Heat Transfer in Fins

[@jcnot9712]

This is a quality explanation, you cleared up so much I was still iffy on. It's criminal that there are no comments so I just came to say hi.

[@omido6604]

Wow!!! AMAZING!!! Thank you so much!!!

[@riadhguiraa1231]

Hi...I have a quite complex problem with a fin, could you plz help me out

[@annonymousvector1690]

Hi Postcard Proffesor. This is a good explanation, but I just want to ask about the part with Fourier's Law. As q=-kΔT, why is it that when you substitute into q it becomes d²T/dx²? As a matter of fact, I have a workbook saying its just dT/dX.

[@PostcardProfessor]

So q=-k dT/dx, and we end up with a dq/dx term. When you sub in q, you get d(-k dT/dx)/dx, which is where the second derivative comes from.

[@annonymousvector1690]

@@PostcardProfessor Thanks for the explanation. I have a favor to ask. Is it okay, if I send over a similar question to your email address? I just can't for the life of me solve it 😅

[@riadhguiraa1231]

Hi...I have a quite complex problem with a fin, could you plz help me out