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@alexeykrylov9995 Жыл бұрын
6:58 dimension mismatch in the second equation: the right-hand side is dimensionless, while the left-hand side in 1/[x]. So, it can't be right.
@AnsysLearning Жыл бұрын
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@disruptivegarage3 жыл бұрын
thx for the clear explanation
@AnsysLearning Жыл бұрын
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@disruptivegarage Жыл бұрын
@@AnsysLearning you dont say. This happens to be what i need
@nikkhil96 Жыл бұрын
It's still not very clear how the pressure gradient along a horizontal flat would be negative? Could you kindly elaborate? Thank You.
@AnsysLearning Жыл бұрын
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@manthanparekh8703 Жыл бұрын
Consider a Fully-Developed laminar flow over a flat plate, hence constant velocity and no acceleration. For such a case, the only force which is opposing the flow is the force (resistance) due to shear (viscous) stress on the plate surface. Now, as the mass (flow rate) needs to be conserved, the flow needs to overcome this opposing force . It overcomes this force by a corresponding decrease in pressure along the direction of the flow. This pressure difference results in a force opposing the viscous force. So to sum up, a force is required to push the fluid against the viscous force (also known as flow work/flow energy), which is provided by this pressure difference. Pressure gradient would be -ve as well as constant for this case. If the flow was additionally inviscid, then there would be no viscous force, hence no pressure gradient. Hope it helps.
@him31anshu3 жыл бұрын
Nice. Good
@AnsysLearning Жыл бұрын
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