Heat Transfer (24) - Flat plate convection heat transfer coefficients

[@emt4921]

Thanks, CPP. I really hope that Dr Biddle finished this playlist before he retired. I'll be waiting for more videos.

[@CPPMechEngTutorials]

He did. The remaining videos will be released in the next couple weeks.

[@vicentereiman368]

This professor is amazing! Thank you so much sir!!!

[@chichorro1000]

24/37 let´s go! thank for the content guys!

[@CPPMechEngTutorials]

Keep going!

[@cathysunny1804]

Thank you for keep updating this series!

[@CPPMechEngTutorials]

You're welcome. Not even a pandemic could stop us from completing the series.

[@ZalanK77]

One step is very painfully missing from this otherwise excellent presentation. To calculate the turbulent heat transfer over the plate h(x)=k*Nu(x)/x is to be used and that needs to be integrated and divided by the length. So, it becomes the mysterious h_avg=0.037*Pr^(1/3)*k*(rho/mu*v_inf)^4/5*L^(-1/5). In this the Reynolds number was already substituted by Re(x)=v_inf/nu*x=rho*v_inf/mu*x as it is a function of x. nu is the greek letter for kinematic viscosity, rho is the density and mu is the dinamic viscosity. Nu(x) is the Nusselt number at location x, h(x) is the heat transfer coefficient the location x.

[@rzeeonthemic]

What is v infinite?

[@ZalanK77]

@@rzeeonthemic The velocity far away from the plate, so basically the velocity of the undisturbed fluid.

[@gajendrasingh_384]

Great lecture watching from India ❤❤

[@CPPMechEngTutorials]

Great comment! ❤

[@CarlMichaelAAdame]

Thank you very much, cpp

[@mohammadaiman4710]

what is eqn for hx for turbulent?? The lecturer didn't show in this video. Can somebody help me.

[@habibbolgiba8095]

I believe he derived it from the Nusselt number, by making hx the subject, therefore multiplying Nu by K and dividing by x. Not sure thou

[@willcolletti4357]

he kept referring to NU bar as h bar, is there a reason for that

[@vladislavbakovic279]

average over bar means average

[@isk3804]

Dr. Biddle is an excellent instructor, however cameraman ruins it a lot!!! :(

[@CPPMechEngTutorials]

The issue got fixed in future lectures.

[@jeffsmith7247]

@@CPPMechEngTutorials you always say that. lol, Here I am in future lectures..... :/

[@CPPMechEngTutorials]

@@jeffsmith7247 Hang in there... I swear it gets better.

[@jeffsmith7247]

@@CPPMechEngTutorials haha the last video better be a beauty

[@CPPMechEngTutorials]

@@jeffsmith7247 If it's not, you'll get a full refund.

[@dilannemutlu3835]

Bad

[@CPPMechEngTutorials]

bad = good?