#4.4 Which of the following systems are BIBO stable?

[@andersonreis5024]

Just amazing. Pretty simple, too. Thanks

[@sazzal3016]

Unfortunately, impulse signal tends to infinity as t tends to zero. Therefore, it's not a bounded input, since the requirement for a bounded input is to have finite value at each and every instant of time. Instead, unit step input could be an example of bounded input.

[@rajshiromani727]

Motivate your answer: Me: hey get up, yes you can do it,get up🎉🎉❤❤

[@SalmanLukaku]

Thanks

[@eggxecution]

if real number is negative it is stable, if real number is = 0 it is marginally stable, if real number is positive it is unstable

[@jasonretik]

Isn't the rule that the ROC must include the imaginary axis? For this to be true the system must also be causal to be stable? Agree?

[@jeffbezos3942]

For pole z=o we can it is BIBO stable?

[@tilrwu]

No, it's considered not BIBO stable. The poles MUST lie in the real LHP strictly.