Gay Lussac's Law Practice Problems

To see all my Chemistry videos, check out
socratic.org/chemistry
A bunch of example problems that show how to use Gay-Lussac's Law.

[@apkeu4345]

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[@sheepherder1014]

Yes I am watching this the night before my exam how did you know..

[@tdewitt451]

Hey everyone, I'm here to help. If you have any questions or just want to learn more, click on the link in the description above. It'll take you to a page where you can ask me questions.

[@fakharuddinmahmud871]

Hello,I am from Bangladesh. Can I use this in higher secondary education (class 12)?

[@gihansaid9854]

Why we have to convert to kelvin as he asked calculation of temperature in Celsius in the second problem?

[@tdewitt451]

yes, it's called "gas pressure conversions." i made it a long time ago, so it looks really ghetto, but the information is solid.

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This is really helpful !thanks a lot

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[@vajirabalasuriya1224]

This is great teaching. I am totally new to gas law and your collection of videos helped me immensely. thanks so much. cheers

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I went back to school to become a Veterinary Technician and I am currently taking Chemistry. Unfortunately, I have a teacher that just reads off power points and doesn't show us problems or solve problems together with us (even when we ask). I was suffering through Chemistry until I saw your videos. Thank you so much! I will probably pass this class and go on to the Vet Tech program because of you! *hug*

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Did you pass the class?

[@jayhung8811]

Really helps when you explain them slowly and in detail

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[@austinwalkup6366]

You could just cross multiply using p1 over t1 equals p2 over t2 you will get the same answer

[@sinaunangmusikera245]

But how about converting it to Celcius like the problem no. 2 in 11:45 ?

[@rahma0_0.]

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[@amacbook6565]

Thank you for the walk through on how to solve these problems.

[@randomgamer8863]

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[@BigNoodLL]

Another way to solve the first problem would be cross multiplying. If you were looking for P2, for instance, you would multiply P1 and T2, and multiply P2 and T1. This would get you P1xT2=P2xT1. To get P2, you have to isolate it, or get everything else on the other side of the equation. So to get P2 on on side, you would divide T1 from both sides, because if you do something to one side, you have to do it to the other. T1 divided T1 cancels it out on the right side. On the left side, you put the entire part over T1 to get P1xT2 divided by T1, or P1xT2/T1. This leaves you with P1xT2/T1. Then you just plug in the numbers and solve! I hope this helped! This took a while to write (I am in 8th grade btw, so its a little confusing to me).

[@ivyy6437]

I think i may be able to pass chemistry now that I learn better from you! Thank you!

[@tdewitt451]

@jobicutooo great. also, you might want to check out the "gas law faq and extra help" video.

[@lisaduncan7232]

Your videos are terrific at explaining these problems. However I was wondering if you have to convert the pressure from kPa to atmospheres?

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[@florida7879]

thank you so much, all of the videos are so helpful

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THANK YOU SO MUCH! I don't know why my chemistry teacher cant teach. I was able to learn how to solve gay lussac law in 5 minutes thank you so much

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[@Beachloverathome]

you rock! i have an test tommrrow on this and this help a lot ! thanks a ton :D

[@dc-nw8kv]

What happens when there is a range of temperatures and they ask you for the final temp? I.e: the temp of a sample of gas in a steel tank at 2.81 arm is increased from -117.4 C to 5100 C to 94.8 C. What is the final pressure inside the tank?

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[@tdewitt451]

@Farawla You ONLY have to convert if you have two different pressure units. Kpa, atm, mmhg are all fine if BOTH pressures are in those units. So if P1=23 kpa and P2=84 kpa, you're fine. But if you have P1=23 kpa and P2=4.5 atm, then you have to convert one of those two pressures so that they're both in the same units. Does that make sense?

[@Barney_Is_your_Friend.]

Well thats confusing

[@analeahrondillos421]

Hi can you answer this. An aerosol container has a pressure of 3.00 atm at 30.0°C. what is the new pressure in the aerosol container if it is thrown into a fire with a temperature of 600°C? The aerosol can explode if the pressure inside exceeds 7.00 atm. Would you expect the can to explode? Im stuck with this. I need help pls🥺

[@dmiu1996]

thanks for the vids! there really helpful? But i was wondering , my class is doing ideal gas laws is there a order of videos you recommend watching

[@aceeky9318]

On the second problem, can't I just multiply the P2/T2 to P2? And then cancel the P2 to leave a T2 alone. Is it possible or nah? Please answer. Thanks.

[@JohnnyJr396]

Can the ideal gas law be applied to a propane tank? If not how can you calculate the pressure?

[@jannlevimaningding8319]

how to find what's p1, p2, t1 or t2? im a little bit confused with that part

[@mmk6673]

You saved my life with this! Thanks!!

[@localchumb]

is it ok to convert the temperatures to Rankin if the question posts it in Fahrenheit?

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You should be my chemistry teacher， this is damnnnnn helpful！！

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Still saving 2021 kiddo. 🙌💪

[@1000frolly]

Tyler I somehow have 'hot' wheels; My tyres are flat and have an air temperature of 293 Kelvin and a pressure of 101.3 kPa. If I pump my tyres up to 230 kPa what is the temperature inside the tyres? T2 = T1 x P2/P1 T2 = 293 x 230 kpa / 101.3 kPa T2 = 665 Kelvin!! This cannot be right - where did I go wrong?

[@michaeljohannsen6020]

why are you not using 273.15 for the conversion from C to K?

[@riyapeter1211]

Hi ur videos r very helpful. don't u have any videos on the explanation of gay lussac's law of gaseous volumes like you have on Avogadro's law? I did not find any.

[@yngarreglado2988]

THANK YOU SO MUCH. NOW WE LEARN HOW TO SOLVE IT AND IT IS JUST EASY THANKS

[@green_razor8569]

Those are some really nice markers really satisfying when he circles the answer idk why

[@tdewitt451]

@pepteamsergi09 for the answer to this, watch my video called "addition and subtraction with significant figures."

[@angelobrowndeguzman4628]

Can I just use the equation T2=p2xt1 divided by p1? haha I dont want to do what you did up there doing many stuffs just to get the T2=p2xt1 divided by p1

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YOUR VIDEOS ARE AMAZING THANK YOU

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Thanks for saving us in 2022

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Thank You Sir Tyle DeWitt i really understand your discussion..

[@vanessafanoga4798]

we can apply the rules of cross multiplication instead of the long method right? anw this is helpful thank you!!!

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Can i ask where did you get 273?

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[@jobicutooo]

what happens if you have two pressures but one temp. would the equaltion be P1/(T1)(P2)=T2??

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[@wendys209]

Do you have a video on this? Converting Kpa to mmHg? Great videos by the way. =)

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When you explain it its so simple

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Because of you my friend I might pass chem

[@monghewc8316]

Where you get the 257 kPa

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Its actually helping me to advance my knowledge 😊😇

[@Danielmendenhall_]

Thank you, Mr. Dewitt!

[@oookillum990]

Damn you mr.roy why can’t you teach like this dude

[@pepteamsergi09]

when talking about rounding.. if we use K= C + 273.15 then u'll ended up with 298.45??? so when rounding when don't??

[@mochitopus737]

What if what's missing is the P2 and T2??

[@Farawla]

In Boyles law you have to convert the kPa why didnt you convert it into atm in the first question?...PLEASE HELP!!!

[@sharmainegalela887]

Sir, what if the given question is increase

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[@prateeksenapati2152]

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[@pieats]

Why was Celsius converted to kelvin again?

[@miicototanes150]

It worth it and help many people.💪thanks

[@MaximizedOfficial]

Thanks for the great video. Couldn't you just cross multiply to make it easier though?

[@SentimentalGentleman]

Another way: Cross multiply (P1 x T2 and P2 x T1)

[@jaylouisrubio2844]

lol i learned a lot from you than my teacher XD.

[@jhoeannelim6018]

its. . P2=P1 T2 over T1.. and it has a point which is total of 257.46 Kpa. but it helps me alot. .tnx

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[@lyricarf5797]

I calculate 4.08×298÷2.38= 510 why your answer is 511?

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