Fluid Mechanics | Module 5 | Fluid Flow I Boundary Layer Theory | Part 2 (Lecture 48)

Subject --- Fluid Mechanics
Topic --- Module 5 | Fluid Flow | Boundary Layer Theory | Part 2 (Lecture 48)
Faculty --- Venugopal Sharma
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9. Thermodynamics --- bit.ly/2PlxJ5O

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[@Yadhiyadgiri]

Sir, As i understand whenever a free flow, flows over any surface there develops a boudary layer. fine. whenever there is a boundary layer mass flow rate changes due to displacement, momentum and energy. you solved a problem for three compensations individually. what would be the compensation for three displacements combinely. as three exists at a time.

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How does density * Area * Velocity^2 will become momentum? as the unit of above equation is kgm/sec^2

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It's volume flow rate

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Same doubt..Sir has taken mass flow rate instead of mass

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Sir you told that the reduction in mass flow rate is for the particles above the boundary layer but you considered the reduction for the inside boundary layer particles in derivation of displacment thickness

[@Mechanicalverse]

Same doubt

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How sir you told mass is entering inside the boundary layer ...boundary layer it self is a apperant wall how it can possible

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Sir why does mass from outside diffuses inside boundary layer?...

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Because of the pressure outside the free stream (downword forces)

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Sir, Will there be rho infinity instead of rho n compensation for mass flow rate?

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compensate krne ke liye solid boundary upar ka badhna hoga niche ka nhi at 4:06 and 19:11 jo xx hai wo kitna upar ho kar compensate karega is mass flow loss ko wo displacement thickness degi

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Sir Doubt he ek , sir jab ham solid boundary ko (del *) distance par move karate he to velocity U infinity kyu lete he Or Kya velocity always hame U infinity hi leni he jab Bhi hum compensate karte he mass flow rate me tab ????? please sir explain

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When we solving displacement momentum and energy thicknesses ......why not considering the constant .....C.....

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