The solution for 6(iii) is incorrect. I provide 2 classes of examples to why 288 is incorrect. 1. Numbers such as 3468 (whose individual numbers do not add up to a multiple of 6) are not subtracted from 360 in both the VJC and your proposed solution. 2. On the other hand, numbers such as 3465 which is not divisible by 6 are subtracted from 360. You have inadvertently included such classes of (odd) numbers in the subtraction by taking 4!. The correct answer is 60. But I cannot provide a systematic solution for this question since I brute-forced my way to the solution by systematically checking numbers from 3456 to 8765. Will provide an update if I manage to figure one out. But I agree - this question is quite unfair to students in an examination setting.
@AchevasTV2 ай бұрын
Thanks for sharing 😊
@gsaray1232 ай бұрын
@timothylim8989, I disagree with you. VJC's and Achevas' answer is correct. You have not read the question accurately. 'no digit may appear more than once in the number and the sum of all the digits in the number is not divisible by six.' - note 'the sum of all the digits in the number is not divisible by six', not your interpretation the number is not divisible by six. This means that 3465 and 3456 are divisible by six.
@timothylim89892 ай бұрын
@@gsaray123 My bad. Yes you are right that I misread the question. Thank you for pointing it out.