BIBO Stable and BIBO Unstable System (Signals and Systems, Lecture-16) by SAHAV SINGH YADAV

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GATE CRACKERS

GATE CRACKERS

Күн бұрын

Пікірлер: 56
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 11 ай бұрын
My first book on "Let's play with Signals and Systems Part-I" is now available on: 1. Ebook (Amazon): amzn.eu/d/8yMs0ND 2. Ebook (Google Play): play.google.com/store/books/details/SAHAV_SINGH_YADAV_Let_s_Play_with_Signals_and_Syst?id=-1n2EAAAQBAJ 3. Ebook(Google Book): books.google.co.in/books/about?id=-1n2EAAAQBAJ&redir_esc=y Hardcover and Paperback Editions are costly as these Editions are published on amazon.com (foreign market) 4. Paperback(Amazon): a.co/d/bBHawdJ 5. Hardcover(Amazon): a.co/d/0BJ0clc
@mahakhan9762
@mahakhan9762 5 жыл бұрын
this is one of the times where i'm thankful that i can understand hindi
@kuchalag3621
@kuchalag3621 5 жыл бұрын
sir at 6.27 , cos^2 theta = (1+cos2theta)/2 ,
@lakshaya
@lakshaya 4 жыл бұрын
Bhut bhut dhanywaad sir 2 subject complete ho gye EDC AND SAS. Sir ek doubt bta dijiye plzz.... Sir kya playlist completed h signal system and edc ki ki ya kch left h Mtlb aap bta dijie kyoki sir only aapke channel ko follow kr rha hoon and only self study kr rha hoon
@TheKingmalik007
@TheKingmalik007 4 жыл бұрын
@ 8:46 if we put x(t)=k=infinite, then 2x(t)=infinite will come.. that will be unstable and you've said that the system is stable. How.? Please explain
@kaushikmondal3005
@kaushikmondal3005 5 жыл бұрын
One more exciting session. 👍👍👍👍
@akaneeii
@akaneeii 5 жыл бұрын
Sir can u pls.. Provide the core subject.. As I am just following u..u not only the best teacher but also the great motivator..
@AjayKumar-ul2dg
@AjayKumar-ul2dg 4 жыл бұрын
heartly thnks sir. Happiiee New year.
@mohduzair6392
@mohduzair6392 4 жыл бұрын
Sir at 7:00 , y(t) = ∫x(τ)cos(τ)dτ yahan pe integration -∞ se t tak hai , agar yahan pe x(t) ki jagah u(t) rakh de to integration 0 se t tak ho jayega aur integrate karne pe answer ayega sin(t) jo bounded signal hai to ye to BIBO stable ho jayega is hisab se . Is it correct or am i wrong somwhere ?
@krupakararroju9015
@krupakararroju9015 4 жыл бұрын
Brother,We have to check for every signal not only unit step
@mohduzair6392
@mohduzair6392 4 жыл бұрын
@@krupakararroju9015 oh ok , thanks man 🙏
@parmeshgupta6346
@parmeshgupta6346 6 жыл бұрын
Sir your videos are awesome
@Narendra_live
@Narendra_live 6 жыл бұрын
Nice lecture sir...
@utkarshpant5297
@utkarshpant5297 6 жыл бұрын
Sir please start Communication Systems.
@prayasjakhar5207
@prayasjakhar5207 5 жыл бұрын
sir tx(t) m infinte put kra aap n but sin(x(t)) m infinte put nhi kyia aisa ku at 9:34
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 5 жыл бұрын
Sin{x(t)} me x ki infinite value rakhne p sin ki value -1 se 1 k beech me hi ayegi... Because Sint will range -1 to 1 hoti h
@siddhant-x8k
@siddhant-x8k 5 жыл бұрын
Sir delta(0) ki value to infinite hoti hai na? for direc delta fxn. Area 1 aata hai. but value to infinite hoti hai @29:01
@tusharsrivastava4364
@tusharsrivastava4364 4 жыл бұрын
Funcn discrete tha
@sangitakumari6364
@sangitakumari6364 3 жыл бұрын
Thank you sir.
@vvsr100
@vvsr100 6 жыл бұрын
sir at 22.27 if a>1 then area is negative by integration and infinite from graph i am confused here
@myravaldez8376
@myravaldez8376 5 жыл бұрын
Sir, please help with this question Determine if the system is stable or unstable 𝒚(𝒏) = 𝒚^2 (𝒏 − 𝟏) + 𝒙(𝒏), for the bounded input 𝒙(𝒏) = 𝒖(𝒏) + 𝒖(𝒏 − 𝟐)
@kshtriyesingh5488
@kshtriyesingh5488 3 жыл бұрын
Input is not bounded as summation goes infinite hence output always unbound..
@pavleenkaur8498
@pavleenkaur8498 5 жыл бұрын
Consider a system with input x(t) and output y(t) related as follows y(t)=d/dt {e^-1 x(t) } Which of the following statements is TRUE A)the system is non linear B)the system is time invariant C)the system is stable D)the system has memory Sir please help me solve this
@kshtriyesingh5488
@kshtriyesingh5488 3 жыл бұрын
2or 3 but mostly system is stable
@dinkarjha8821
@dinkarjha8821 6 жыл бұрын
At 29.06 aap h(n)=0 for n
@bhawanishankar13
@bhawanishankar13 5 жыл бұрын
really amazing sir
@swatiyp6502
@swatiyp6502 6 жыл бұрын
Sir, Need lectures on power systems also.
@RJ-bd3ww
@RJ-bd3ww 4 жыл бұрын
Sir is from ECE
@thedopegamer313
@thedopegamer313 5 жыл бұрын
sir if there is y=x(t+1)+x(t) then how to keep k in this equation
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 5 жыл бұрын
K1 and k2 in place of x(t) and x(t+1)
@amulyaputtapaka1480
@amulyaputtapaka1480 5 жыл бұрын
Sir,I didn't understand how ten pi by 2 becomes unstable and infinite. Please explain sir
@ajitsikdar7613
@ajitsikdar7613 4 жыл бұрын
tan(π÷2) value is infinity
@RajiSuresh-Spiritual-Talks
@RajiSuresh-Spiritual-Talks 5 жыл бұрын
Thank you sir
@sajalbarsainya7037
@sajalbarsainya7037 4 жыл бұрын
Y(t)=x(sint) sir..this system is stable or not..?
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 4 жыл бұрын
Stable
@sajalbarsainya7037
@sajalbarsainya7037 4 жыл бұрын
@@GATECRACKERSbySAHAVSINGHYADAV Thank you sir
@shahnaz1981fat
@shahnaz1981fat 4 жыл бұрын
Y(n)= exp[x(n)] is it stable sir?
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 4 жыл бұрын
Yes...it will give finite y for finite x...
@shahnaz1981fat
@shahnaz1981fat 4 жыл бұрын
Nice content in your videos sir
@punityadav5545
@punityadav5545 6 жыл бұрын
sir y(t)=x(t)/sint is this system stable or not answer given as unstable how sir please send me the group information so that i could join your group
@GATECRACKERSbySAHAVSINGHYADAV
@GATECRACKERSbySAHAVSINGHYADAV 6 жыл бұрын
Unstable... Because Sint will be zero for any integer multiple of Pi.. Hence y(t) will be infinite for finite value of x(t) at those values
@adarshkasera8172
@adarshkasera8172 6 жыл бұрын
Please add lecture on power electronics
@ranitmandal5959
@ranitmandal5959 6 жыл бұрын
great job sir.
@riteshkumar476
@riteshkumar476 4 жыл бұрын
sir plzz make a new whatsapp grp so that we can ask the doubts plzz sir will be very thankfull to you
@vishalsagade
@vishalsagade 5 жыл бұрын
Sir y(n)=cos[x(n)]....?
@towardstosuccess3944
@towardstosuccess3944 4 жыл бұрын
Stable
@ktk3228
@ktk3228 5 жыл бұрын
sir i want to join the group
@Rahulkumar-mu2qd
@Rahulkumar-mu2qd 5 жыл бұрын
Sir samaj n ya raha hai ya baa
@edutechpathsala4850
@edutechpathsala4850 5 жыл бұрын
Cosine's formula is +..
@arjunfitness3836
@arjunfitness3836 4 жыл бұрын
Cos^2x=1+cos 2x/2
@a2a708
@a2a708 6 жыл бұрын
Power system lecture daliye
@apoorvagarwal796
@apoorvagarwal796 6 жыл бұрын
Wow
@vishalkunyal7698
@vishalkunyal7698 6 жыл бұрын
Sir online course nikalo koi paid
@meenazsaiyed4833
@meenazsaiyed4833 6 жыл бұрын
e^[-(1-2j)t] u(t) is stable??....e^(-t) cos2t u(t) is stable ??
@mukeshjadon8017
@mukeshjadon8017 6 жыл бұрын
meenaz saiyed may be both stable
@biuhalchatterjee2775
@biuhalchatterjee2775 2 жыл бұрын
Thank you sir
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