Hardy-Weinberg Equation

[@SherlyElise]

Given Info: 12% red hair (homozygous recessive or q^2) What we need: % for non-red hair (homozygous Dominant or p^2) Step 1. Solve for q^2 q^2= 12% or (0.12) √(q^2) = √(0.12) (radical sign on both sides to get rid of the square) q= 0.35 Step 2. Solve for p Equation= p+q=1 So if solving for p (p= 1-q) p= 1- (0.35) p= 0.65 Step 3. Solve for p^2 (0.65)^2 = 0.42 Step 4. Change it to percent 0.42 x 100 = 42% -Thank you Mr. Anderson for all of your videos!

[@VedavyasMunugoor]

Velcro, the final part of the problem specifies homozygous non-red.

[@leahsmo928]

VelcroZGaming g

[@mummiedanser1609]

its actually 43% due to rounding

[@mbe0102]

@@mummiedanser1609 yup its 0.427 so its 0.43 = 43%

[@oliverpdcook]

@@mummiedanser1609 yeh I got 42.7 so I agree

[@the_jacked_doc]

I watched your videos getting into medical school and now I'm in Medical school and still watch your videos on certain topics. Crazy how some medical school professors can't articulate a concept like the way you can.

[@lukashumber582]

hi mr bozeman it is currently 2023 and im taking ap bio in school with my exam in 3 days. I had no idea how to do the hardy weinberg equation because i was trying to solve it as an equation and you've really helped clear it up with me. not only that you've helped me for the majority of the year and im so grateful for that. its amazing that these videos with your concise and simple explanations can still be relevant 9 years later. keep it up!

[@elizabethfunbun94]

not ready for that test tomorrow...

[@cabbageman6309]

never ready

[@buttermilk_pie]

Two years later, how'd you do?

[@omarawwad1890]

Wil McDowell ayyy

[@kaiyo_o6477]

Elizabeth German same...

[@andyvelez3822]

same...

[@christinalange3280]

He's like the Biology version on John Green.

[@TrevorSchmahl]

+Christina McKay Wouldn't the biology version of John Green..... Be Hank Green? lol

[@christinalange3280]

Trevor Schmahl True XD

[@vaishnavimatti2508]

Hank is dope🤩but so is Mr Anderson

[@nadakhalil9938]

No, Better !

[@Whoisthatguy906]

Hank is bank brah

[@thomasratliff9278]

Thank you again Sir. I should thank you for every time I learn from your lesson. I will begin to be more respectful from here forward.

[@WBCStudio.]

Thank you professor, you have contributed to my understanding of this complicated equation. For the last problem you have us, q=✓.12=0.346 p= 0.654. Since p2+(2)qp+q= 1, 2pq= 0.452. This is the percentage of the population that are heterozygous for non-red hair. The percentage of the population that is homozygous for non-red hair is 43%

[@nathanielanderson8753]

Mr Anderson, are you my dad?

[@Bozemanscience1]

+Nathaniel Anderson no

[@siribrown9690]

+Nathaniel Anderson Sucks for you. He's an intelligent dude.

[@andersaubry]

+Bozeman Science maybe you just have similar fenotypes?

[@ummewaseem5983]

+Nathaniel Anderson haha this made me smile :)

[@kalebg1706]

YES

[@aajuicygirl]

You are the reason I'm passing AP bio

[@Sana-jb5zu]

morning of my exam, thank you!! you make this so simple and easy to understand now im not going to lose any marks if it comes up!

[@heyashleyestrada]

I happen to have an exam including this material tomorrow. I wanted to leisurely review via KZbin and found this right on my home! What a fun coincidence! Thanks for the upload (:

[@sophi3love]

I'm doing hardy Weinberg in school at the moment and thanks so much for uploading this! You are so inspirational to me :)

[@transmutation-alchemist5802]

you my friend just restored my hopes in learning genetics.

[@Kaiju-j2f]

I'm can almost for certain say that the answer to the question he last gave is approximately 42%.

[@nathanielanderson8753]

Seriously. We look alike, and have glasses, and have the same last name

[@murodmahkamov359]

He is your dad!! ;))

[@annamarie6712]

You explained it so well, it sounds so simple when you explain it!!! Thank you

[@CowsClub]

A hardy weinberg question came up in this years ocr biology paper, and this video definitely helped. Thank you Bozeman!

[@LearnsubmissionsHere]

I am going to try this equations in different areas to see how well it holds true in other fields.

[@jillwild23]

As always, great organization and excellent explanation as to the "whys"

[@taladiv3415]

Cooool analogy with the socks for the masking of the recessive allele by the dominant allele!

[@gayatriduhan9873]

i was looking for it on bozeman for so many days and finally it is there thank you so much sr

[@79laksiri]

Thanks Sir!!!!! Tried a lot to understand this equation until i found this video. SIMPLE but GREAT!!!

[@vincentlenart1697]

Thank you! This was extremely helpful! It seems so easy now. Not sure why I was having trouble.

[@melissamiliam412]

your videos are a blessing for my biolab homework

[@cydney5049]

I'm in grad school and this explains it better and more quickly than the textbook.

[@genesislayne3322]

got 42%.... would that be correct?

[@genesislayne3322]

+Edris Zalmai ok cool :)

[@buttermilk_pie]

Thanks! The sock explanation was very creative.

[@Candyicsma]

He never said I hope that is helpful

[@SERGE_Tech]

This Time he hopes its destructive.

[@mourningmelody]

may the science gods bless you, bc u just saved my bio grade

[@rakshanabala5062]

I got everything... but just wanted to know what if we are considering genes having more than 2 alleles like the I gene that codes for the sugar polymer on the surface of the RBC's which has 3 alleles ?? (ABO blood grouping) In that case how does this principle work ? Someone help me with it.. i am just a beginner ....

[@thehighhost2084]

It is easy to calculate allelic frequencis with homozygous. But, how do you calculate allelic frequencis from heterozygus?

[@dayannaortiz2257]

Thank you so much for helping me understand this! Starting AP Biology tomorrow and natural selection is the first topic we're learning and now i feel a lot more comfortable and ready for tomorrow and the year, thank you!!!

[@marintiamayolanava4019]

Thank you! You explain very well.

[@1mlevi1]

Bozeman Science!! You rock. I wish I was in your class

[@DCUPtoejuice]

it would be good to mention that the p2 and q2 terms are derived from the likelihood of two of those alleles both being present in an individual given their frequency in the gene pool

[@zipporahdianeesmeralda9492]

The Greatest Teacher for Me❤ Seriously, you're the best❤‍🔥

[@mredoward9858]

Can someone tell me how to Calculate p , and how it became 86 in the example

[@iamlearning100]

simple and brilliant really appreciate your work

[@kevinschmitt3113]

q^2=.12 q=.346 p=1-q=1-.346=.654 2pq=2(.346).654)=.452=45.2% 43% is a little bit too much rounding in my opinion.

[@u.s.aamerica2695]

Kevin Schmitt this is what i got

[@icecream6741]

that's incorrect. he is asking for "HOMOzygous", so what you're supposed to do is p^2 the p --> (0.654)^2 = 0.427 = 42.7%

[@spacesax1]

@@icecream6741 You're absolutely right.

[@u.s.aamerica2695]

god bless you , explained this much simpler than my teacher

[@irinakhokhryakova6825]

Thank you, this made things so much clearer!

[@poseidon878]

Mr.Anderson, is the answer to the problem 65%?

[@alicesams2851]

When would you multiply by 2? My teacher mentioned how if there is, for example, an individual who is recessive, then you multiple that gene by 2 and I'm getting confused with why you would square q instead?

[@mohamadhamad92]

that was really precise and concise .. Thank you so much

[@Omegasub101]

Mr Andersen, you are God.

[@hatz6039]

Omegasub101 god doesn't exist my brother Think logical

[@woodwoodchuck546]

Thank you so much for your videos!

[@lauraromdeussen864]

I cannot be the only one going "exactly what size shoe ARE you b/c those socks are HUGE!!!" And also, this was a beautifully simple way to explain a concept I was not understanding.

[@isabellevonlockner1186]

Bless your soul this helped me so much!

[@carolinamendana2477]

you teach better than my fiu professors! wouldn't have passed without these videos! please do not ever stop T_T

[@DrReginaldFinleySr]

Carolina Mendana You have a professor that actually teaches? :-)

[@itsMizaa]

Thank you for a well and easy explanation. 😊

[@frkurfamsoad]

really good video for explaining the basics thanks

[@Chris-nl3pj]

Thanks a lot... Very good explanation! And also thx for talking slowly thats helpfull for german people^^

[@rakshagupta9048]

Thank you so much for the understanding of concept. I am stuck in this question Given gene A at frequency 0.2 and gene B at frequency 0.6, find the equlibrium frequencies of gametes AB, Ab, aB and ab. Plese explain this question

[@sweetlife3623]

i love your intro soundtrack

[@monarchgaming9360]

what if I put a black sock in a red sock? is red still recessive

[@ForzaWiz11]

No

[@ysminlv]

Thank you! The video was really helpful!

[@jemima6458]

Thank you for explaining! That was great, esp. the sock analogy! :)

[@ezzeldin3714]

If you know what an allele is and what genes are, skip to 5:07

[@edwardmitchell6002]

The question is how many are HOMOZYGOUS for NON-Red Hair...not dominant or recessive. Remember red hair is a recessive trait so although the 2(P)(q) group will carry the trait red hair will not be expressed, but they are HETEROZYGOUS. So, the only HOMOZYGOUS NON-RED HAIR group is P^2 the answer is .427 or 42.7% or rounded off to 43%

[@TheSilvermoondancer]

Can someone help me solve this problem?In a population of 500 individuals, 200 are genotype AA, 125 are genotype Aa, and 175 are genotype aa. What is the frequency of the dominant allele A? What is the frequency of the recessive allele a? Given these allele frequencies, what does Hardy-Weinberg predict will be the frequencies of each of the three genotypes? Is the population in Hardy-Weinberg equilibrium? Fully explain your answer.

[@maydayramsden1205]

+TheSilvermoondancer p^2 = 200/500 = 0.4 (AA) 2pq = 125/500 = 0.25 (Aa) q^2 = 175/500 = 0.35 (aa) 0.4 + 0.125 = 0.525 (A) And sorry, I don't know if it's in Hardy-Weinberg equilibrium :/

[@jakewoodruff51]

how would you know whether the trait is recessive or dominant. For example, how did you know that the red hair trait is recessive.

[@briangoldstein3007]

it told you in the previous question red was recessive

[@hailiejadeable]

thank you. it was very helpful

[@szym0n986]

You saved my life!

[@DA-sj2gw]

The Hardy-Weinerg law makes it possible to predict the allele frquencies (for a locus in a population) based on the observed genotype frequencies. (True or False)?

[@possible_world_productions2789]

You have confused me. I am unsure of your question because I don't know. I would think FALSE because not all locus have the same genes or appearance in certain area.

[@KiLLerBeast1O11]

im confused, how did u get .86? please help

[@mindcraftful]

cris casicana How did he get the .86

[@Stockcryptocritique]

I love Boseman teaching.

[@Mrssunshine5991]

thanks !! C: i love these videos so much

[@nanszy]

Thank you! That was very helpful!

[@zoyaharoon9252]

thank you soooooooo much.....keep it up.....it was really very helpful

[@clayclay136]

So what is the answer to the last one 43 percent?

[@waheedkakar6741]

hey; mr anderson i solved out the answer can u plz tell me whether it's right or wrong the percentage for homozygous non red hair is 43.56.....and i found ur tutors very helpfulll thankssss

[@yassinessam3945]

Thank you so much! this was so helpful ... GREAT teacher as always .. :))))))

[@zxsdwe170]

2% =0.02 and square root of that is ~=0.14 Using the equation 1-0.14 = 0.86 .:2pq= 2x0.86x0.14~=0.24 so he is right people not 42 or what u r saying there is jus little mistake of the 2% bit= 0.02 not 0.2

[@johnbuttler915]

What if they give you the heterozygous number?

[@AFCAdutchie]

I love ur videos man

[@amanihur5734]

q^2=0.12, q=0.35, 1-0.35=0.65, p=0.65, p^2= 0.4225, 42.25%

[@YaKnowMe29]

What video software do you use?

[@janecrus9484]

Pls. Help me with this problem. there are 300 organisms who carry the homozygous dominant gene, 200 organisms who carry the heterozygous gene and 250 organisms who carry the homozygous recessive gene but this data does nit obey the Hardy-Weinberg equilibrium, you should add the same number of species who carry the homozygous dominant gene, organisms who carry the heterozygous gene and organisms who carry the homozygous recessive gene so that the population will be double the original number of individuals. in order to be in the Hardy-Weinberg equilibrium, How much organisms for every genotype you should add and what will be the resulting allele frequencies?

[@lelabb4110]

Phenotype whats dominant?

[@lokeshkoomarstyagee6742]

sir u are crazily awesome the answer is 44%

[@TheJame2383]

holy --- now I know some sh*t , thank doc this really help me.

[@kerpelwaston3223]

can someone write out the answer of the problem at the end of the video for me?

[@kingkisser958]

q2=.12 for 12% in decimal form therefore q is the square root of .12=.3 p=.7 because 1-.3=.7 so follow the equation p2+2pq+q2=1 2(.3)(.7)=.42 or 42% Hope this helps! :)

[@namimiyagi857]

Thank you so much that's so helpful

[@SmithCraftCo]

Thank you so mush Mr. Anderson! My teacher has been confusing me so much with this and she recommended me here! I got 65% homozygous for non-red hair!

[@EvangelistIfunanya]

I got the same answer but I don’t know why everyone is saying 42%.

[@zaka6933]

But how do you know if the 12% red hair is Dominant or recessive in the first place?

[@nandinivyas4434]

he was using the red as a recessive trait so we should assume red is recessive

[@demolidor0518]

Brazilian here, good class

[@alexandrebaraka1]

i'm also brazilian and i must say mr. andersen is an amazing teacher. this class is top notch

[@maeakins6132]

Since the last question asked for the homozygous dominant, the right answer should be 65% I did it twice and arrived at this answer

[@dabj9546]

You forgot to square p. So the answer is 42.7%. Probably nothing you could care less about three years later just wanted to mention it.

[@nurulainishaari2419]

really like this video bcoz it help me alot

[@GunMonkey696]

42%?

[@EinarKrog]

42.7%, rounds up to 43%

[@카리나-b3g]

My book isn't this awesome, I finally understood this topic, thank you so much!!! (I'm from Mexico and I'm 16 years old so.. my english isn't quite good, sorry)

[@morotigyan8353]

Very awesome video

[@technoshindo]

Daddy Anderson saves the day again with his sexy phenotype

[@robinhorst706]

Mr Anderson, holy crap, are you the one?

[@naraharipothamsetty9084]

Thank you for saving my biology grade, oh father of my bio grade

[@bahahos7426]

Thank you very much, the answer of the last quation 0,44= 44.% :D

[@firedazzerintern2260]

Mr Anderson can you message me the right answer please. Thank you. I just want to know if I got it right. Thanks a bunch! :)

[@minilupe3]

right awnser is .69

[@firedazzerintern2260]

thanks!

[@MrCinnamonTiny]

Don't listen to him. . . It's 42.25%, or just 42% if you round it. This is the same answer that was repeated further down as well.

[@firedazzerintern2260]

oh...I see..okay

[@minilupe3]

why are you lying to him silly boi its obviosly .69 dont lie to throw him off he needs to do good on his test

[@zen8877]

How do we know red hair is recessive ???

[@alldagreen6909]

So why is the red gene recessive to the non red gene?

[@gopaljha1484]

Allda Green if in the whole world only 2 % contain red hair then it must be recessive

[@alldagreen6909]

yes, good point :). But still, my question is why is that the red hair gene is not expressed in the remaining (most of the) population and thus making it recessive?

[@alejandraceledon4547]

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