Numerical Problems on Plain Sedimentation | Lecture 11 | Environmental Engineering

[@shaileshsingh-px7zp]

Thank you ma'am for teaching us this whole topic from start till end, we can clearly see the amount of hard work you put into these lectures, thanks a lot. My request is if you will upload lectures of waste water engineering also, than it will be very helpful for us, Thanks a lot

[@alrekoth1005]

determine the storage volume of an overhead tank to balance the treatment plant output of 113500 m3 /day with the high service pumping with the following schedule: [10] 12 midnight - 6a.m. = 2.83 * 103 m3 /hr 6 a.m. - 10 p.m. = 5.68 * 103 m3 /hr 10 p.m. - 12 midnight = 2.83 * 103 m3 /hr utilize graph paper for plotting the supply/demand curves.

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Mam u r my back bone of study.... Plz upload more videos with regular basis.......... Plz upload fast We are waiting 10 days or more approximately to get a video....... Kind enough nd upload fast

[@-AnkurRajkhowa]

Hl na ni

[@Mohitkumar-hf9or]

In question no 4 change the depth by 9m automatically your answer will correct.....

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I appreciate work of Gate academy team as a student .

[@christopheralba7388]

thank you mam i will watch from the start your lecture.. to enhance my envi engr. course.

[@TheChiteau]

20:44 Ma'am the kinematic viscosity will be 1.002x10^-7 as the kg of Rho will need to be converted to N. Thus result of correct diameter will be 0.02 mm. This is verified as diameter for using Stoke's law should be

[@subhadasgupta5705]

Unit of Dynamic viscosity in SI unit is N-s/m2 or kg/m-s...both r same...when we divide it with density(kg/m3) we get kinematic viscosity,unit of which is m2/s....so no need to multiply 10...if u still have confusion comnt on this....

[@TheChiteau]

@@subhadasgupta5705 It's fine ma'am. Thanks for your reply.

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Mam, please upload videos soon. At least 1 video per week. Please.

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U teaching wonderful✨😍 ma'am

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Very good mam

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Amazing.. got my answer asked on the last video..

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U teach too good

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Tnq Soo much for such a valuable class madam please complete the syllabus of EE ....as soon as possible......👏👍

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Nice ma'am

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Thanks

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legend👌👌👌

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Great❤❤

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[@Vikashkumar-ht1rz]

Ma'am aap itna khubsurat ho ki blackboard se jyada aapko hi dekhta hu 😅btw it was so nice explanation

[@SantoshKumar-bu2qe]

Madam jb d=0.21 mm aa gya to Stoke's law kaise valid hoga ??

[@jayrpatel4041]

Vo myu ki value galat hai... question me Newtown me diya hai to use kg me convert karna padega so ans 0.02 ata hai

[@debasismishra2909]

Mam namaskar, please a class about RO and D. M plant

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Mam do you conduct any personnel class or is it only youtube channel

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Anybody please provide me info

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Thanks madam

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Mam ye jo last Question katwaya app ne wo thoda samjha nnehii aya

[@akshayhatwar9114]

Nise ma'am

[@akshayhatwar9114]

Ma'am or video bnayeyee fast on... All environmental subjects video..

[@vivekkumarpal2455]

Online class time ky ha

[@raviranjan4434]

For question 3 they asked the amount of solid deposit ... Means total SS - removed SS ie. 140-98=42 kg/day.... But u have written in ans as 98 kg/day can any one tell why

[@jeesmonbabu2053]

it says 70% efficiency that means 70% of total ss is removed hence 98(70% of 140)

[@subhampradhan935]

+Ravi Ranjan 98 kg per day is not removed. It's the amount of ss deposited at the bottom of tank. It would've been 140kg per day but the efficiency is 70% so it's 98. 98kg per day is not removed ss . It's the amount deposited at the end of the day

[@-AnkurRajkhowa]

@@subhampradhan935 I think per day remove.

[@sanketholey5496]

Plzz mam uploaded more video

[@Theek001]

Yours answers are not matching when done in calc

[@sanketholey5496]

Mam in this lecture Question no.2 and 4 is not correct ans

[@Mohitkumar-hf9or]

Bro what's wrong in this.....plz reply I'm also searching .....

[@subhampradhan935]

In question 4 Depth of water should be 9m instead of 0.9m The answer is correct d=.21mm

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10^6 kaise aya

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Thanks Mam