Fluid Mechanics: Energy Equation Examples, Differential Continuity Equation (14 of 34)

0:00:10 - Revisiting conservation of energy for a control volume
0:03:58 - Example: Conservation of energy for a control volume, turbine
0:13:32 - Example: Conservation of energy for a control volume, pump
0:25:42 - Differential continuity equation
0:40:25 - Example: Differential continuity equation
0:44:59 - Preparation for midterm exam
Want to see more mechanical engineering instructional videos? Visit the Cal Poly Pomona Mechanical Engineering Department's video library, ME Online: www.cpp.edu/meonline
This lecture series was recorded live at Cal Poly Pomona during Fall 2014. The textbook is Munson et al., "Fundamentals of Fluid Mechanics (7th edition)."

[@crismathews4354]

Thank you for uploading these lecture videos online sir, you are a very good teacher.

[@ezez9213]

to those confused on how he got 28hp @20:00 , I found the question and the unit for the given losses (61/2V^2) is ft^2/s^2 which means it is per flow rate basis (or per m dot). So you need to multiply it by m dot to get the losses. (density of water is 1.940 slugs/ft^3 not 62.4... 62.4 Ib/ft^3 is the gamma... just a side note for those no used to english units like me XD)

[@casadehonguito6444]

This is definitely helpful! Now I understood how it worked!! Thanks ;)

[@calilife5392]

Thank you man. Stuck for 2 hours lol

[@chichorro1000]

I am really happy with this course because he solves a lot of different problems. Thanks.

[@guvencolak350]

You are the #1 mentor/teacher in yt Thanks again all your free classes

[@AceofDlamonds]

YES! I love the explanation of the small element values at 26 minutes.

[@AmeerHamza-bc4fh]

Is there any way to get a list of homework problems that Professor recommended to do from Munson's Book, the 7th edition, for full lecture series? Recommended Examples and problems from the end chapters? Thanks.

[@muhammadafifhidayat2566]

there are many meaningful words from Mr.John about learning something

[@kevtj7145]

bct pip

[@somethingdifferent1910]

At 0:09:07 we said z2=0 but isn't it supposed to be 0.5meters since we are looking at point 2 ?

[@f7773]

Thank you so much, sir!

[@MisterBinx]

I really wish he would teach Thermodynamics and post those lectures. These lectures have really helped me.

[@muhammedeminural3333]

check David Miller in this channel

[@joshuapancuelo1942]

Professor David Miller is a great Thermodynamics prof

[@chemicalengineeringbd7614]

May allah bless you, you are a great help for the students.

[@Nayan133]

Hello sir, please take some problems on the unsteady state type problem on the energy conservation equation.

[@LostInTheSalsa]

How does he get 28 hp at 19:49? I'm getting 459.5 hp.

[@juniorjay001]

Why isn't there an 'm dot' on the other side like in the equation?

[@engineerikramalimechanical5603]

THANK YOU SIR

[@rtrt2889]

Biddle is the best!

[@ragnorock08]

God Bless you sir! Saved my butt from failing fluids!

[@sydrive4320]

Let's hope he saves mine tomorrow

[@CPPMechEngTutorials]

So... was it saved?

[@locom16deen78]

i have mine in a few weeks,

[@AceofDlamonds]

I have mine in just two days. I'm afraid to say I was too late in watching these. But theres' still hope!

[@pyro.monkey2501]

where did the extra order of magnitude come from at 10:20 im getting 2224 W so 2.22kW not MW

[@grethuman]

That is because the density of water can be considered 1000 kg per cubic meter.

[@locom16deen78]

there is a mistake at 10:22 i think. shouldnt it be (50g)(rhoAV)=dotWt as that gives you the value that he writes???

[@ezez9213]

too late but nah he is correct

[@ezez9213]

@@harisabdullahbinashraf1346 yes sorry I just noticed he forgot to multiply the m. to (v2)^2/2 in the right hand side. 👌👌👌 he didnt subtract v^2/2 from both sides (if u mean v1). cuz v1 is already 0. everything good except that he forgot to multiply m.

[@ezez9213]

oh he corrected it later in the video after the girl pointed it out 😂😅

[@deva5355]

tell me name of book from which you are taking questions.

[@CPPMechEngTutorials]

The book title is in the video information section.

[@kingkd9201]

fundamentals of fluid mechanics

[@user-dw8lv6sy2y]

공학을 공부함에 있어서 많은 부분들이 단순한 식으로 표현된 것이 아닌 미분의 형태로 표현되어있습니다. 공업수학에서 배운 미분방정식을 활용할 좋은 기회를 이 영상을 통해 가지게 되었던 것 같습니다.

[@mohitoshdeb6579]

i have a doubt, so please reply. professor made a mistake at 44:17 in hurry ,after he puts that minus sign, isn't the equation possible? i mean if the value of x and y both gets equal to 2, 2y-x^2 =0 then the equation could be equal to zero.

[@TGreenWizard9]

My best guess is that it should be equal to zero for every value of x and y. That is, the result should be directly zero instead of 2y-x^2. I'm not 100% sure, but it looks like that's why.

[@rubenvanassche3255]

Yeah it's like you say, the question is not if it is mathematically possible, but physically. And since x and y are coördinates it's impossible for them to satisfy that equation in the whole flow.

[@towafubuki]

@@TGreenWizard9 thank you bro, I have the same question as mohitosh's , but I got it now after your ans^^

[@TGreenWizard9]

@@towafubuki no problem, happy to help :)

[@wowcoldboy076]

How do I get 28 HP 19:49, after plugging in all the values I get 17 HP

[@mattrhoades9487]

What he did not show is a conversion between "head loss" to "losses" so you need to multiply "head loss" by m_dot...then you get the 28 HP.

[@MarineOffshore]

why is v1 zero at 8:03?

[@vitorgtiepo]

The reservoir is very large

[@achillesheel12]

Generally free surface has negligible velocity provided reservoir is very large

[@muhammedeminural3333]

10:42 r/killthecameraman

[@engineerikramalimechanical5603]

PLEASE SIR MENTION BOOK

[@mikebernard8535]

Fundamentals of Fluid Mechanics, 8th Ed., by Munson et al.

[@adjourafik2669]

@@mikebernard8535 electronic book please

[@burhannecati]

why p1 is equal zero at 8:10-8:20

[@AhmedMohamedP]

pressure gauge at atm pressure = zero

[@MarineOffshore]

why is v1 = zero at 8:03?

[@YoussefCherqaoui]

@@MarineOffshore The water level, although you might think it is moving downwards, in dam examples and intro to fluids examples as well, the level is taken as a constant thus no change in displacement so 0 velocity)

[@altanaker9767]

@@YoussefCherqaoui Actually, it must be considered as a big reservoir. The surface velocity is too small thus it can be neglected.