Gravitation 04 | NCERT Numerical Practice Session | Class 9 | NCERT | Sprint

[@PW-Foundation]

📝Download Lecture Notes From PhysicsWallah App : bit.ly/2SHIPW6 🎯 Science group- t.me/joinchat/RYszj_1cAl8xEvnv 🎯 Social Science- t.me/joinchat/GCBE5bDgFdxrZeI8 🎯 Mathematics group- t.me/joinchat/GBbG4p5S_OVRV920 ----------------------------------------------------------------------------- 🗓️ Scheduled Syllabus For Sprint ( Class 9th ) released describing which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 •Duration:-1 month (Jan 2021 - Feb 2021) 🎉 Free Batch Exclusive on our KZbin Channel : Physics Wallah Foundation - 9 & 10 •Batch Details : 1) Best Faculties across India for different Subject/Topics. 2) Complete & Relevant Syllabus Coverage of Class 9th within 1 Month - Fastrack January 4,2021- February 15,2021 3) Monday - Saturday : Scheduled Classes everyday. •Physics : Tuesday, Saturday •Chemistry : Wednesday , Friday •Mathematics : Monday, Wednesday, Friday •Biology : Wednesday , Thursday , Saturday •S.ST : Tuesday, Thursday, Saturday, Sunday 4) Scheduled Syllabus released describing which topics will be taught for how many days. Available at PhysicsWallah App :bit.ly/2SHIPW6 ----------------------------------------------------------------------------- OUR SOCIAL MEDIA PROFILES : ⭐Instagram Handle : instagram.com/physicswallah/ ⭐Facebook Page: facebook.com/physicswallah ⭐Twitter Account : twitter.com/PhysicswallahAP?s=20 ⭐ PW App on Google Play Store : bit.ly/2SHIPW6 ❤️ Padhai Karte Rahe, All The Very Best 👍

[@editorvindhyalok7300]

Thankyou sir 😊😍

[@non-stopstruggle578]

Sukriya

[@non-stopstruggle578]

Sir naye batch ke liye new video banaiye

[@Ckr010-w1k]

Thanks sir mujhe sare numericals to aate hai par sir mai bahut confuse hoti hu ki g ki value me minus me li jayegi ya phir + ki

[@fearlesswarriors7270]

15:51 sir 16.333333333 ans

[@Chad_Stand]

5:34 Sir g will be positive if. the object is stationary or moving downwards. g will be negative if the object is moving upwards.

[@awakinthunder]

purane lectures dhyaan se dekh samajh aa jayega

[@kanu6894]

@@awakinthunder kal exam hai purane vedios dekhne ka time nahi hai please batado kyu hoga aisa

[@kanu6894]

@@awakinthunder aur ho sake toh abhi

[@heerjaitly1179]

@@kanu6894 dekh ek easy way bata rahi hun. In our no. Line if we make it vertical negative no.s were coming down so if it's falling down soo the g will be negative. This isn't the correct explanation and shit but this is a trick of my own

[@rishisingh2500]

yep, because force is working against gravity but there the car is coming down that's why downward g will be p+

[@kAushalkumar-tc9hb]

46:01 Sir is singing a song. Mai itni sundar hu mai kya kru. I m like wah sirr moj kra di sirr moj 😀😀😀😀😀😀

[@gamingassassinyt1672]

Lol 😆🤣😂😹😆🤣😂😹😆🤣😂😹😆🤣😂😹😆🤣😂😹😆🤣😂😹😆🤣😂😹😆🤣

[@rishabks1381]

Yeah 😂😂

[@MONIKAKUMARI-kj4yd]

😜😜🤣🤣🤣🤣

[@NirajKumar-te3ou]

Aise koi na majak mat udao

[@ninad6971]

Rakshak(protection) sir always protects us from failing in physics...😂

[@yashpalrajput7818]

Bro

[@diamondnahihai2482]

Sir yarrr 3 eq kyun lagai

[@gamingwithrounakrkg1709]

Rakshak means protector not protection

[@ninjathesmartboy3892]

at first i thought you are talking about other protection ........

[@VarshaKumari-oz2oj]

Flirt with us to fell in love of physics 😅😅😂😂

[@anonymousfahd]

15:47 Correct answer is 16.3

[@nusratperween5752]

Chlo koi to h jo meri trh soch rha h

[@nakulattry4593]

Yesh

[@artofenglish7159]

Bhak

[@Akash-vn4cw]

26:26 Sir, the final velocity should be negative, but it is positive. Why?

[@prexoYT]

Sir i got full marks in my physics UNIT TEST and i only study from you i dont have a tution or any coaching bus sub aapki kripa hai, THANK YOU!

[@Ajay-nv3lg]

😇😇😇😇

[@youareunique123]

Sir distance =upward height +downward height that is 80+80 =160. and displacement =0 because initial and final point are same

[@gamercrystals8679]

Same doubt

[@lanterneditz4150]

Me too

[@rimplesingh4335]

Yeh galat kar hai upar ke liye bhi - and niche ke liye bhi -

[@mukeshduggal9338]

For falling objects, NCERT books states the gravitational acceleration is positive whereas you say that it is negative. It's confusing. Could you please recheck and clarify.

[@triggeredfacts3265]

Same problem bro

[@AnshuKumari-ts3gk]

Same here ...

[@dynamicsgaming4780]

Same problem here

[@yoman9161]

In lecture 1 or 2 sir said that in bigger classes this positive will be however turned into negative itself that's why he said it otherwise it will cause problem for students in future however it is correct in book at standard 9 but it would be changed in 12th or 11th if u will opt for sci

[@adityasingh10th71]

❤

[@pranlegamerz3868]

28:43 sir total distance will be 160 na because it have asked total distance covered by stone if the stone will go 80m up then it will come down also 80 m and the net displacement will be 0

[@shubham7009]

Yup.sir is wrong here .so It's simple net displacement is 0 because stone reveredy to is actual position and total distance covered = 80 +80 =100 m

[@sibasishpurohit]

In question it is not given that the stone come to the ground

[@pranlegamerz3868]

@@sibasishpurohit brother if it will go up then its fact it will come down even

[@gamingclouds15]

@@sibasishpurohit bhai gravity name ka bhi koi chiz hota hai 😂😂😂 vaise ncert book me bhi back page me answer diya hua hai dekh lo Chapter 10, question no. 15

[@gamingclouds15]

@@shubham7009 80 +80 =160 not 100 Shayad tumne galti se 100 likh diya 😅

[@brajeshpal7756]

Thanks for 4th lecture ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

[@reignschampion]

28:40 sir but here total distance= 80+80(ascend+ descend) = 160m Displacement=0 (because when we throw a stone it get backs to initial position so displacement will be 0.)

[@reignschampion]

@Technoblade rest in peace bro when we throw something it always attracted to earth due to gravity.

[@reignschampion]

@Technoblade rest in peace Are bhai kaihna kya chateh ho

[@reignschampion]

@Technoblade rest in peace Jo tumne kaha 🤭🤭

[@EDUWITHRAGHAV]

Right

[@nilusingh377]

Total distance will still be 80m, not 160, since the body hasn't come to ground yet. Take Hmax to be distance covered, Hmax= u^2/2g , direct formula, if thrown at an angle then multipy u^2/2g into sin^2theta.

[@anaghanair7739]

Sir in question no 1, when an object is thrown upwards, acceleration due to gravity is negative and when an object falls downwards g is taken positive..?

[@reddymadhuri67]

We always take g =-9.8 because it always acts downwards. as in free fall questions a=g so acceleration becomes -9.8 .

[@reddymadhuri67]

There is nothing like +g

[@anupamadhoot7928]

Check previous videos

[@Lkshydv]

Sir in Q3 the mass of moon will be 16.3 Newtons, not 16.6 Newtons

[@kashafthegamer3757]

You are right team pw

[@NepalSingh-gd1ou]

You are right

[@NepalSingh-gd1ou]

My son

[@shivamtomar1453]

Abe tum sab galat ho Are Uloooho 🦉 Answer 16.2 N hoga na ki 16.3 N 💢

[@ridhima2019]

It can be both values depend upon that u choose g = 9.8 or 10 m/s^2

[@Tejal_rana07]

46:07 he is singing itni sunder hu kya karu😂😂🤣 lit yaar sir app sach mein lit AF ho💥💯😂🤣

[@Heyyy_Envy]

🤣🤣

[@aayan230]

Kal kiski kiski exams hai 😂 all the best for tomorrow's exam 😂😂

[@UnknownUser-my1md]

kal mera exam hai 😂 Thank You...

[@saritagupta5604]

Mera ! Thankuuu !

[@Its_Aayu13.]

Mera😂😜

[@s.mtruegamer3663]

Thank u .

[@indugautam6387]

Mera

[@sujit3577]

44:50 Sir maine a = 9.8 Liya tha to mera U= 29.4 m/s S= 44.1m/s Position =39.2 m Aaya hai to kya yah sahi hai?

[@Darkypekka]

28:45 sir actually total distance will be 160 meters because it is also asking the distance to up +distance down

[@039c2]

Then the displacement will be 0 bro...!!

[@039c2]

@Snehal Gaming YT Hnnnn😜

[@vatsalyavashisth9563]

no then displacement would become 0 the question just said that it went not that it came down so distance would be 80 only

[@Amansarkar700]

u=√20h dhalo answer mil jayega

[@Amansarkar700]

We know that u=40ms-¹ and we don't know displacement hence apply u=√20h then, 40=√20h, square both sides to remove root then (40)²=(√20h)² now 20h=1600 h= 80m if you like my solution pray 🙏 for sir Issac Newton RIP

[@mohammadalquama6393]

For falling objects, NCERT book states 'g' is positive where as you say its negative . Could you please check and clarify..

[@anupamadhoot7928]

Plz check previous videos of the chapter......your queries will be solved

[@avanish1203]

Sch me kya bhaukal hai physics wallah ka Loved it a lot ,❤️❤️❤️❤️😍😍😍

[@S_KING69]

Uses insta..?

[@educationalspirit.]

28:40 Sir net displacement will be zero because final and initial position are same. And distance= maximum height ×2 =80×2=160m respectively

[@AryanPanda-pk5jf]

Not as per the question. It never mentions that the stone comes down again. It just says it reaches a height and then we stop tracking the motion of the object so final position is not the same as initial position. Therefore, net displacement and distance is the same as motion is in a straight line. So all answers are 80 metres.

[@AryanPanda-pk5jf]

Hope you got it!😊

[@educationalspirit.]

@@AryanPanda-pk5jf it's not said but according to gravity it will come down for sure

[@AryanPanda-pk5jf]

I understand what you are trying to say, but we must only consider the given data as per the question. But like you said it will eventually come back to the ground. For the sake of the question, we don’t consider it. Just like in math questions, nobody is going to buy 100 oranges, if you understand the meme.

[@ekamjotkaur9116]

​@@AryanPanda-pk5jf but in NCERT books displacement is given as 0 and distance as 160

[@deepmalagogad4719]

THOSE WHO AGREE PLEASE LIKE...❤❤❤🎉🎉🎉 Sir, if an object is stationary or moving downwards the gravitational acceleration will be positive... And if an object is moving in upward direction the gravitational acceleration will be negative....

[@AryanSharma-os8xy]

28:53 best part 😄😄😄😄😄

[@naman5812]

Sir for last question it should not be √132 / 10 👎. Sir it should be √134 /10 . You are my best best best physics teacher ☺️

[@dipanshukumar8068]

32:47 legends have noticed this😏😏

[@architha7056]

When an object is thrown upward direction it is negative when it is thrown down it is positive

[@HarjinderSingh-xt8qd]

Yes. Sir told wrong in 1st question

[@Khushi_mehra_OK]

Yess

[@anaghanair7739]

exactly

[@khushitiwari16264]

Sir ke purane lecture fir se dekho

[@Gaming.withSharmaji]

Yes brother

[@saharshsharma6871]

15:56 sir (g= -10) then the answer would be in positive (-100) because the force is downwards and acceleration should be taken negative?

[@iamarider4855]

28:36 sir net displacement will be 0 m

[@alokgupta496]

Sir I don't know physics but ..I think in free fall when the car is falling towards downwards direction then we will take g as + ve bcz it's moving under gravity

[@balkrishnasrivastava7541]

Yeah...mujhe bhi isme hi doubt h

[@astroxxgaming5031]

ha BHAI I WAS FOUNDING THIS COMMENT

[@PieVio]

Bro it would be negative according to the Cartesian plane. Either positive or negative, it is correct though.

[@programmingwithkartik4319]

na bro deko hamesa direction of vector quantity cartesian plan ke hisab se lo fir kabi galat nhi honga

[@Kush__216]

Sir we take value of g + when it fall vertically downward and we take value of g - when a object vertically upward

[@GurdeepSinghSardar]

Yes bro

[@sudhirkumarsharma9680]

actually we take the signs - positive or negative , by cartesian plane and in the cartesian plane - for the downward direction we take minus sign as we have learnt in the chapter 3 of maths -coordinate geometry

[@davlearning4672]

All the best legends for tomorrow exam's 👍🥲🥹

[@theverse1256]

yep

[@The_wax_1M]

Sir aap bahut accha padhate ho you are best teacher.

[@DestroyerMahakal]

37:34 sir is standing on a platform near the board. Whoever who observed next to me should be a legend 😆😆😆

[@kumar.a.v3095]

38:30 pe sir jo figure banaye hain uske bare me aap bat kar rhe hain kya🤔😏

[@harshitavishwakarma5681]

Me,

[@pokegamer4403]

@@kumar.a.v3095 sir platform se utre the

[@lakshaygupta8496]

Can anybody help me? At 37:10 , Sir found out the speed which was 4s. However, it's given it takes a second to cover 25s and height is 100 m. Than you can find it easily by doing 100/25 = 4s.Than, why sir told a big method.

[@akshatupadhyay6360]

@@lakshaygupta8496 bhai ya to english Improve krni pdegi tumko Ya to tumhara concept haga hua hai.. It's given the stone is projected upwards with an initial velocity(u) =25m/s Not That the stone takes 25 seconds to Do the Motion.. Hope you understood. And speed can never be in seconds It is always In Seconds U have written in ur comment that speed=4s. Try to improve your concept understanding and practice. Just a friendly advice.

[@surendarkumar4820]

You are the best teacher in the world thank you very much sir you explain very well

[@LuckySingh-yh5mx]

28:45 The maximum height attained by stone is 80 m. The total distance traveled and displacement of the stone after reaching the ground is 160 m and 0 respectively.

[@himanshijha5706]

I feel the same.

[@shalinraj8046]

Yes

[@MRGENIUS22]

No bro kyuki sirf pusha tha ki stone ne kitna distance cover kiya . Ye to likha hi nhi tha ki stone return to the ground .

[@stevenamvs5540]

@@MRGENIUS22 haan i agree

[@helllegend1579]

@@MRGENIUS22 total distance covered pucha tha

[@aglwildfox259]

I am just wondering that how the gravitational acceleration can be -10 m/s as gravitational force act downwards and the object is also falling downwards.. So the g should be 10 m/s

[@MariaMaria-oy5yp]

Because g is along -ive y-axis

[@sibambehera6026]

Sir has done some mistake.

[@Pianoplayer6136]

@MariaMaria-oy5yp This is not maths this is science

[@samikshaverma4122]

Same doubt 🧐

[@sudhirkumarsharma9680]

actually we take the signs - positive or negative , by cartesian plane and in the cartesian plane - for the downward direction we take minus sign as we have learnt in the chapter 3 of maths -coordinate geometry

[@Vijay-ip1rg]

Sir in question 3 answer of weight of moon will be 16.33333........

[@sudeshbeniwal9116]

16.67N

[@nishantverma4015]

P- phosphorus H- hydrogen Y- Yttrium S- sulphure I- iodine C-Carbon S-. Sodium

[@roushanraj876]

C- Carbon H - Hudry E - M- I - iodine S- sulphur T - R- Y-

[@pubggamer1026]

Wow 😂😂 Chemistry in physics

[@nishantverma4015]

@@roushanraj876 C C- carbon H- hydrogen E-=mc^2 M- Molecul I- iodine S- sulphure T-titanium R- Rutherfordium Y- Yttrium

[@manshusingh42]

Physics wallah will die after seeing this😂

[@anshagrawal7209]

It was a nice lecture it really help me a lot thanku sir

[@NR_PRATYUSH]

Sir you are my favourite teacher on KZbin ❤️

[@jayeshbansal6718]

Sir in ques.7 total distance covered by the stone will be 160m ....as it returns to the ground also.

[@pritamraj6957]

Yes I also want to say that only

[@Vilayamyadavneet]

Yes s=160m

[@PencilDragger2828]

@@Vilayamyadavneet no because , in the question it is not mentioned that the stone is falling down again

[@amanraj00000]

52:00 sir it should be 6.7 only instead of 6.6..and sir for me the answer is under root 13.4

[@Sunshine9p]

Yeah me too ..... At first I thought I was going wrong :P

[@amanraj00000]

@@Sunshine9p ❤️❤️

[@ADDY-Aditya]

28:40 Distance= 80m Displacement=0m Total distance= 80+80 = 160m Thanks, if this help u please like Please 🥺🥺🥺🥺🥺

[@GamingPro-ly9mg]

Its wrong .. in the question it is not mentioned that stone is returning back

[@ishanmishra786]

@@GamingPro-ly9mg Abe saale jab stone upar jayega toh return nahi hoga kya pagal😐😆

[@Medicoaradhya]

46:07 it was hilarious 😂😂😂

[@divyanshdwivedi-r7h]

you make my physics easy rakhsak sir and whole team of physics wallah thank you so much 👍👍❤❤

[@PANKAJKUMAR-de4fh]

13:46 Sir the answer should be 14 m because if acceleration is not mentioned 10 m/s in the question so we have to take the acceleration 9.8m/s(gravitational force) so the answer would be 14 😊😊

[@sureshdubey4813]

😂😂Kal Jiski Jiski bhi exam ho😂😂, aap sabhi ko {BEST OF LUCK} for tomorrow's exam

[@Haryana94949]

Thanks bhai💕😂

[@rptcreation892]

Rakshak sir Op 🔥🔥🔥 No words for this type of amazing explanation ❤❤❤ What a legendary teacher Rakshak sir is !!! ❤❤❤

[@DhirajChauhan-r9l]

Sir ,7 que. Net displa will 0,and total distance will 160m

[@deepaksaini7471]

28:43 displacement =0 and total distance =160

[@paramjitkaur1468]

Yes right

[@paramjitkaur1468]

@Technoblade rest in peace how wrong???

[@shaoibalam1671]

brilliant explanation, evrywords are understandbale , THANK YOU SIR FOR MAKING PHYSICS A FUN

[@Vivek12890]

Your words no understanbale

[@namitakumaripanigrahy8879]

@@Vivek12890 apana kam khud karne ka😂

[@preetijain759]

Sir i think that in question no 7 the total distance is 160 m and displacement is 0

[@Karan1M50]

Any one 2024 😂

[@rajesh_171]

Yes

[@jeevansikdar3584]

Yes 😂

[@saswatisar5203]

Ya

[@g.kwithkhan252]

Ha bhai😂

[@DeepakRai-zi7nu]

Bhai tara sub to bahot ha 😮😮

[@manitakumari9035]

Thank you so much sir aapke uja se mere exam bhaut achha Gaya 🥰

[@umangharsh4811]

last video's 2nd challenge question at (49:08), sir if motion is downward than displacement(s) should be negative(-1)but you have taken positive . so that is making me confuse , because in last video you told us that displacement is vector that's why in downward motion we take it negative. THAT'S all from my side . you are the best teacher and sir please clear my doubt. At last THANK YOU Sir for teaching us.

[@pschycologylover]

sir the net displacement is 0 because the stone will come back to the initial point, and the distance will be 80 multiply by 2 which is 160.

[@Nilesh__yadav7]

My answer is also same

[@mahendrasingh8141]

Sir , in 7th numerical you have told net displacement is same as distance that is 80m but displacement should be 0m bcz stone returns to its final position

[@omkarsingh979]

Yes same here

[@khushboochoudhary8937]

g should be taken in positive when body is falling in downward direction

[@Its.Viraj....]

Yes

[@A_SA818]

Sir , plzz make work and energy CHAP tomorrow is my exam

[@shivkhatri8415]

Thnx lecture fourth ❤️👍🏻👍🏻👍🏻👍🏻

[@ayushiisingh02]

In qno.7 displacement is zero beacuse the stone will come back to their initial point and the total distance covered be 80+80 = 160 metre

[@madhudubey9705]

Q3. the weight of an object on moon having mass of 10 kg is 16.33N but, why have we not taken it negative ?👇🏻 [ it should be -16.33N ]

[@chandrahas272]

5:50 Sir, *g* taken as positive when objects goes downwards. Because Object Is Displacing in the same direction where Force Was Taking Place.

[@yatharthbisht5295]

44:54 Q.9 (iii) ans. should be near to 4.9m (bcz I have taken g = 9.8m/s²) Because after 4s time will be 1s and u=0m/s

[@lively_xd2593]

Wo top se distance hai sir ka bottom se se distance hai

[@lively_xd2593]

44.1-4.9 kar de 39.4 near to 40

[@NANDRIS_AMOUS]

Thank you sir for your determination to do so much for us

[@ANSHUKUMAR-t6k4x]

sir your teaching style is different from other teachers who taught me. now my physics is good enough only by you RAKSHAK SIR 🙂🙂

[@cousincrew4831]

Voh sab toh thik hai bhai pr tu yeh fake emoji kyu bhej rha hai ??

[@ajayagarwal1469]

Sir in ques no.7 net displacement will be 0 and net distance will be 160 ...

[@amanraj00000]

28:36 sir but total distance should be 160m bcz sir if stone goes up then it also comes to the earth surface...therefore the total distance should be 80 + 80 :- 160m

[@rajivks7966]

true

[@vikasjaiswal5473]

Are bro question me ye kaha bola hai ki stone wapas ground pe aaya hai.. Agr stone wapas ground pe aata tb distance 80m + 80m = 160m hota. Read question clearly

[@rajivks7966]

Arrey bhai question mein likha hain find the total distance matlab 80+80=160m

[@vikasjaiswal5473]

@@rajivks7966 ha total distance likha h but ye kaha likha h ki "Stone returns to ground" Thoda socho bhai. Question aise hi hote h confused krne ke liye.

[@toaa2301]

@@vikasjaiswal5473 bro are you serious total mtlb upper se niche ana tak hota hai aur object return ayega kyu nahi uski inti velocity nahi hai ki woh troposphere ko bhi cross karle

[@MRGENIUS22]

23:44 sir Mera time 9.8sec Aya tha kyuki Maine -10m/s acceleration due to gravity liya tha . ❤❤

[@sejalgupta6572]

if it falls downwards, won't it be positive?? Because gravity is towards the ground and i have already been following this phenomenon only even it's written in +ve in the book too, pls clear my doubt.

[@sudhirkumarsharma9680]

actually we take the signs - positive or negative , by cartesian plane and in the cartesian plane - for the downward direction we take minus sign as we have learnt in the chapter 3 of maths -coordinate geometry

[@sudhirkumarsharma9680]

please tell me if it was helpful for you

[@krishnaagrawal4552]

See all the lectures in 2x speed it will be time saver

[@bhatishrat7459]

🤣🤣bahi kch b smj nii aaraha

[@abdullahsidd8456]

Sir is very different from before 3 years hena

[@danishmushtaqdraboo5729]

I wish if you were in my school today I would be far ahead in physics

[@Anaya-Bhardwaj6095]

Acha online se hi ho jao offline nhi toh online hi shi bta abhi toh 10th me honge😜😂

[@danishmushtaqdraboo5729]

@@Anaya-Bhardwaj6095 ap kon?

[@SuprexGamingBroOfficial]

28:52 so epic 😝😂😂🤣

[@Ks_PC_07]

28:40 after the calculation we get, Total height reached by the particle = 80m. Hence, Dist = 80*2 = 160m and the net disp will be 0 becsuse stone returned to the initial point of the action. So, highlight this comment to avoid such mistakes like this.

[@letsstudy699]

I think everyone has having confusion that why sir is taking g in negative so it's because we write signs according to Cartesian plane.

[@sunitaduhan]

Bhagwan sabh ko pass kra :)🙏

[@Forever_bt]

Bhagwan nhi teacher sabko pass Karen😂😂

[@samiksha_7s]

28:46 sir net displacement = 0 {as it asked net displacement so upward displacement + downward displacement = 0} and total displacement = 160m { as it asked total distance so upward distance + downward distance = 160m }

[@deepalikale1684]

Ya net displacement should be zero

[@kabitaranimallik8310]

Hm toh ye wapas thodi aa raha hai

[@jaya5250]

I am attempting your lecture first time and really I understand this chapter very clearly 😊😊👌 really an amazing lecture thank you very much

[@ultrasong8284]

First of all this is last lecture

[@jaya5250]

@@ultrasong8284 I know I need only numerical

[@drawiteasy4458]

*attempting*

[@proud333yt]

@@drawiteasy4458 bhai 6 class kids attending 9 class lectures and they dont know english lol

[@ajayjain4673]

Sir right now for the practice we can take the value of g10 inthat moon and Earth que.

[@hemagupta4225]

Thank you sir by this video I am able to understand physcis

[@savitagour7234]

Q NO. 7 M net displacement (0) Hai sir

[@Cragygirls]

Why

[@sibasishpurohit]

Sir in question number 6 why the value of final velocity (v) is positive according to your sign convention it's value is negative since it is also a vector quantity and direction is downward

[@anshikayadav296]

After solving equation in which you have put -a and -s your answer become atuomaticaly +v

[@Gamerfit53]

Sir g will be -10 when object is Thrown upward and when coming down it will be 10

[@iqbalbadami3649]

Don't fear😱 when physics wallah is here 👍👍

[@anjaiahkandula7538]

Raksakh sir talent is infinite. 👍👍👍👍

[@ghahmad4325]

Op

[@kapilvyas9911]

Limited

[@laddugopal8083]

Sir mera ek doubt hai ki jab ham weight find out krte hai , tab 'g' ko 10 m/s² kyu lete hai , -10 m/s² kyu nhi lete.

[@ayesha6568]

I HAVE A DOUBT IN QUESTION NUMBER 2 THAT IF WE TAKE g = 9.8 m/s so answer of initial velocity coming is 14 but sir your answer coming is 10 root 2 m 🤔🤔🤔🤔

[@prt4691]

10✓2= 10×(1.41)= 14.1 Kyuki ✓2 is around 1.4 Close hi aayega agar sir ne g= 10 liya hai Toh unka answer toda sa alag aayega lekin ekdum close aayega jaise yaha 14.1 aa gaya Hope this helps 👍

[@ayesha6568]

@@prt4691 THANKS 😊 I WAS KNOWN ABOUT THIS BUT I WAS CONFUSED A LITTLE BIT . THANKS FOR HELPING..

[@akyt8004]

9:43 sir average speed ka formula 2 tarike se hai 1:- TOTAL DISTANCE / TOTAL TIME 2:- V+U/2 ♥️🥰

[@maihudon]

Bro vo average velocity ka formula he v+u/2

[@akyt8004]

ans same aa rha hai v+u/2 5+0/2=2.5 And by sir method total distance /total time 1.25/0.5=2.5

[@akyt8004]

@@maihudon reply and explain me if i am wrong 😊

[@Shan100k]

@@akyt8004 wrong 😱

[@Mouteebking]

Thanks sir for teaching us you are great teacher I found this chapter difficult but made it easy

[@akritikesarwani7011]

Sir but thoda confusing ho gya ki kaha pr (9.8) or kahan pr (10)?

[@preetijain759]

Yes it's so confusing 😞😞

[@ayush99.8]

School wali madam be like:Sir aapko mujhse problem kya hai 😂😂😂

[@madhudubey9705]

In case of velocity ,negative sign represents downward direction (with respect to cartesian plane) while in acceleration, negative sign represents retardation (a force acting opposite in the direction of moving object)

[@madhudubey9705]

isn't it?

[@screen-marvel-us1424]

28:54 op🤣🤣🤣just died because of laughing, and then took birth again to complete this video.lmao 😂😍

[@aryan5910]

Kamedy!

[@ishikaburnwal3470]

PW's intro is much better than any gamer or any other youtuber. This produces another type of feeling 😂

[@tejassharma6040]

Fr😂

[@txt_tejas]

WHAT ABOUT CARI BAHI

[@ishikaburnwal3470]

@@txt_tejas dekho bhai teacher desh badal skta hai aur wo bs time paas krwa skta hai

[@mayank_liftzz]

​@ishikaburnwal3470😂😂aabe bcche

[@craftieU]

15:49 sir, (Weight on Moon) W = 16.3N

[@srujanadiga9428]

Sir in 8th question for both cases why you took acceleration as -10

[@sudhirkumarsharma9680]

actually we take the signs - positive or negative , by cartesian plane and in the cartesian plane - for the downward direction we take minus sign as we have learnt in the chapter 3 of maths -coordinate geometry

[@fizaali4747]

This is my fixed tchr to study pyschis 💎

[@KrishanKumar-sq9oe]

Tu pahale English seekh

[@niravsmagicalstudio1670]

Happy Diwali PW sir

[@bhoomikakulkarni3667]

sir isn't the first formula : M1 x M2/ d2?

[@ayushjadhav3138]

F=G M₁ × M₂/d²