Free Space Path Loss (ITS323, Lecture 13, 2014)

[@satisfylife7806]

Really very good class on Path Loss Model for wireless system, antenna gain calculation and free space loss. For Radio Frequency Engineer or In Microwave design student this lecture is very very helpful.

[@barancan_snmz]

indeed even 9 years later this is the best explanation I find.

[@rohitbabu5578]

I don't have any experience in particular lecture field. But i understood everything because of your lecturer sir thank you very much this sort of videos

[@greysonkingsley8446]

i guess I am pretty randomly asking but does anybody know of a good place to stream newly released series online ?

[@liamcharlie3592]

@Greyson Kingsley Flixportal

[@greysonkingsley8446]

@Liam Charlie Thanks, I signed up and it seems like a nice service :D I appreciate it!!

[@liamcharlie3592]

@Greyson Kingsley happy to help =)

[@aram1rasul751]

Reallly it is a nice explanation!

[@tariqislam9388]

@Steven Gordon Thank you very much for your perfect explanation. I have one question. Pr=(Pt.Gt.Gr.lambda^2)/(4.pi.d)^2. So if we know the minimum required Pr for successful transmission, we can adjust our Pt to achieve that minimum required Pr. However in this equation we are considering only pathloss. If the receiver is experience noise and interference, then do we have to increase our Pt even more to be able to achieve the required SINR. In other words is the following formula correct for the cases where we have interference and noise on the receiver side ---> Pr=(Pt.Gt.Gr.lambda^2)/((4.pi.d)^2 * interference Power* Noise Power)

[@ElReyMedy]

Thanks Steve...very helpful

[@ahmedhakem1031]

Is you can provid books pdf about : Empirical path loss models??

[@pigrebanto]

how can be that you transmit 10W and antenna multiply by 5? is there an amplifier? in previous lesson teacher said that power is anywhere less than 10W...

[@karthikeyini1215]

how to calculate received power in free space model by using directional antenna sir

[@aamirkhan9660]

very helpful sir,thank you.can i get your notes?

[@StevenGordonAU]

Go to sandilands.info/sgordon/teaching/ and browse for course ITS323 and then "Topics and Lecture Materials"

[@anjamesonusn]

It says clearly that it has 3*5dBi external antennas.... not 2dBi..... That's twice as much power!

[@aram1rasul751]

why wavelength and distance(d) are squared?

[@StevenGordonAU]

In the path loss equation, the path loss, Lp, is (4 pi d) squared divided by wavelength squared. See equation (2) and an explanation in: ict.siit.tu.ac.th/~sgordon/its323y14s1/reports/its323y14s1h11-path-loss-model.pdf