Mam isme jo 7 or 8 order ka group h Usme common elements bi to ho sakte h
@akd26438 Жыл бұрын
Mam Kya sirf identity common ha or koi elements common nahi Ho sakta.
@latestfactsfile3900 Жыл бұрын
Very nice explanation mam❤
@05anjamantabssum532 жыл бұрын
Thank you❤🌹 so much mam
@NAZMULHASAN-nl9ev7 ай бұрын
Mam,why are you take such as n1,n7 .which method ,please explain
@recipe_routine3 жыл бұрын
Thank you mam for this presentation, it is so helpful.
@dr.upasanapahujataneja17073 жыл бұрын
Many Thanks....please refer to other Videos of modern Algebra and real analysis...
@anikumari44232 ай бұрын
Thanks di
@aadityakant73292 жыл бұрын
Ma'am if last condition was hold then will what??
@04arunjeet222 жыл бұрын
Mam pls make a video on group of order 30 . What will be the cases?
@BlacksheepY-l8q2 жыл бұрын
This prove fails at 7:49 here the number of “2-SSG” is 7 and number of elements in every “2-SSG” is 8, we know nothing about these subgroups of order 8 and you just assumes they are all isomorphic to cyclic group of order 8 and trivially intersects. THIS IS SIMPLY FALSE. The same problem arises multiple times in your videos, and you have refused to address this issue.
@dr.upasanapahujataneja17072 жыл бұрын
Will definitely look into this and will revert asap
@amansparsh72292 жыл бұрын
Mam, here in 2-SSG order is 2 1 is identity common in all H1,.....H7 and rest contains one more element in total 1+7 = 8 (you took 48 here) And 7 SSG is 48 In total giving 56 which divides 56 Am I right ????
@saumyagupta7192 Жыл бұрын
The order of 2-ssg is not 2. It is 2^3 = 8
@deepakgautam70622 жыл бұрын
Thanks mam 🙏🙏🙏
@dr.upasanapahujataneja17072 жыл бұрын
Thank you
@rohitprasad5333 Жыл бұрын
Thank You so much ma'am!!😭
@dr.upasanapahujataneja1707 Жыл бұрын
You are so welcome! Keep watching
@sambhusharma14363 жыл бұрын
Ma'am why there is only identity element common between two p-ssg?
@dr.upasanapahujataneja17073 жыл бұрын
Thanks for asking the question😊 Ans- As every group has Only one identity element and these are Subgroups of this group so the identity element is common.
@BlacksheepY-l8q2 жыл бұрын
@@dr.upasanapahujataneja1707 the question here is not why identity is a common element between two p-ssg, but the “only common”.
@BlacksheepY-l8q2 жыл бұрын
Because she made a mistake on assuming all “p-SSG” has prime order, forgetting the p here indicates the group has order of a power of p, not that group has prime order.
@kartiklifestyle Жыл бұрын
Thank you mam
@lapotela310811 ай бұрын
thanks mam
@dr.upasanapahujataneja170711 ай бұрын
Most welcome 😊
@karma_returns4632 жыл бұрын
Mam in case of group of order 30, n2 = 1,3,5,15 n3 = 1,10 n5= 1,6 Now how to proceed further? What will be the different cases?
@radharanibhakta87353 жыл бұрын
Thank you so much ma'am
@dr.upasanapahujataneja17073 жыл бұрын
Thank you 😊
@radharanibhakta87353 жыл бұрын
@@dr.upasanapahujataneja1707 Ma'am is it possible to personally contact with you ??
@dr.upasanapahujataneja17073 жыл бұрын
Mail me at upasna.pahuja@gmail.com
@radharanibhakta87353 жыл бұрын
@@dr.upasanapahujataneja1707 okk thank you ma'am
@abijith88293 жыл бұрын
Very usefull
@dr.upasanapahujataneja17073 жыл бұрын
Thank you...😊
@RideR-SAM653 жыл бұрын
Mam there can b more elements common in two Sylow p subgroups...why are we taking only identity element in intersection?
@dr.upasanapahujataneja17073 жыл бұрын
They Will not have any element common other than identity as they are groups of prime order...
@BlacksheepY-l8q2 жыл бұрын
@@dr.upasanapahujataneja1707 by this you are claiming 8 is a prime number, again, “2-SSG” is a group with order being powers of 2, in this video every 2-SSG has order 8, by no ways you can restrict it to just a cyclic subgroup or order 8.
@arpitamishra6562 жыл бұрын
Please make a video on "group of order 120 is not simple"