{680} Transformerless Power Supply Circuit, Capacitor Dropper Circuit

[@rogermagnus7303]

Thank you. I searched for months to find someone who could and would explain the design of a electronic circuit as you have.

[@HaseebElectronics]

it is my pleasure

[@Lami-cb7qo]

Cảm ơn bạn!

[@HaseebElectronics]

Thanks a lot for your valuable support 💕

[@N0G0MAIL]

Led current = V/R = 4V/330 ohms = 12mA. Maximum surge current will be V/R = 230V x 1.4 / 56 ohms = 5.75A which is good (1N4007 surge current is 30A). The 47uF capacitor will protect the zener diode and the led from surge current. The 47uF capacitor, the zener diode and the 330 ohms resistor will limit the led current, so the surge current will not reach the led. 47uF/0.2uF = 235, so the maximum inrush voltage on the zener diode will be around 230V x 1.4 / 235 = 1.3V, which is good, under 6.2V and the zener diode will be protected. (the 2 capacitors will react like a resistive divider).

[@HaseebElectronics]

perfect analysis special thanks and best regards

[@rogermagnus7303]

Thanks again! The bleeder and surge resistor calculations were great. I am building my project to provide a LED light to a microwave light.

[@Ianf1x]

Its been a while since I did any electronic projects but this brought me joy going through the design of this and seeing I haven't forgot everything I taught my self .

[@HarlavanisPanagiotis]

Wonderful video dear friend, have a happy Sunday 😊

[@kaleelurrahumanrahuman99]

Sir I'm from Sri Lanka that i watched your channel regularly it is very important topics for me also you started to explain in English it is Very useful for none Urdu people like me continue jazakallh khirah

[@Deshantha1996]

මේ විඩියෝ එකේ විනාඩි 16.02 තියන එකේ 6.2 v / ×0.636 කියෙනේ මොක්කද ඒ ඒකේ ආදේසය පැහැදිලි නෑනෙ. 6.2v ඒක පැහැදිලි අවුට්පුට් Dc වෝල්ට් එක. ප්‍රස්නේ තියෙන්නේ x 0.636 කියලා තියෙන්නේ ඒමොකේ ආදේසයද . උඩ ආදේසය C= i 🔼 T / 🔼 v ඒ සූත්‍රය සන්කේත මොක්කද C = කැපසිස්ටය කියලා දන්නව I = අමිපියර් කිය්න්න දන්නව ඒ සූතයේ 🔼 ත්‍රීකෝනේ වගේ තියන එක මොක්කද කියන්න දන්නෑ. පුලුවන් නම් කියලා දෙන්න

[@AbdulMomenZargar60]

Salaam Karne Ke Liya Hazir Ho Geya Hun Bhai Saab

[@HaseebElectronics]

wa alaikum salaam dear brother

[@muhammadishtiaq24]

Excellent job done keep sharing

[@t1d100]

Very excellent information! Thank you, Haseeb!

[@HaseebElectronics]

My pleasure

[@nasirzamanawan.3485]

Buht umdah 👍👍👍

[@ravisalunke4889]

thank you sir, you are a good teacher.

[@N0G0MAIL]

Excellent video, as always. Here if I don't use the bridge rectifier, only the zener diode, the led will work only half of the cicle, and the average led current will be 10mA = half of 20mA :)

[@HaseebElectronics]

if we don't use rectifier, then LED reverse voltage are only 5 volt in datasheet but in practical it can sustain only 20V reverse. although the current is limited by dropper, but it may lead to drive in reverse breakdown, in case that the line voltage are increased than the rated values for that reason we must use at least 1 diode to clip off the reverse peak. so that LED must be protected

[@N0G0MAIL]

You are right. In the absence of the bridge rectifier we can count on the zener diode to reduce the reverse led voltage to the 0.7V zener direct drop voltage.

[@W1RMD]

Thanks! Your explanations are amazing!

[@Elikaee]

Thank you so much; As always awsome!

[@vijayakumarkumar9190]

Very useful information sir thanks

[@HaseebElectronics]

it is my pleasure

[@kaizen1071]

Harika bilgiler için teşekkürler kardeşim. Allah cc seni ve sevdiklerini korusun .

[@shivshakti158]

Thank You Sir

[@uzmaimranvlogs1612]

Informative video bro

[@debashisroy4u]

Great analysis sir, love from India

[@pv.chalapathirao4581]

Thank you Sir 🙏

[@Versatiledani]

Good job thanks for sharing

[@HaseebElectronics]

best regards

[@knowledgetreasure-1523]

great video

[@susantaatha6468]

Excellent

[@HaseebElectronics]

Thank you so much 😀

[@DrKhakeeBaadshah]

Nice job dear brother

[@moseslakkam]

Thank for sharing your knowledge..! sir, please give complete calculations with timing too..on bleeder resistor as there is no complete info on dicharging capacitor on youtube channel..

[@rafiuajape448]

Salam alaekun engr Haseeb. I am and Rofiu from Nigeria, I really love ur blog and I have learnt alot especially, something I have been fine difficult in power electronics, I.e SMPS. May God Almighty Allah continue to increase your knowledge. Pls. I would like to ask you two questions: (1) in your CAPACITOR VOLTAGE DROPPER CIRCUIT (transformerless power supply circuit), you posted few week ago. How did you get "0.636" with ripples when you are calculating filter capacitor?. (2) pls, I have 12V/200AH sealed AGM Lead Acid batteries two, and I need to charge these batteries with at least, 30% of 400AH (60A). I don't want to use iron core transformer, I need SMPS, using ferrite core transformer. Pls I need your guidance on which topology should I used? with high current. Pls, giude me with schematic design diagrams and few calculation. (3) lastly, I have gone through all your tutorial about SMPS, I want to know how to design choke for input line filter and what type of toroid should be used with few calculation. Thanks God bless you.

[@electroniquepassion]

👍🙏🏻👍👋good

[@CookingKhabir]

👍👍👍👍👍

[@rambeweveranhoti4257]

woud you please inform me can this circuit use for rechargeable torch 'and can use 105 j 400v one instead of two sir

[@AugustineAriola]

Pretty video. How do I modify the circuit to charge small 12v lead accumulator battery?. I am aware charging current should be way high.

[@nayanjagirdar8408]

👌👌👌👍

[@HaseebElectronics]

thanks a lot

[@zawilious]

i think you forget to take into consideration that when calculating the capacitance(C), you took Xc (apparent resistance of capacitor) as the whole resistance of the dropper , but in reality the total resistance is Xc + R(of surge resistor), this is way you got different output voltage than you calculated

[@KAMARULZAMANAkader]

How long can it be used, can we apply as a continuously....

[@HaseebElectronics]

if it is designed properly, it works long.

[@sagittariusa5642]

Supply voltage is 230 Need voltage is 4V Need current is 0.1A Need power is 4v*0.1A = 0.4W Then capacitor voltage is 230-4 = 226V capacitor heating power is 226V / 0.1A = 22.6W But it doesn't get hot like 22.6W

[@cdlopez29]

Hello, thank you very much for this excellent video, I ask you, why did you use the peak voltage (317 V) instead of using only the input rms voltage of 250V for the calculation of the capacitor? pro security issues???Thank you, greetings.

[@abdulwahab5957]

great

[@HaseebElectronics]

thanks a lot dear brother

[@yashjasnani4466]

Some design uses drum core choke to limit inrush current and noises. Sir plz make a video on drum core choke design for differencial mode, common mode, buck or boost converter choke.

[@gtube2306]

Warning this circuit could potentially kill unless double insulated. In the event of a faulty component there is the potential to electrocute by direct connection to mains potential. The circuit is fine & safe if it is impossible to accidentally touch live parts or any metal work which the unit could be connected. Recommend also the addition of a fuse, and earth connection to provide protection in the event of a fault. An ELCB or RCCB may also provide protection.

[@69PlombierChauffagisteRamoneur]

salut 🙂

[@HaseebElectronics]

salutes dear friend

[@miriamramstudio3982]

Great video. Where is the value "0.636" coming from (in your calculation 16 minutes into the video)? Thanks

[@andriymakeyev]

Looks like it's an average value of a sine wave after diode bridge over its period Pi that is equal to 2/Pi=0.6366

[@hichamtassi1753]

Salam M Haseeb. I am having hard time to understand some aspects of this technical video. Why not putting the surge resistor before the capacitor and what is the function of the zener ? Thank you.

[@rushikeshdhiwar4831]

Sir can you please make a video on budget Multimeters.

[@raoamarjeet5473]

Nice video Sir I have 24v 750mamp transformer and i need 12v but 750mamp and if I drop voltage by using resistors, will i get amps also reduced by this process?

[@N0G0MAIL]

If I use a resistor R to drop 12V, R=V/I = 12V/0.75A = 16 ohms, P=V x I = 12V x 0.75A = 9W, so, I need a 16 ohm resistor / minim 9W. The resistor will heat, and need good airflow. The amps will not be reduced. If the load resistance is constant, this circuit will work, but if the load don't use 0.75A continuously, then the voltage on the load will be unstable, and can reach values greater than 12V. If the load use DC voltage, then we can use a voltage regulator as L7812 on a heatsink to provide a constant 12V on the output.

[@raoamarjeet5473]

@@N0G0MAIL ok ji Thanku so much

[@hrigamer9117]

Aslam o alikum sir Can i make this type supply for 12v 500mA.

[@aliali-et7xh]

i confuse..about calculate math n fomula of err electronic.calculate capasitor....dificult for me..😅😅..but it good video ...learn new today..26 december 22..

[@shefqetkaralliu6816]

🙏👍

[@HaseebElectronics]

so nice of you

[@vijayramakrishnan6838]

request is for a 6kv solar circuit and load 1.5 tonn ac ( using igbt - steup transformer -battery 100 ah X 12 v and panel 8no

[@cmk_tech0288]

Sir hindi wala chanel pe vido bana plise sir

[@kishmishkhopra4152]

Excellent explains