i think it must be a angle of 30 degree 0.5 value is satisfied ... nice information from you sir

[@manikantareddy7425]

In matrix we have square values i.e, (1/root2)^2 =2 so that all values are 0.5 hope it's clear Comment if any further clarification needed

[@hyderabadifoodblogger4912]

Awesome video it help me alot thank u so much and explanation is very nice

[@MaheshGadwantikar]

Thank you so much...!!

[@praveenjain5280]

Thank you so much sir The exact video which I was lookin for

[@MaheshGadwantikar]

Ty

[@rajkumargadasana2768]

For finding k3 matrix 4th row 2nd column was -0.5 and also in global stiffness matrix also 1St row 6th column was -0.5 ....please check sir...thankyou sir

[@MaheshGadwantikar]

Okay

[@rajkumargadasana2768]

@@MaheshGadwantikar tq sir for replying me

[@stevendna8956]

Thanks sir. Very well explained. 🙏🙏🔥👌

[@MaheshGadwantikar]

Thanks a lot

[@prof.dr.sadiqs.muhsunal_ji6353]

Dir sir. The form of stiffness matrix already deals with global coordinates x @ y . So u3 and v3 must be considered in x and y and not as indicate by the mister . Therefore u3 and v3 have a displacements tword x and y . I.e, v3 not zero. Thanks

[@anwarseid6656]

Thank you so much for this knowledgeable video

[@MaheshGadwantikar]

Thanks

[@manuelantonio2990]

Great video, it helped me a million! Keep up the good work brother.

[@MaheshGadwantikar]

Thank You Brother 🎉

[@madhukarelagandula8780]

Sir in the element-3, l = cos45° that means, l =1/√2 ( which is the value of 'l' in the matrix ) but why you are substituting this value in the place of 'L' (which is the length of the 3rd element right 🤔) Reply me sir, i have an exam tomorrow

[@madhukarelagandula8780]

'L' value is different and 'l' is different. But you substituting the 'l' value in the place of 'L' value !

[@MaheshGadwantikar]

In this Problem , I don't think any 'I' there in the equation. Only we have the length of the element = L, Note : There is no difference in 'I' and L, both are same value.

[@MaheshGadwantikar]

Dear Madhukar , We have only length in the equation ( l or L).

[@MaheshGadwantikar]

I Understood your doubts, For Element 2, the length is 1m.

[@madhukarelagandula8780]

If there is no difference between 'l' and 'L' , why don't you replace the 'L' value (as zero) with the value of 'l' in the element-1 ? ( Check the difference sir, L=1 and l=0 in the element 1)

[@jidapa2969]

Thank you so much Mr.Mahesh

[@MaheshGadwantikar]

❤️🙏

[@amiduallie6225]

You're really great sir

[@MaheshGadwantikar]

Thank You So Much

[@fqkhan245]

Here you took v3 as zero its not correct .check again you have to use the global coordinates so in end u2,u3,v3 are to be found out and we would have 3x3 matrix in end 🤔🤔

[@MaheshGadwantikar]

🤔

[@fqkhan245]

@@MaheshGadwantikar after checking reply me with correct answer 🙏 waiting for your response

[@ersinyildiz]

I agree. Did he give the correct answer?

[@wocko25]

Thank you so much for this!

[@a38preethishn56]

NICE sir

[@MaheshGadwantikar]

Thank you 🙏

[@indianhits148]

thank u soo much sirr... it helped a lott for my examss

[@MaheshGadwantikar]

My pleasure

[@ignatiusikemefuna2440]

Thank you. Can you help me to analyze a continuous isotropic plate using finite element method in Matlab

[@MaheshGadwantikar]

No I am not good in matlab

[@krishnakumarbidari4862]

for skew support truss [f]=[T][K][T]^t {u} isnt it?? i found this procedure and different answer than yours for same question with same data what shall i follow?

[@MaheshGadwantikar]

Which is easy method? Easy to understand u can follow that procedure..

[@krishnakumarbidari4862]

I got different answer

[@MaheshGadwantikar]

Then you follow my procedure, its actual answer obtained..for more problem plz do Support us

[@CKSEditz]

Nice explained thankyou so much ❤️

[@MaheshGadwantikar]

Thank you so much ❤️

[@CKSEditz]

@@MaheshGadwantikar bahut muskil lg rha tha KZbin me video ni mil rha tha fir apka video dekh k sb ashan lg rha h sir ❤️🙏

[@MaheshGadwantikar]

Acha laga, Mera mehnat safal huwa

[@akaykaushik7255]

Bery very nice explanation sir

[@MaheshGadwantikar]

Thank You

[@lovepreetsingh4566]

This wrong, coordinate of support 3 are rotated by 45 degree we have to consider that also

[@MJs-85]

16:27 it is U1U1 i think not u1v1 ... i hope you would agree .. the first element in global matrix which was 0.5 according to u

[@sujalsapkota6875]

But support at node 3 is inclined so this method is not correct.

[@user-ve6jz7sw4f]

A great video but your way of handling support 3 is wrong.

[@kiranbhaskar5527]

Tq sir very neat explanation

[@dipakchaudhary4470]

[T][k][T]^T Is not applied when inclined roller support is not provided

[@satyasangoju4142]

in other truss video you told 1Gpa=10^3 n/mm2.....but in this u said it as 10^3......plz correct it......what is the correct answer

[@MaheshGadwantikar]

Where 1MPa=N/mm2 ok, and 1GPa =10^3 MPa= 10^3N/mm2

[@teganthomas2235]

How is F3X=0?

[@rajatgajbhiye7244]

Sir if any numerical numbering of node is not given then how to give the numbering of node.

[@MaheshGadwantikar]

Yes ,It's available.. Please check in my playlist

[@kadavathvenkatesh820]

Remember please when you teach a subject mention a subject name and which year you teach clearly mention in before starting video

[@ikchimedza6819]

Very good video!!

[@MaheshGadwantikar]

Thank You 👍

[@semihtuncer12]

Thank you so much .

[@MaheshGadwantikar]

❤️❤️

[@ersinyildiz]

How come does V3 equal to 0 at 22:52 ? That roller at node3 makes an angle of 45 degree with global coordinate system. You just edit global K matrix with respect to local coordinate system at node 3. I believe this is a mistake, if not please explain this.

[@voiceOver5000]

I also think that there is a mistake, because of the orientation of the force, the beam must elongate to the right-hand side. please correct us.

[@MaheshGadwantikar]

By tomorrow i will post the pdf of the given problem in the description. Please wait

[@ersinyildiz]

Before any boundary condition implementation, transformation should be made at the roller support with an angle. By doing this, corresponding component of the K matrix are transformed to local coordinate system with respect to corresponding element. After that boundary conditions will implemented. Solving the system will result transformed results for that node. Retransformation should be done to obtain results in global coordinate system. Tomorrow I will share a book which describes this procedure.

[@ersinyildiz]

Check Example 3.11 on page 106 of the book of Daryl L. Logan named "A First Course in the Finite Element Method" 4th edition.

[@ichisan3775]

@@ersinyildiz it is a good recomment. I have a question that the symbol l in T transformation is length of element or just 1. Thank you.

[@dessalegntassaw2796]

Thank you !

[@alistairtaruc4918]

amazing sir thank u

[@MaheshGadwantikar]

Most welcome

[@mvasavi777]

Sir also expalin 4 element problem

[@satishvarmavaidadi9792]

Good explaining good

[@MaheshGadwantikar]

Thanks you so much Varma

[@ThexGhostxGamer]

Thanks

[@chefnabil5351]

you are Best tanks

[@3DPRINTechnology]

How you calculated the area? Area means cross-section area of another area?

[@MaheshGadwantikar]

The area of cross section of each Element.. Generally a bar Elements will be considered in truss problem..

[@3DPRINTechnology]

If you are online, please answer it. also, the distance calculation needs to be elaborated in detail. Thank you

[@MaheshGadwantikar]

From the geometry of the fig, we have find out the length.

[@3DPRINTechnology]

@@MaheshGadwantikar how to calculate the area if dia of bar is not given? You explained triangular truss structure nicely in this video, do you have or can you please prepare one video explaining square truss in which the lower horizontal beam is fixed and upper horizontal beam has UDL? If you already have any relevant video, please share the link.

[@MaheshGadwantikar]

If Dia is not given, then would have given Area value directly.

[@bakhtawarmallah1177]

good job sir..

[@MaheshGadwantikar]

Thank You 🙏

[@manibitra0099]

Good explain

[@MaheshGadwantikar]

Thanks

[@zainabjawad122]

Sir in this question, the support is inclined so, this solve is wrong

[@yogeshwarnishad2164]

Nice sir ji

[@MaheshGadwantikar]

Thank you so much Nishad

[@evangelosgeorgiou1662]

Sir i did not understand, why do you put l and lm inside of the stiffness matrix at 4:07, where did l and lm come from?

[@MaheshGadwantikar]

L is nothing but cos tita and m is sine tita

[@evangelosgeorgiou1662]

@@MaheshGadwantikar Thank you very much, but whats the difference between L=1m for element 1, and l that we put inside the stiffness matrix?

[@MaheshGadwantikar]

Yes

[@Saikiran-qb2yo]

how to do elimination, u have used some elimination methods so could u plz brief it

[@pratik8197]

Thank you

[@niharikamudavath8678]

Sir while calculating global stiffness matrix if 0.5 in one matrix and 1 in other matrix then we should add it get k ?

[@MaheshGadwantikar]

Yes, you should add it if both are lies in the same displacements.. For more details watch a video on global Stiffness matrix method.

[@powerisinsoul7061]

Sir how to find reaction...Please Help me ASAP as i have the paper

[@brucekabali3175]

you did not consider the fact that node 3 has an inclined support.

[@awazhamza7437]

hello .sorry sir how can i find next video to solve reaction forces? the video stated that you will find reactions of forces in the next video following this video

[@angieladagook7490]

Hi, i've been solving a problem using this method but i'm not quite sure if it's right. Anyway, about the area how did it arrive to different areas, is it because of the angle or is it just given? hope you can answer thanks

[@MaheshGadwantikar]

Please Wait 1 day, I will upload another video on same problem by considering the Inclined support

[@angieladagook7490]

@@MaheshGadwantikar by any chance do u have email i could send a problem and help thanks

[@MaheshGadwantikar]

m a h e s h m g 5 3 3 at g m a i l . c o m

[@angieladagook7490]

already sent an email

[@mvasavi777]

Sir in element 3 it is inclined then is any need to convert local to global cordinates..

[@pitabashabaral3401]

Sir this is wrong because one support is inclined..so we need to use another transformation matrix for that support..

[@nileshkarwar5143]

Calculation for second member is wrong , we need to consider inclined support angle also

[@MaheshGadwantikar]

It's considered in the Problem.. Check Once

[@nileshkarwar5143]

It consider for member 3 what about member 2

[@a38preethishn56]

New method to solving the problem HOW?

[@deepakkumaar2637]

Hey, Mahesh Can you tell me in which book have this example?

[@MaheshGadwantikar]

MD.Jalaluddin

[@deepakkumaar2637]

Sir, Do you have softcopy of this book? If yes please share with me. OR Any online source of it.

[@syedshadabquadri7641]

Good work

[@MaheshGadwantikar]

Thanks sir

[@2424ahmed]

❤❤❤

[@MaheshGadwantikar]

❤️❤️❤️

[@sriguruskandha9920]

Stiffness matrix for 3d pin jointed truss ?

[@gillianashleylazaro8650]

sir can i get the link of the second video? continuation of this one. i cant find it, thank you somuch

[@rajendrabutalekar7805]

E=210×10^3

[@MaheshGadwantikar]

Yes

[@DC-gb4nh]

There is no external force acting on F3x so you took it 0?

[@MaheshGadwantikar]

No force, so it will be 0

[@enga-qs6co]

11:45 one by root 2 is nothing but root 2?????

[@leoakari2335]

hay quá thầy ơi

[@rohanpatil7860]

sir, how did you take (L = 1/ √ 2) & M =(1/ √ 2) for element(3) because, cos45 = ( √ 2/2) and sin45 = ( √ 2/2).

[@raphaelomungi8682]

if you understand surds, (1/√2) =(√2/2)

[@marojahansamosir4342]

why not transform the matrix?

[@naseradeenashwear708]

Are You sure about the application of B. C. at node 3

[@MaheshGadwantikar]

Yes.

[@naseradeenashwear708]

@@MaheshGadwantikar But you put v3=0 and v3 in global is not zero because the support is inclined

[@naseradeenashwear708]

@@MaheshGadwantikar Hi I am still waiting for your answer Sir.

[@naseradeenashwear708]

Are you sure about the application of the boundary conditions. I saw you put v3 =0 but in global axis it is not zero as the support at node 3 is inclined. In other words node 3 is deformed in both global directions the horizontal and vertical.

[@aaryad9043]

i also think he took wrong direction for U3 and V3 they should be in direction as x and y so V3 can't be zero

[@arkham-8015]

How’s is 1/root 2 equal to root 2

[@HappyKumar-uy3qj]

Sir how to find bandwidth of truss

[@seenumehta9952]

Sir how 1 by √2 is √2 in element 3

[@didarulhasansaharaj4396]

The node 3 has skewed support. The displacements in node 3 have to be transformed to global axis. Your solution is wrong.

[@RAYUDU_ROCKY_45_999]

-1² = -1 x -1 = +1

[@jibranjameel3182]

great

[@devendrabisen6631]

Thrita 2 ki value 0 kaise aayi

[@shahvaizkhan4131]

Is there any matlab code for solving this sort of problems?

[@MaheshGadwantikar]

No idea about Matlab coding

[@monkeyface802]

Why as engineers do we over complicate things. The idea of engineering is to make things easier not more difficult!! This is ridiculous!

[@nmaheshkumar6746]

Sir upload full fea notes as per osmania university for be students I request you sir

[@MaheshGadwantikar]

OK Mahesh Kumar

[@ShresthChandan]

Sorry but the shown solution is wrong third roller is rotated

[@basharm.m2372]

Can i contact u bro i need your help

[@MaheshGadwantikar]

Sure You can

[@basharm.m2372]

@@MaheshGadwantikar do u have Number whats up

[@MaheshGadwantikar]

Visit Channel Description

[@HimanshuPothareFilms]

the value of cos 45 is worng...The value of cos(45) is √2/2

[@ashishmistry6102]

1/√2 & √2/2 both are the same🙏

[@alemayehugirma7315]

Hi my best how are you ? that is best example, best to do more and can you give your email address.? I sent to more assignment to help me

[@MaheshGadwantikar]

m a h e s h m g 5 3 3 @ g m a i l . c o m

[@maheshsonawane4754]

👍

[@fuzzpi4607]

Wrong answer