Heat Capacity, Specific Heat, and Calorimetry

We can use coffee cups to do simple experiments to figure out how quickly different materials heat up and cool down. It's called calorimetry. Take a look!
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you are amazing what the teacher do in 50 min you did it in 5 min

[@JihadAlAnsari]

I always wondered why it would take them 30 minutes to explain a concept which can be done in 2 minutes.

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indeed

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@@JihadAlAnsari because they are teaching 20+ people who learn in different ways, they also need to go over multiple topics at a time. Imagine you have a 2 minute class and don’t pay attention for one minute (zone out) you’re done for!

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"He knows lot about science stuffs, Professor David explains! Turuttu ! "

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Lol

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It's dave*

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@@DvolWOLF no it's chemistry Jesus

[@1alex92]

I love that too lol I'm always singing along 😂

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How tf does that sound like "turuttu" to you ?

[@charlesyuan]

It's my 2nd semester of first-year university chemistry... and of course, Professor Dave saves me once again.

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Same here and agreed 🥹

[@AbdelRadhwan]

@@yunyung lmao same as well

[@riruruuu]

Then why am I doing this in 10th grade. Not fair

[@riruruuu]

Then why am I doing this in 10th grade. Not fair

[@keviisam5200]

@@riruruuu bcaz what that person is doing is a intro chem course, they refresh the basics first then dive into the harder stuff as they progress

[@KFUURE]

Hello guys, just to help you guys out the equations is missing negative in the calculation. To end up with the Ans: 2.19 J/g °C i thought i would simplify for those that may need it. Don't forget the metal is losing energy and the water or liquid is gaining energy 'joules' So :- Qmetal/metal DT " -850J /(4.82) (-80.5°C) = 2.190665189. COOL WELL EXPLAINED VIDEO THOUGH. hope this helped.

[@gabriels2395]

At the beginning, it thought I would be really difficult, but you explained it well! I see that you omitted the cancelation of the negative signs of the metal q and the metal Delta temperature, that confused me at first but made me think a little harder (which was good!). Thank you again!

[@thestrange6]

hello sir ! my self rishabh , i am from india. today fortunately i came to your channel. your style of teaching is fantastic it attracts me a lot . thanks for free education. you are making a great effort to make this world Literate wish you all the best. you cover the topics very earlier and effectivily it is very benificial for all

[@BabitaKumari-vv4vo]

Same bro

[@ethanp4050]

I didn't do the comprehension I was to busy jamming to the sick beats

[@ProfessorDaveExplains]

check out the song at the end of any clip in my organic chemistry practice problems series. that's the dopest beat of them all.

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Wow you're right I'm adding it to my playlist rn ✌🏾

[@EbonyPope]

@@ProfessorDaveExplains Why are you using Celsius and not Kelvin? The equations I saw multply by Kelvin not Celsius. Won't you get a wrong result this way? Please help.

[@alexandergeorgebradley8707]

Thanks Professor Dave for doing something in four minuets my professor couldn't do in forty minuets. Explain the material.

[@comchemistry9381]

I would much prefer you use the equality of heat lost = heat gained. q(water) = -q(metal) Thus you can be consistent in the determination of delta T as final T - initial T. Your video is really nice for an introduction to the concept of calorimetry but may be confusing when instructors discuss exothermic changes which are given a negative q or delta H.

[@Jamieeee-ht7qk]

How do I always get suggestions on what I'm currently learning in class!? 😮 Professor Dave is psychic!

[@kevinkennedy1667]

Awesome video hit the nail right on the head

[@OddFoxxeP]

I know this video was a while ago but if you ever do remakes, putting everything in standard units would be awesome so it's consistent with college courses. Like kg, K, and all that. The visuals you put in are so helpful, thanks! ;]

[@mahigupta8505]

so u are a studend of thermodynamics?

[@EbonyPope]

Why is he using Celsius and not Kelvin? The equations I saw multply by Kelvin not Celsius. Won't you get a wrong result this way? Please help.

[@angeliemaebonaobra4448]

Thank you Professor Dave!!!!!

[@kameiku]

This dude is so amazing even the teacher all over the philippines LINKED his vids for me and my class mates to whatch

[@MasAgungLaksana]

It was a couple years I haven't learn about different of heat capacity or specific heat. Thanks for explaining us.

[@morganburke2286]

This really helped my understanding of this topic thank you!

[@abeladugna1897]

I love this man! Thank you so much, your amazing! ❤️

[@witty_me]

Dave, you are really good.Thank you very much.

[@alexiskironde7413]

Thankyou for the video on Heat Capacity, Specific Heat, and Calorimetry.-Alexis Kironde.

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Such a wholesome comment written like an email

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This is KZbin you didint have to be that formal take a chill pill😂

[@anubhavyadav4113]

The best part is your video is concise and useful . thanks

[@daflemubarik5000]

thank u very much really its clear more about calorimeter

[@oliviaadel594]

You are very fantastic prof. Thank you for making this channel 😊😊👍👍👍

[@ruivivarjohncarls.149]

Liked and subscribed. Thank you professor Dave, this is dope

[@aya5468]

Wow, I needed that visualization. 👀👌 This is good stuff.

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I love your content so much but bro you your intro is the funniest thing ever it really made my day

[@venkateshwarraovenkateshwa8837]

very nice explained sir

[@Catnipis]

Amei a explicação ❤🎉 muito obrigada! O Brasil te assiste!!

[@mcvihemba]

At a village a mother heats 4 liters of water with a paraffin stove from a temperature of 18 °C. She later noticed that 20 g of the paraffin was used up. Calculate the final temperature of the water if the heat value of paraffin is 31 MJ/kg and the specific heat capacity of water is 4187 J/kg. °C.

[@shlokmorbale7792]

thank you professor Dave, for eplaining me calorimetry in simple words.

[@thatboi7492]

Great videos! Keep it up!

[@randomguy36j98]

i have long graduated and sometimes this very simple thing is not remembered (we cant remember everything right), so this video is an excellent video for a short revision.

[@taimgamer9648]

What is the initial value of metal temperature?

[@sledfitness]

Very insightful helped me to understand that coffee cup experiment

[@pranavsrinath5076]

sir, will you define heat capacity with some other lab activities??

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Nice lecture

[@buildingfilming]

Awesome comprehension question!

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That's great explanation

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lovely explaination

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Your videos r very useful but can u plz talk about thermal decompostion

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to think this the same dude who be cussin out flat earthers i love this guy frl

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thamks

[@mattpachec0]

Thank you so much !!

[@damongeo840]

Τhank you very much for sharing! I am watching you lectures to revise material which is needed in order to earn my master's degree. The only thing that I would like to say is that since the volume of the water has two significant figures, the end result should have two significant figures too [2.2 J/(gr*°C)] (3:38). Apropos, I couldn't find a metal that has this specific heat; could you reveal it to me?

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THANK YOU FOR THIS!!!

[@ahnafajmain4366]

lovee the introoo i already start singing it when i click on ur video thank you brother, u help alot of fellow studs by ur lecs GOD BLESS YOU!!

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I love you Professor Dave

[@user-jn7uh4ej7u]

very great video! prof dave

[@warlock2158]

Thanks Dave.

[@asociatiaademed7417]

For practical reasons, the change in water temperature is to be recorded in time. When the graphic peaks, that is the temperature change for the given equations. That is because the calorimeter change heat with the environment as well. Your thoughts?

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Bless this video

[@tinkertaylorm0624]

Thanks!!

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The best explainer❤

[@mauwww_]

THANK YOU !

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Nice lecture sir

[@noelyperez2582]

My native language is Spanish but I study in Brazil so all my classes are in Portuguese and the only way that I found to understand this topic was theses videos in English hhahahahah, I love your videos

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Really? kkkkkkk I'm from Brazil

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I am from Bangladesh. Really your lecture help me.

[@Hiba-gd8rz]

That last q helped me understand that I understood. Tnku

[@nhynearanilla7601]

Hello sir.. thanks for this video. Just wanna ask how to measure sp of soluble solids like sugar? pls reply thanks

[@Seif97ify]

What's the difference between ''heat transfer'' and ''change in temperature''?

[@mohammadanwarzahoor1286]

Thank you sir

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I have my examen in 1 hour and I so nervious, thanks for help me

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Superb bro!!

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I am from Egypt , Really Thnx 💙

[@LinhNguyen-ds6vt]

Thank you

[@loyan.k]

I have another question is Does material has high heat capacity means to faster speed in change of temperature , in the condition of provide same heat to different material?

[@ruxiversi]

In the problem 4.82g of an unknown metal is heated to 115.0c and then placed in 35L of water at 28.7c,which then heats uptp 34.5c.What is the specific heat of the metal? For the waterq=(4.186 j/g) (35g)(5.8c) how or where did you get the 5.8cand for the Metal 850j =s(4.82g)(80.5c) S=2.19 j/g cwhere or how to get 80.5c as these temperatures are not mentioned in the question and also when i multiply the specific heat and the temperature i dont get 2.19 j/g ci get 4.82*80.5=388.01 Please explain at your earliest convenience as iam in a dark dark place

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Thank you bro 🙏

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vry usefull..gd way of teachnggggg

[@angeloamam3039]

Helps alot

[@snow1999]

i got more confused but thanks

[@bhavishyasharma7834]

3:45 why was the difference in water temperature not subtracted from the temperature of the metal, and why the total temperature was subtracted from the temperature of metal?

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I will do anything to make u my physics teacher....Thanks for these amazing videos !!!!!!! 🤩

[@prashant4123]

He looks like Ranveer Kapoor

[@shafianizan6808]

Hello prof. , im confused by the concept of this question which is contrast to my understanding, the solution explains that the q of the diamond is equal to the "-" q of the water (q[diamond]= - q[water]. Why did the water absorbed heat and has a negative value? 5. As a purity check for industrial diamonds, a 10.25-carat diamond (1 carat = 0.2000 g) is heated to 74.21 oC and immersed in 26.05 g of water in a calorimeter. The initial temperature of the water is 27.20 oC. If the specific heat of diamond is 0.519 J/g oC, what is the final temperature of the water?

[@JacobNignandorMobe]

Please prof, I have a question on the enthalpy as, If the elementary step A to B has a reaction enthalpy of XKJ and the activation energy of the reverse step B to A is YKJ, then the activation energy of the process A to B would be what?

[@user-hv6ef9ie1g]

2:31 Is the specificheat before or after the water absorbs the heat from the rock?

[@amitnayak5869]

Sir, how specific heat different from conductivity or with other mode of heat transfer....

[@Adarsh_Negi]

Specific heat is not a means of heat transfer , it is the characteristic property of every substance and is different for all.

[@matrixate]

Specific Heat of Water is 4.186 J/gC for the comprehension part.

[@gmed26]

TheChosenOne thanks. i was going crazy as i was using 1 cal/g C and getting the wrong answer hahah

[@keylal3339]

how does he get 4.186?

[@dre7teen530]

@@keylal3339 exactly i want to know as well

[@jasminecoca1170]

Thanks that helped alot But did you assume that the metal started up at 25.5°C when the question doesn't mention it. I thought that when the starting temperature isn't mentioned we just take the standard which is 25. So my answer was slightly different, s≈1.958J/g°C

[@zeimarodriguez7400]

Omg. Thank you! Im a chemistry major but this type of problem was so confusing to me. Thanks!

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Zeima Rodriguez bruh i’m in 6th grade tryna figure this out😭

[@aliyajamal3757]

Thanks

[@joshrosal5573]

Thank you My physics teacher is ass You made my day

[@asmaas4427]

Hi Professor Dave THANK YOU! Your videos are very helpful with my SAT Chemistry prep. I have a question tho, how do you get delta T for the second equation of the metal?

[@ProfessorDaveExplains]

the initial temperature of the metal is 115 so you have to use that!

[@puneetpalsingh4383]

@@ProfessorDaveExplains sir why we are taking the subtraction whether both are differently placed?

[@bubblee1445]

Hi@@ProfessorDaveExplains, I also have a question. Why are we subtracting from the initial temp for the delta T (change in temp) and not from the final temp (i.e. 34.5 C - 115 C)?

[@RebaoneKomane-xt7ep]

Thank u sir

[@laurend1307]

Why is 66.5 degrees not a negative change in temperature at 3:05? The temperature of the metal decreases to reach the final temperature, right?

[@amiralclaude3376]

Very intelligently explains. Prof Dave is the best

[@aristondaganioiii2670]

where did he get the 9.25g and 66.2 C in his computation for specific heat of metal?

[@user-mn8re8jp7v]

More examples, please!

[@syzy1442]

shouldn't be the q in computing for the specific heat capacity of metal be negative? Heat was released by the metal isn't it?

[@michellechal4669]

what is the calibration constant?

[@Kasiramaniyer]

thanks,

[@johnfei434]

These videos are very helpful. But just one suggestion, put them into an organized playlist of some sort so that people don't have to go around and search for the next topic

[@ProfessorDaveExplains]

buddy all of my tutorials are immaculately organized into playlists! did you even think to check before commenting?

[@liam5075]

3:45 Why is the metal's temperature variation 80.5 °C? Shouldn't it be 5.8°C?

[@marklarryorigenes8782]

Don't we use -q for released?

[@Emelliieee]

wouldnt q= -850? since delata T =final - initial? ---> (34.5-28.7) ...?

[@divinephanes]

I'm confused, how did you calculate the specific heat of an object?

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Me too 😢😢😢

[@LP.H967]

I need the latent heat and specific heat capacity of "Geraniol"....Can you help me?

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Yess