Harvard University Admission Entrance Tricks | Radical Algebra Aptitude Test

[@joseeoliviero6078]

I understand the math as you do it. But I don't understand how you see ahead of time, what your substitutions will be, if that makes sense. Sense you don't explain what you are "thinking", I'm not mattering your secrets 😢

[@beekeeper-m5q]

Excellent explanation thank you sir

[@learncommunolizer]

You are welcome, Thank 🙏❤️🙏

[@ari345n]

It can be solved easily with binomial theorem

[@sgntsids]

6:14 niiiice

[@is2yoonah]

It was helpful. Thank you🎉

[@subhaskar1049]

Please see last calculation

[@NelsonMakabulus]

The answer is more complicated than the initial. It's not a simplification.

[@robertveith6383]

The directions should be: "Expand this expression and write it as A + Bsqrt(2), where A and B belong to the set of integers."

[@taopt4496]

Can i just seperate it into five ((√2)-5)^2

[@joseeoliviero6078]

Mastering

[@antonipeters2333]

That is, 3363 - 2378(2)^(1/2) = 3363 - 3362.99985... which is basically 0 (zero)

[@robertveith6383]

No, it is *not* "basically" zero. You're wrong. Delete your post.

[@antonipeters2333]

@@robertveith6383 Okay so it's 0.000148676..... . A really big number right? Essentially negligible, unless you're talking about atoms or electrons, right? So no I will not delete my post. Take a hike, pal.

[@봉치-z7c]

그냥 직접 계산하는게 더 빠름 ㅋㅋ

[@ВалентинГорелов-э6в]

Сначала возвести в квадрат будет 3 - 2 корней из 2, а потом всё возвести в пятую степень представив как квадрат помножить на куб быстрее и легко

[@MelindaToth-y8u]

X=9-7=36 Y=7 MY NAME:T MELINDA 1973 ❤❤2024 X 14❤❤

[@cabasantbab]

1 only

[@riyatmoko8241]

10

[@atchutharajugudivada2992]

A P explain

[@antonipeters2333]

When one works out the solution, the answer is ZERO.

[@robertveith6383]

No, it is *not.* You're wrong. Delete your post.

[@elchile336]

That's because √2 - 1 ≈ 1.141 - 1 ≈ 0.141, and 0.141¹⁰ = a very small number, about to be zero.