Harvard University Admission Interview Tricks || Find the Value of a+b+c=🖋️✍️

[@arvindkulkarni6580]

Very nice teaching method

[@harshpathak2359]

Very well explained

[@ManojkantSamal]

^=read as to the powe5 *=read as square root As per question a(b+c)=300...eqn1 b(a+c)=400...eqn2 C(a+b)=500...eqn3 Eqn1 -eqn2 ab+ac-ab-bc=300-400=-100 ac-bc=-100 C(a-b)=-100.....eqn4 Eqn3 ÷eqn4 a+b=-5(a-b) a+5a=5b-b 6a=4b b=3a/2.....eqn5 Eqn2-eqn3 ab+bc-ac--bc=400-500=-100 a(b-c)=-100.....eqn6 Eqn1/eqn6 b+c=-3(b-c) 4b=2c C=2b C=2(3a/2)=3a...... Eqn7 Now eqn1 a(b+c)=300 a{(3a/2)+3a} a(9a/2)=309 9a^2=600 a^2=600/9=200/3 a=*(200/3)=(10.*2)/*3 =(10.*6)/3 b=3a/2 =5.*6 C=3a=10.*6 Hence a=(10.*6)/3, b=5.*6,c=10.*6

[@ask4jubad]

Although, I didn't verify the final answer(s), this makes much more sense and logically consistent. Thanks for sharing.

[@54sheetalpandey49]

Lovely

[@maxvangulik1988]

a(b+c)=300 b(a+c)=400 c(a+b)=500 ab=100 ac=200 bc=300 c=2b=3a c^2=2bc=600 b^2=bc/2=150 a^2=200/3 (a+b+c)^2=a^2+b^2+c^2+2(ab+ac+bc) =200/3+150+600+2(100+200+300) =6050/3 |a+b+c|=55sqrt(2/3) since we only know terms of order 2, it's entirely possible that a, b, and c are all negative.

[@DarshChouhan-r6g]

GOOD teaching

[@kateknowles8055]

Thank you, Mamta maam ab +bc = 400 ab + bc +ac = 400 +ac = 300 + bc = 500+ ab 100 = bc-ac 500 = bc+ac 2bc = 600 bc = 300 ab = 100 ac = 200 a/c = 1/3 b/c = 1/2 a:b:c = 2:3:6 let a+b+c = 2k +3k +6k = 11k a.a : b.b : c.c = 4:9: 36 or a.a = 4k.k b.b = 9k.k c.c = 36 k.k (121-(4+9+36) )k.k = 1200 , because this is ab+bc + ab+ ac +ac+bc) k.k = 1200 /(121-49) = 1200/72 = 100/6 = 50/3 k =+/- 5 root(6 )/3 a+b+c =( 55 root (6))/3 or ( - 55root(6))/3

[@dhananjaypandey6258]

Great 👍🏻

[@h.ppandeyh.ppandey2448]

Good 👍

[@BrijLalSahu-bb1lu]

🎉🎉 very nice video @MATHS TUTORIAL ( BL SAHU)

[@DipikaPandey-p6r]

Very nice

[@LaxmanKumar-yi4cv]

Too good

[@petterweinberg]

Lovely voice ❤

[@امیرقدرتیان]

I'm from Iran you are good teacher.thanks❤

[@امیرقدرتیان]

بسیار بسیار زیبا عالی عالی

[@KeshavKulkarni-x1w]

Perfect theorem

[@manojchaugule794]

❤❤❤❤

[@NithyaGhumare]

😊😊😊😊

[@harikishan1900]

❤❤

[@cristianquisbert6632]

Me parece que elevar el trinomio( a+b+c) al cuadrado es innecesario.

[@aruntiwari5714]

Good morning maam