Germany | Can you solve this? | Math Olympiad

[@maths01n]

Watching and learning ❤❤

[@MasterTMathsClass]

✌️♥️

[@ethoslogospathos]

I used to be able to calculate this when I was a student at UC. I was very good. Now, over 12 years later. Nope! If you don't go to the gym, the muscles shrink. I never encountered a reason to calculate logs. Physics a few times. Trig even more. Wet noodle.

[@VitorJKhan]

2³x=50, x= 50/3 log2

[@AlexanderSemashkevich]

x=(log100-log2)/log8≈(2-0,3)/0,9≈17/9. Absolute error is about 0,0076.

[@rafaelyorro4466]

Lo hiceeee

[@MasterTMathsClass]

✌️♥️

[@Kwalliteht]

8^x+8^x=100 8^x=50 x=log8(50) x=1.8812853966 (I guess we don't need more digits). 2*8^1.8812853966=100.000000001751951 (this should be accurate enough).