Fire alarm design - Battery Calculation

[@ammaraloush6313]

Very good

[@ammaraloush6313]

I liked it and share

[@WMirza79]

Ohhhhhhhhhhhhhh awesome brother Great explanation in detail. Thank you so much for posting such an informative video.

[@AllaboutFireProtection]

Thank you.

[@baijuvarghese7472]

Professor Eugin Boss Best class you offer ,Thank you ........

[@AllaboutFireProtection]

Hi Mr. Baiju, thank you for watching and it's nice to see you here.😀

[@phitune6614]

thank you so much Sir,,, new follower here ---i am elated to this video tutorial i started in 3 parts introduction about the safety codes hoping more tutorial about fire alarm sytem...

[@AllaboutFireProtection]

Thank you for your support. I will upload soon.

[@mohamedsalama607]

Good job

[@justinpoblete4481]

Satamat po, thank you for this video!

[@AllaboutFireProtection]

You're welcome po. Thank you for your appreciation sir.

[@DavidMoore-od9kv]

Keep it up!!! Love the videos!

[@AllaboutFireProtection]

Thank you.

[@nelsoncapalad3387]

Thanks bro for tutorial 🙏

[@AllaboutFireProtection]

Salamat bro. Good luck to you.

[@vicentebuenconsejo5056]

hi, sir eugene. i appreciate your videos. been watching it and it really helps.

[@AllaboutFireProtection]

Hi Sir. You're welcome. Likewise thanks for your appreciation. I'll be uploading more videos regarding FDAS.

[@lc1288]

simple and direct.. thanks for this

[@AllaboutFireProtection]

Glad you liked it

[@marcogalindo3275]

Do you have a video explaining calculation of power needed and devices, for example I am using beam detectores with a Potter AFC-100 Panel, so I need to know if I need Power Boosters and how many. Thank you.

[@nisuquayum7817]

how did you get the value of 1.2 to multiple

[@bart901]

Sir panong mo nakuha yung .833 diba dapat .0833? Thank you

[@AllaboutFireProtection]

0.0833 yan sir, typo error sya. thank you for watching.

[@bart901]

@@AllaboutFireProtection thank you sir nakita ko nga sa comment...salaamat

[@bart901]

Nagkataon na tinanong ako ng amo kung sino daw may alam mag compute ng battery hehe...tamang nakita ko yung tutorial mo very helpful salamat ulet

[@AllaboutFireProtection]

@@bart901 yes sir basta may clarification ka, message ka lng dito. Salamat sir sa pagbisita mo sa channel.

[@digitaldaemon74]

Hey nice tutorial, you've taken on a lot. Question that bothers me. If I have an auxiliary output on panel, how do we account for the current of the wiring's voltage drop? It is not accounted for in the voltage drop. The out put of the relay is given is the internal mA for that driver on battery calcs. But what about the calculation of the current consumed by a wire on a long run, it is not insignificant. For example I am driving a hornstrobe off of a control module. Say with 14GaFPLR which is about 3 Ohms/1000 feet. So for simplicity sake I am driving a an outdoor horn-strobe 1000ft away. Then my 24V source and 3 OHM voltage drop give so assuming we de-rate20% to 20.4V like a Nac using OHMS law we have 6.8 Amps of current draw. This is ignoring our device. That 6.8 amps is not accounted for in a battery calculation anywhere. So when we size a battery, will it run on battery backup for the designed time? I wonder if they do. According to ohms law probably not. Unless I'm missing something, most fire alarm calculations out there do not account for this I think. Am I wrong? I'm not sure where manufacturers come up with these 6,000ft numbers everyone runs with. Thanks in advanced. JT

[@AllaboutFireProtection]

Hi John, first I also like to thank you for your time watching one of my videos, and please continue doing that so that I could share more once I find time to do another video. Please note that I value all of the questions here as this is a way we share our ideas and experiences. In your question, I assume we are talking about having an addressable fire alarm system where our notification appliance devices are powered from the 24Vdc auxiliary output from FACP and controlling it using a control module. Let's say the derated voltage of Aux output is 20.4Vdc and your overall wiring resistance is 3 ohms, we are not calculating them by the direct formula of ohms law which gives us 6.8A as an additional load to note. Instead, it is always part of the procedure in calculating our voltage drop to know the load first of whichever output terminal we account for. In our case here, the load connected to our aux output is an external horn strobe. If its rated current is let's say 320mA and only one of it is connected, then that 320mA will be our flowing current to the 14GaFPLR cable that has a total resistance of 3 ohms instead of 6.8A. The same 320mA will then need to be added to our batter calc as an additional load. And to know the voltage drop from your cable, .320Ax3ohms will give us 0.96V which means, only 20.4V - 0.96V= 19.44Vdc is delivered to the external horn strobe which is still acceptable as most UL notification appliance has an operating voltage range from 16-33Vdc. Hope this helps. Thank you again, John.

[@digitaldaemon74]

@@AllaboutFireProtection so how can we you ignore the effects of the wire at such long distances. So if I have a 20v battery attach 1000ft of wire it pulls no current? The FA manufactured give us a max distance calculations are convoluted. My concern is that this current never gets added to the battery calcs. I always upgrade my batter calcs a size above calcs.

[@ivancruda9445]

Sir, kmusta po. Tanong ko sana. Sa battery calculation, ibig po ba sabihin ng alarm current 5mins, is testing ng FDAS system for 24hrs Standby and additional 5mins na activated/alarm state.

[@AllaboutFireProtection]

Yes sir, 24hrs na patay ang ac power plus 5 mins na nasa alarm state ang system dapat kaya ng battery

[@ivancruda9445]

@@AllaboutFireProtection may gumawa po kasi na 24hrs standby and alarm state 24hrs dn, possible po ba un? battery rating niya is 40AH, calculated is 39.6AH. May battery ba na ganun?

[@AllaboutFireProtection]

@@ivancruda9445 hi sir ivan, minimum lang nmn yung sa nfpa if required cya s project specs pede nmn gwin din basta make sure capable yumg charger ng power supply support yung capacity ng battery mo.

[@ivancruda9445]

@@AllaboutFireProtection Salamat po talaga malinaw na sakin. 😁

[@deanepepito]

Sir, how did you get 0.833? If you mean 5 minutes of an hour is equal to 0.0833

[@AllaboutFireProtection]

Its 0.0833, its a typo error like i replied from other comments.

[@AllaboutFireProtection]

Thanks for watching and please don't hesitate to ask if there is any.

[@AwesomeAngryBiker]

Great video but man that intro, 6 secs was more than enough.i almost left because I thought it was just a music video

[@AllaboutFireProtection]

Thank you for watching. I'll consider that for our future videos

[@vintagesimplexfirealarmsof6440]

I collect old simplex fire alarms from 90s and 80s

[@AllaboutFireProtection]

Nice to know that. Welcome to our channel.

[@marieneneilputoandcheese6822]

Nice very informative po!!! Mariene Travels - Vaklang Chizmosa

[@AllaboutFireProtection]

Glad it was helpful!

[@andrewjck1]

Can you help me? Shouldn’t 5 minutes= 0.0833? I’m no mathematician who’s is why I’m watching this so just straight forward explanations please

[@AllaboutFireProtection]

Hi Andrew, that one is a typo error from me. It should be .0833. Thanks for watching.