I am utterly amazed watching these videos...i am a 50 year old guy who was never good in math and science but have an overabundance of curiosity about how things work. I feel lucky to live in a time where i can look anything up on youtube and get some undestanding about how the physical world works around me. Also, i had no idea how involved pumps were...meaning the engineering behind the pump.
@CPPMechEngTutorials6 жыл бұрын
We feel lucky to live in a time where it is possible to leverage our efforts to help others well-beyond the classroom.
@craigbain16455 жыл бұрын
@@CPPMechEngTutorials thank you for your posts. I feel lost sometimes watching these things but rely on osmosis. Knowledge helps us all thanks
@celospiky3296 ай бұрын
I have been working for more than 10 years as rotating engineer in water treatment plant and offshore oil n gas industry where the pump require either ANSI or API 610 type. But for me, this uncle has produced one of the best explanation in youtube and easy to be understood by our normal people in the world
@alouisiusprabowo32504 жыл бұрын
Am over 2 years in pump industry as engineer. Splendid, crystal clear sir. Thank you.
@jerrysmith97802 жыл бұрын
Feel like this prof is more like a coach, you don't wanna let him down. I bet students work their tail off for him because he's engaged in the learning process.
@CPPMechEngTutorials2 жыл бұрын
Never let Prof. Biddle down... NEVER!
@primesonypaul7230 Жыл бұрын
47:42, when Q=0, Hs=150. But how at increased flow rate Q=500, Hs is also increasing to 150.5? Because according to the curve at increased flow rate head decreases. Isn't it?
@wonkisbonita3 жыл бұрын
If you try and do the math on minute 44:48, on the replacement of V, Q=AV, so you should have V=Q/A. Thus, V=4Q/(pi*D^2). V=4Q/pi with D=1.
@CPPMechEngTutorials2 жыл бұрын
Yup. We put that message in the comments.
@rioloroane Жыл бұрын
should i square it like the v?
@myokokoaung9857 Жыл бұрын
It is crazy how I can watch those lessons for free. Thank you very much.
@CPPMechEngTutorials Жыл бұрын
The world is a crazy place. :)
@denwilden27485 жыл бұрын
Great lecture, remembering when I was in university. Now I work in small business servicing pump, and this lecture is realy helpfull. Thanks Prof
@CPPMechEngTutorials5 жыл бұрын
We're glad it was helpful.
@eeoui03345 жыл бұрын
Excellent lecture, Dr. Biddle. My professor doesn't even try to explain and solve these problems. Thank you very much.
@CPPMechEngTutorials5 жыл бұрын
Thanks!
@TenkiKun245 жыл бұрын
I left my class for this topic,but luckily i found this video,it's about 2 days bfr exam,,i watched it,,excellent lecture,,hope my final exam become good
@pbpracticobienhecho34804 жыл бұрын
Muchas gracias. Excelente explicación. I am an electrical engineer and these concepts are very useful for me. Thank you very much.
@shibanishashin59933 жыл бұрын
This is a beautiful culmination of my pumps course. the clarity of it brings tears to my eyes.
@GenaEnSamIAm5 жыл бұрын
All I can say is brilliant and thank you. Thank you for sharing!!
@CPPMechEngTutorials5 жыл бұрын
Our pleasure.
@GerardoSanchezZz6 жыл бұрын
Thanks for including time stamps in these videos!
@CPPMechEngTutorials6 жыл бұрын
No problem. We are starting to add time stamps to the lecture series to make it easier for viewers to find exactly what they need. Hopefully the timestamps will save people a lot of time and frustration.
@jeezwheez47409 ай бұрын
I haven't enjoyed a lecture as i have enjoyed this one!👏🏾👏🏾
@AY-cj9kp3 жыл бұрын
What a great teacher! I am electrical engineer but just enjoy listening and understanding...
@fa90lq5 жыл бұрын
Thanks for your effort. One tip though, unlike the case in the pump sketch you showed, for centrifugal pumps and compressors, the suction side is always one standard size larger than the discharge size. This is to minimize losses and, consequently, reduce cavitation possibilities.
@CPPMechEngTutorials5 жыл бұрын
Thanks for the tip.
@ericzenteno2531 Жыл бұрын
This professor is a legend, I wish I had him as teacher at University 😮
@CPPMechEngTutorials Жыл бұрын
There can be only one Professor Biddle.
@syedemaadrizwan62594 жыл бұрын
LEGEND Dr. Biddle
@ebrahimamiritokaldany91799 ай бұрын
The equation provided to calculate delta z based on NPSH is for the case that the water level at the supply reservoir is below the water level at the demand reservoir. So, for the case which is shown in the video, the water level at the downstream reservoir should be lower than that the water level at point 1 and for this case: delta z (minimum water level difference between two reservoirs)= (Pa-Pv)/gamma - NPSH (for available pump) -HL (all head losses) as shown in the video. It is not surprising that if the difference in water levels reduced to values less than delta Z, cavitation is expected to take place. For the other case if the water level at the demand or downstream reservoir is greater than the water level at supply reservoir (most cases), delta Z (Max different in water levels)= NPSH (of the available pump)- (Pa-Pv)/gamma +HL (all head losses) and in this case if the water level at supply reservoir or the well is dropped to lower depth, than the difference in the water levels increased to values more than computed delta Z and we expect cavitation will take place in this situation.
@mjvonstein5 жыл бұрын
Appreciated the clear explanations and real-world practical focus.
@CPPMechEngTutorials5 жыл бұрын
Thanks!
@johnartgallery3473 жыл бұрын
Great Teacher ,nice channel, improve my listening and English on engineering.
@jonathanloorgarcia69612 жыл бұрын
It´s such an amazing class, thank you so much for this video , I got a brief summary about centrifugal pumps which I learned through the university.
@anthonyanderson16295 жыл бұрын
This video is great, a lot of good information presented in a clear manner. Thanks!
@CPPMechEngTutorials5 жыл бұрын
Our pleasure!
@chitramypower43445 жыл бұрын
Thank you for your lacture.. I learnt a lot and but why the H vs Q curve by manufacturer is decreasing while system head curve is increasing..However, I know, at 0 flow, head will be maximum and if flow will increase, head will be go down because pressure will be reduced but please make me clear on what basis or data manufacturer plot H vs Q.
@zoazali74845 жыл бұрын
dear DR. AT 45 MIN there is a little error Q=VA so V=Q/A SO it well be V=Q 4/ π D^2 thanks lot ...
@ibrahimhajjaj81554 жыл бұрын
He assumed D = 1
@wonkisbonita3 жыл бұрын
You're right.
@yashsherathia83492 жыл бұрын
I got an exam tomorrow. My prof sucks. You are great. Thank you
@brettruss33594 жыл бұрын
Hey it would be great if the handout was posted for this video.
@jha85394 жыл бұрын
Excellent lecture
@andresjanz3 жыл бұрын
Great class, what's the professor's name?, he mentions 'his book' and I'd like to check it out....thanks CPPMechEngTutorials guys !
@jhonmoncaleanotorres19755 ай бұрын
Great explanation, thanks, what is the textbook used?
@miriam44284 жыл бұрын
Excellent Lecture. Pretty Understandable
@JacksonMalcolm4 жыл бұрын
this is great info, I'm studying for my next wastewater certification and notice a few differences. Total dynamic head and Head in general is always referd to as the verticle distance the water has to be pumed (measured in feet). But it sounds like head is just any force acting to restrict flow? Also Cavitaion is described only happening at the impeller near the inlet or outlet and not in the pipe itself. this is due to the pressure difference across the impeller. the bubbles are formed by rapid pressure loss and on implotion they take part of the impeller with them and they sound like BBs in the pump. again, great video. i enjoyed getting away from the text book for a bit.
@serrarbrahim5 жыл бұрын
Thanks a lot Dr Biddle for sharing this is a really helpfull !
@CPPMechEngTutorials5 жыл бұрын
Glad it helped!
@parsapirestani14213 жыл бұрын
Thank Prof for the great lectures!
@5afbi3 жыл бұрын
This is very useful for engineering student thank you sir😍👍👍
@mojtabaabdjbarh34362 жыл бұрын
Hi teacher I would like to thank you for your wonderful explanation and I want to know why in the pump efficiency chart, when the height increases, the discharge decreases,please
@hussainshaheed45023 жыл бұрын
Best lecturer. Thanks
@celospiky3294 ай бұрын
Just to confirm that Axial flow Pump is also one of the types of the Centrifugal Pump, for Example of Between Bearing BB1 API 610 Centrifugal Pump
@sandilendlela65312 жыл бұрын
Great lecture indeed but I'm confused where did the professor get 175 and 140ft to generate the pump head curve?
@avika88 Жыл бұрын
Thanks for some great videos! This is probably a shot in the dark, but could anyone help me reference to the book he is using. I’m in the middle of a thesis but I cant seem to find alot of good theoretical references on the subject.
@sagarpuri7838 Жыл бұрын
Thank you very much . Very helpful lecture videos.
@133wavi4 жыл бұрын
Thank you for the great video. I have a question about the effect of temperature on the characteristics curve of the pump. How does the characteris curve of a centrifugal pump change with the decrease in temperature provided that the pump power is constant. A reference material to read would of great help. Thank you
@benmoussayoucef46992 жыл бұрын
I can tell you that increasing tempreture will increase the risque of cavitation; unfortunantlly i don't know really it's effect on HQ curve.
@ajaynavale973911 ай бұрын
Thank you very much sir... really appreciate it 🙏...
@dheyaalgallaf60605 жыл бұрын
How to find his lectures about Turbine & compressor
@isaachaynes69352 жыл бұрын
Would cavitation also occur if boiling coolant (car's cooling system) is flowing through the pump? Pump would be at the lowest point in the system. I'm really curious about this
@lazer24056 жыл бұрын
When you run the pump at a constant speed, how do you increase the flowrate through the pump?
@CPPMechEngTutorials6 жыл бұрын
Open the flow control valve downstream from the pump.
@jeffreystroman28114 жыл бұрын
Raise the fluid temperature to change viscosity, density? (Not practical but I'm an electronic guy working at a farm and my boss keeps trying to make me do things that are not correct. My solution, learn about fluid dynamics on my own, not to be right but to respect energy and knowledge). Thank you professor, much respect for your life's work, reminding me as always I am standing on the shoulders of giants
@MichaelATH4 жыл бұрын
Change the impeller size as per manufacturers impeller data
@abdelfattahkhyralla22033 жыл бұрын
@@CPPMechEngTutorials Awesome
@vijaybhatawdekar62132 жыл бұрын
Actually V=Q/A (Cross sectional area of pipe)
@freedomcompany34284 жыл бұрын
Check me out but at 25:10 the 101kpa makes it 101,0000 Pa which is NPSH is 7.4 METERS then that makes sense with the whole equation to make the units workout. But he wrote that vapor pressure is 1666 kPa and then out it in the equation as that value so there's a mistake on that one way or the other. Either it was incorrectly labeled with the kPa units initially or he should've left the Patm in 101 kPa form and converted later. Can someone confirm?
@dawidpietrucha53333 жыл бұрын
Yeah exactly. Patm is 101 kPa and the Pv at 15C according to the steam tables is equal to 1.7 kPa.
@freedomcompany34283 жыл бұрын
@@dawidpietrucha5333 lol too long ago I can't tell if you're agreeing or disagreeing
@aj_david9 ай бұрын
He's agreeing....
@imky081114 жыл бұрын
Is NPSH used for the single purpose of determining the maximum elevation which the liquid can be raised?
@dawidpietrucha53333 жыл бұрын
No, because NPSH changes with the change of Q. The higher is the flow rate, the higher is the pressure drop at the suction side. Therefore it's rather used to get to know the maximum flow rate available. Also the temperature plays the key role, since it influences the vapor pressure.
@imky081114 жыл бұрын
great tutorial for a EE....At 25.00 regarding NPSH, visually the water tank is below the pump, the Z is the height between the two. How would the analysis change, if the pump was below and the water tank was above? I would think the ABS | Patm -Pv | may be a more general solution to avoid an answer with a -Z value.
@nadonadia2521 Жыл бұрын
What a great teacher, where do you teach, i want to join one of your classes
@CPPMechEngTutorials Жыл бұрын
Sorry. Only Cal Poly Pomona students are supposed to be in the classroom.
@blessingmajongwe20765 жыл бұрын
Excellent explanation
@teslaheavyelectricals59574 жыл бұрын
Very much interesting and informative lecture. Thank you Professor.
@AKK1053 жыл бұрын
How can we calculate the flow rate of a split type centrifugal pump if we know the refrigerant flow rate through the chiller's evaporator?
@gouthamraghavan64672 жыл бұрын
Thank you sir for the explannation, it helped understand the fundamentals better. Also, I would like to add a note on vapor pressure. Vapor pressure of Water @ 15degC unit shall be read in Pa (i.e 1666 Pa)
@shrikantmnit4 жыл бұрын
Great lecture, Thanks Professor.
@PracticeMakePerfectMuslim93 Жыл бұрын
love this subject 😊
@CPPMechEngTutorials Жыл бұрын
We love it too!
@ALNasserSaladin3 жыл бұрын
Hello Sir, Can you drive the specific speed formoula? How we have got the range for every type?
@hydraulictestrig3 жыл бұрын
Beautiful Class Thanks Prof
@shoaibahmed55614 жыл бұрын
my supervisor recommend this video i was in search of topic for research.
@AKK1053 жыл бұрын
Dr. Biddle, Good day to you. Which textbook are you using?
@NithinNayak-dm2ii Жыл бұрын
Which Text book he is referring to?
@siriuselectrical99868 ай бұрын
Which textbook does he use?
@ibrahimhajjaj81554 жыл бұрын
Thank you sir.. I like ur way
@ghij7530 Жыл бұрын
Where i can find the explaination of chapter 10 ?
@Henry-yw8bl3 жыл бұрын
may i know which textbook you guys used? and where can i get the copy?
@panoskb94053 жыл бұрын
How do you arrive to the equation which include the term Hp?
@bashamsk12886 жыл бұрын
how can we increase Q at constant V ? Area? I mean with velocity diagrams we can calculate everything then why we need graphs for?
@CPPMechEngTutorials6 жыл бұрын
Since Q = VA, we cannot increase Q at constant V (assuming the fluid is incompressible).
@fa90lq5 жыл бұрын
For centrifugal pumps and compressors, the suction side is always one standard size larger than the discharge size. So yes, area will be a factor.
@osamashamil49413 жыл бұрын
Thank you sir for sharing this valuable informations !
@un77452 жыл бұрын
I have a question, If a centrifugal pump flow limit is from 60 LPM to 535 LPM at 3500 rpm, does the low flow limit of 60 LPM changes with running the pump at lower rpm? Does this limit changes goes down when we run the pump at lower rpm?
@mattstevenson58492 жыл бұрын
Surely changing the flow rate from 60 LPM to 535 LPM would mean a change of impeller, assuming constant rpm. If you have a 60 LPM impeller, on a 3500 rpm motor, and you reduce the speed of the motor - the flow rate will reduce.
@pnekanayaka46503 жыл бұрын
Great professor. Thank you
@satriobp93 жыл бұрын
on NPSH example problem, Patm defined by value of 101000 kPa. Should it be valued 101 kPa if Pv also in kPa? CMIIW
@dawidpietrucha53333 жыл бұрын
Yes you're right. He denoted it with the coma. However the value of Pv at 15C according to my steam table is equal to 1,7 kPa.
@bhradramazani3 жыл бұрын
@@dawidpietrucha5333 Same, from Table A.5 in the class textbook, interpolating you'd get 1.782 kPa for vapor pressure.
@arifabdurrahman25994 жыл бұрын
I just want to know that shouldn't the peak of efficiency be below the horsepower curve?
@Abhijeetsingh-ql5il3 жыл бұрын
Sir what will happen if pump is run at very low head than rated head... There will be low efficiency i know. What other practical problems will occur.
@leonardogomes63612 жыл бұрын
Very good vid
@planetdeepak4 жыл бұрын
Thank you very much
@benmoussayoucef46992 жыл бұрын
please can you tell us the effects of no flow rate (valve closed on runing pump).
@CPPMechEngTutorials2 жыл бұрын
The pump may overheat since it is dumping lots of kinetic energy into water that is not flowing.
@benmoussayoucef46992 жыл бұрын
@@CPPMechEngTutorials thank you very much
@samanvaziri8195 Жыл бұрын
It was great👍 thank you so much, but I should say the teacher made a tiny mistake, at the end of the video he wrote Q=V/A, actually it is wrong and the correct formula is Q=A.V
@CPPMechEngTutorials Жыл бұрын
Yup. That correction is already in the video notes.
@MunirLoyed Жыл бұрын
do you have videos for closed loop system.
@CPPMechEngTutorials Жыл бұрын
Some of the earlier videos in the lecture series involve the energy equation for pipes.
@rantogunawan41784 жыл бұрын
Well explained...thanks a lot
@rahulmore62745 жыл бұрын
Informative and pretty good.
@Rtqd7215 жыл бұрын
thank you very much professor!!!
@CPPMechEngTutorials5 жыл бұрын
You're welcome!!!
@brendangolledge83122 жыл бұрын
Is there a theoretical derivation for the shape of a pump curve? I guessed maybe a centrifugal pump imparts constant energy per unit mass to whatever fluid passes through it. Then you'd get E = constant (for any given fluid density) = P + (1/2)dv^2 (d is density), or h = E/(dg) - Q^2/(2gA^2). This has the shape of an upside down parabola (right basic shape), but when I try to compare it to real pump curves, the real curves turn downwards something on the order of 100 times faster than my theoretical model. Do you know why this might be? Am I making some unit conversion error, or is the whole thought process just wrong? If the real pump curves turned down something like 10-50% faster than the theoretical one, I'd be happy, because I guess the pump doesn't conserve energy perfectly and it doesn't have the same efficiency at all operating ranges. But getting a result 10,000% different than the theory is unsatisfying.
@seydou4325 жыл бұрын
Thank you so much for the excellent lecture prof. I have one question: why the efficiency form on previous graph is different from those of pump performance map?
@piyushgupta47692 жыл бұрын
Yeahh, the same question crossed to my mind !!! Even I'm confused for it
@seydou4322 жыл бұрын
Dear Prof! speaking about elevation of the pump above reservoir surface you said: Well, as you get the pump higher and higher in the flow rate, that pressure is going to start drop. I think that could be: Well, as you get the pump higher and higher in the elevation, that pressure is going to start drop. What do you think about that? Thank you very much.
@nooruddindalvi5916 жыл бұрын
The professor writes Q=V/A at 44:52, shouldn't it be Q=V*A?
@CPPMechEngTutorials6 жыл бұрын
Whoops! Great catch. I will put this in the video notes.
@HarisKhan-df8tr6 жыл бұрын
@@CPPMechEngTutorials CAN WE GET VIDEO NOTES PLEASE ??????
@CPPMechEngTutorials6 жыл бұрын
By "video notes" I mean the comments just underneath the video.
@masihtukhi63564 жыл бұрын
Professor: why is the velocity difference between point 1 and 2 very small? Shouldn’t the velocity at point 2 be very high because impeller blade is pushing the liquid and velocity should increase significantly.
@piyushgupta47692 жыл бұрын
The pump definitely provides Kinetic energy to the water which intutively make us think the increase in velocity of flow at outlet, but because of volute casing of pump that kinetic energy of fluid gets converted into pressure energy. Thus the velocity remains same. Moreover velocity is governed by the pipe diameter. Since pipe diameter at inlet and outlet of pump is assumed to be same and flow rate also going to be same to maintain steady state ( because whatever amount of water is entering , the same amount of water will move out of pump). Hope it will help!!
@ahmedabdelkader314 жыл бұрын
Hello, could anyone tell me how pump curve is determined at a certain speed however the input power = ( torque x angular velocity). so, to get more discharge we need more input power by increasing velocity and then by applying the efficiency formula (output power / input power) we can draw an efficiency curve. so, how this curve could be at a certain velocity?
@moazsalem34885 жыл бұрын
please Sir If the inlet fluid is subcold ( at low temperature ) but the liquid is entering the pump at low pressure and the impeller will start swirling the liquid and create bubbles just as when you move your hand quickly on water surface you will create water bubbles though the inlet pressure is above the vapor pressure is that possible
@dheyaalgallaf60602 жыл бұрын
What if pump delivers to two destinations
@operasisngr1153 жыл бұрын
Thank you for sharing
@chemicalengineer19852 жыл бұрын
Great explains 👍
@alipacheco81494 жыл бұрын
Great class. One would intuitively think that the velocity of the fluid at the discharge of the pump is higher than the suction velocity. Apparently, this is not true, because the professor is neglecting that difference. I would like to understand better the reason behind it. Any advice?
@laxmikantpuranik39673 жыл бұрын
Usually, suction pipe is one size higher than the discharge pipe size, hence the velocity in discharge pipe is higher than that of the suction pipe
@adjourafik26694 жыл бұрын
a book plaise ?
@htwang42284 жыл бұрын
Near 31st minute: It seems, we put g instead of 9.81 [m/s^2] in the N's formula JUST TO MAKE THE FORMULA VALID ON THE MOON. On the moon, g is small, the pump head H is big, hence g*H is the same as on earth.
@NuclearSavety5 жыл бұрын
Love this defining of all abbreviations .... thats unfotunately not standart any more...
@panosnik46625 жыл бұрын
ΦΙΛΙΕ ΣΕ ΕΥΧΑΡΙΣΤΩ, ΔΕΣ ΠΩΣ ΚΑΝΟΥΝΕ ΜΑΘΗΜΑ ΣΕ ΠΑΡΑΚΑΛΩ. Do you know If I could find the document that was given to the students? Thank you
@ahmednaji43755 жыл бұрын
what is the textbook title which you kindly are using please?
@CPPMechEngTutorials5 жыл бұрын
That information is in the video notes.
@halasimov13623 жыл бұрын
But what is the water horse power in Shark Power?
@MohammadAtaeinejad Жыл бұрын
Hi.tanks for this class. one mistake in calculating ouccer is Q=AV