Hill Cipher (Encryption)

[@nesoacademy]

Hill Cipher can be done in 2 different ways, 3*1 and 1*3. We will get different answers following the different ways. But adopting one method will surely satisfy encryption and Decryption. Few conventions use KP and a few uses PK.

[@kunalh910]

I dont understand ..how can two different ciphertext of same plain text can be possible .

[@bipinverma]

But according to formulas we have to adopt 3*1 if we are using c=k*p mod 26

[@ReelzAndLaughs]

We have only method to find cipher text i.e, c=kp mod 25. Here u did it wrong..please update the video..many of the students are loosing marks because of wrong formula

[@kirtanjaviya4306]

Bro NEY (13 4 24) THAT'S WRONG ............

[@kirtanjaviya4306]

Answer would be (14 3 7) of (NEY)

[@poongundran007]

Pls check the (13, 4, 24) its wrong .. The correct answer is (13, 4, 24) mod 26 is (353, 341, 605) mod 26 which is (15, 3, 7) =(P D H)

[@Reactionface0]

you are right brother

[@lakshmiprathyushaveturi4980]

Sir please continue the complete playlist ... We just depend on your playlist rather than our faculty...

[@AkashDeep-rr6jo]

Paid lectures

[@l3nox_music]

😂😂😂😂

[@Supreetvajjaramatti]

😅😂

[@nice6524]

Even college faculty depend on these videos

[@ashwinivaidya4183]

Very toughest algorithm understood in very simplest way ❤ love you neso❤

[@arulbalaji431]

you are the best professor in the world , hats off bro :)

[@Sanjaysview]

I just want to say thank you so much

[@abhisheksinghrajput1002]

Sir the for for encryption is = K*P not P*K cause both will give different outcomes cause matrix multiplicative properties... Pls correct it .. btw thank you for the content :)

[@Yametekudasaai]

Lora

[@NDORASRAVANASANDHYA]

Yes exactly

[@VivekYadav-ds8oz]

What? K*P implies a multiplication of 3x3 and 1x3, that's not possible. You'd have to change your plaintext to be a column vector then.

[@rahulguggilam5120]

Bro please upload stacks completely as soon as possible our syllabus is running so fast

[@rnjnmhta.catomato]

a lot of u are saying he is wrong but he's right using the example from whitman cengage Book

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@prathameshchavan3953]

Sir, the formula for encryption is Ci = (Ki*Pi) mod 26. where, Ci = Cipher Text, Ki = Key, Pi = Plain text

[@rnjnmhta.catomato]

both

[@Justanerd239]

Column vector , Row vector same thing .

[@yey7718]

This is wrong answer …. The ciphertext is :LNS HDL EWM TRW , you missed when you multiplication the row with a column its wrong the right solution its a Row with Row

[@manjunathkavishetti4619]

Why did u take p1 p2 p3 in row wise..why not in column wise..?

[@rajeshbalasingi377]

Thanks a lot sir It's help to done with my assignment

[@ShivamPatel-pq4vt]

Can you please continue and finish this series fast?! If I have to pay I will

[@slayerdangelo234]

Whoa 😮

[@Mp-lw8tw]

"pay more money" lol

[@shwetahegde8850]

Thank you sir.. Very helpful

[@ki_san321]

For the Hill cipher, you must perform matrix multiplication, treating the plaintext as a column vector. Row-wise alignment will not produce the intended results, and it deviates from the standard method of encryption in the Hill cipher.

[@vishwasshukla8687]

i think there is a problem with this method. i saw other videos videos K.P here it is P.K, both are different, which method is correct. Plz Explain...

[@Hecker_bro]

12:40 bhai tune 3x3 and 1x3 matrix multiply kaise kar diya??

[@sandynaguib4806]

Is choosing the key based on any criteria other than the dimensions of the matrix ?

[@ashiksaleem360]

I think this method is wrong. cause you multiplied 1*3 x 3*3 instead of 3*3 x 3*1. also i check using a online hill cipher tool

[@sawpaingchitmin8848]

Thank a lot sir!

[@beletebekele1211]

tanks your help me academically tutor.

[@diwakar542]

Should have used KP approach. Most of the textbooks follow KP approach as well as most encoders and decoders. I'm 1 year late to know the fact. All the damage haven't been made that were to be made.

[@Mohanad_Adnan]

Hi Sir may be there is a mistake in Encryption of ney is (353 341 605) not (348 312 538)

[@malavikagowda5809]

Yeah

[@naveenbabusunkoju6068]

Yes I also find same for ney 353 341 605 but may be some editing error 348 84 48

[@beborani1660]

Exactly same issue

[@paritoshpandey5705]

Can we only encrypt on only plaintext that have length as multiples of 3 if key is 3×3 ?

[@purvababhulkar1415]

Thanks a lot😊

[@rohitpatle2312]

Hamari ma'am bhi yahi se padh ke padha rahi hai class mai 😅😅

[@Yash_kamble2201]

Copy paste 😅

[@spoideegaming6168]

yup it's right bro 😂 is se accha to youtube ka premium membership le lete ads to skip ho jate

[@RVGAMING-ot3bf]

😅

[@utsavseth6573]

beautifully explained

[@pramod198]

Sir in Network analysis we want Time domain analysis of RL and RC circuits

[@Rimi666]

I don't understand the division area for example 303/26 is 11 but in the video he said 17 please help

[@valkyrex5262]

17 is the remainder, 303÷26=11 remainder 17

[@ganeshbagul9732]

RSA.py import math # step 1 p = int(input(" - Enter a prime number (17, 19, 23, etc): ")) q = int(input(" - Enter another prime number (Not one you entered above): ")) # step 2 n = p*q print("n =", n) # step 3 phi = (p-1)*(q-1) # step 4 e = 2 while(e

[@AyeshaSahelRahamathISE--]

I got the answer to be RRLMWBKMSPDH instead of RRLMW A KMSPDH I’m not getting 0 It’s 312mod 26 which means 12 which would give M & not A Correct me if I’m wrong

[@yogeshkumar5307]

while grouping if we get one or two letters extra, then how to proceed.. eg. if plain text .. my name is joe... grp1: myn grp2: ame grp3: isj .. now what to do with oe?

[@haricharan2836]

u did 312 mod 26 calculation wrong the remainder should be taken so 0 is correct

[@shipenalamech4382]

Sir I don't understand from final calculation divided by 26. I am not getting same amount.

[@valkyrex5262]

303÷26=11 remainder 17, 303÷26=11, 11x26=286, 303-286=17 that's why 17, because its from the remainder

[@AnshumanPal-pk3ei]

Sir the cipertext of of "mor" is different from what you are saying

[@Kuber-n8b]

What about the encryption of spaces between each words?

[@NeemaPaul-pn4uv]

What if plain text ended with 2 letter and its three cross three matrix....am asking about the letter added will not have effect when generating the cipher text?

[@ilhemwalker9145]

thank you

[@babydisyam3508]

Very very so much👍 ❤❤❤❤❤

[@AnshumanPal-pk3ei]

If we divide 532by 26 the answer is 20 point something

[@gemechu7384]

Thankyou so much👏👏👏

[@sameer282]

IN VIDEO AT 16:30 THE VALUE OF P1 IS 353 ONCE CHECK

[@sameer282]

P1 value

[@ferhangursum1693]

YEP 221 + 84 + 48 =353 @@sameer282

[@nadeemdanish1868]

el(L) ❌ yel ✅

[@hetdoshi9385]

in the calculation of encryption of emy you have make misktate but you dont correct it how confusing for any beginer solve it and then your ans is correct so it totally confusing for any beginer

[@sharikatasnim1198]

This isnt the correct method of encryption. The plain text matrix was supposed to be 3x1 matrix and not 1x3. What Stalling's book says is: the plaintext should be converted to coloumn vector of length k, if the key matrix is a k×k matrix. This is why even the answer is not correct here.

[@nesoacademy]

Hill Cipher can be done in 2 different ways, 3*1 and 1*3. We will get different answers following the different ways. But adopting one method will surely satisfy encryption and Decryption.

[@rnjnmhta.catomato]

dono shi h bhen

[@beborani1660]

yeah it will be done in column but giving me good concept

[@mdmaaz7817]

Issko koi tappad marke chup karo

[@Student_of_bca]

Why are subtitles off?

[@CSsaThishR]

How to insert the filler character if plaintext ends with two digit

[@5_Minute.Lectures]

Thank you !!!

[@DasEtwas]

nice video

[@TechAsad]

Plain text should be in column not in row

[@soundarrajan8311]

If there is no key value what can i do would you pls explain

[@anirbansaha2104]

pray

[@PaulMarkovu]

You multiplied vector by matrix but u should multiply matrix by vector so u r wrong

[@dr.anitapradhan5489]

MAM IF FOX & XEROX WILL BE THE PLAINTEXT HOW TOMAKE PAIR

[@Haramian.]

Entire multiplication is wrong. It should be k x p and not px k.....I lose 5 marks because of your teaching mistake in my engineering exam

[@dr.anitapradhan5489]

MAM PLEASE POST FOR MORE VIDEOS

[@syedmunawerhassan9994]

You have missed spaces how spaces are encrypted or decrypted ? Why x is padded why not y or what if last letter is x then should we pad x ? Or other character ?

[@c3a118]

spaces are not encrypted. do each word separately i suppose

[@yogeshkumar5307]

@@c3a118 while grouping if we get one or two letters extra, then how to proceed.. eg. if plain text .. my name is joe... grp1: myn grp2: ame grp3: isj .. now what to do with oe?

[@irtiqamuzaffarzaki3706]

Last calculation is incorrect needs to b rectified

[@kirthika821]

How to get the ppt ??

[@TechnicalWaniyt]

cipher text is wrong bro

[@shreenathsp7016]

13:35 its qql not rrl

[@subrajitbhowmik706]

how L is 11 in PAY

[@motivation_with_harsh]

Answer to this question = RRLMWBKAQPDH

[@omaralbalouli7452]

Your encryption is wrong you have to multiply every message pair with the row not the column I advice you to delete the video and make another one Thanks for the good videos

[@nesoacademy]

Hill Cipher can be done in 2 different ways, 3*1 and 1*3. We will get different answers following the different ways. But adopting one method will surely satisfy encryption and Decryption.

[@brianjoonjiangoh9206]

Lol, r u sure u teaching the correct thing? I think the encryption for "Pay more money" is "lns hdle wmtrw" All these people are following blindly lol.

[@ashiksaleem360]

Yup the video is wrong. verified from online hill cipher decoder. i think the error is when he muliplies the matrix. coz 1*3 x 3*3 is not the same as 3*3 x 3*1 and neso is muliplying matrices using 1*3 x 3*3

[@JavedIqbal-fb4dk]

@@smilealways7344 bilkul

[@cst030santhoshm4]

The method is correct but plain text should be taken in the order 3*1 but here it is taken in the form of 1*3 thats why there is a such variation in the chipertext

[@bulliraju5439]

@@cst030santhoshm4 we can't multiply if we take (1*3)

[@scooby-doo1778]

I agree, Plaintxt and Ciphertxt matrices should always be column matrices

[@mahirchauhan213]

Formula is false True formula is :k*p(mod 26 )

[@phunsukhwangdu8273]

sharath sir .............

[@shivvi__]

Actually 15*17+0*21+24*2 is 255 and you are saying it as 303 lol

[@rodzay8771]

It’s “303” 255*48 = 303

[@MuhammadFaez1]

you did the calculation wrong

[@jaypatel6770]

lnshdlewmtrw

[@AnshumanPal-pk3ei]

You are saying 12

[@poojapoojadhapte1430]

😊

[@Adonis08]

🔴🔴🔴🔴🔴🔴🔴 This is Wrong!!! just one change K*P instead of P*K .. otherwise you will get a Wrong answer btw Thank you!!!

[@mercykimaiyo6338]

This is wrong the multiplication of the matrix is not it

[@skbala3107]

Ney answer wrong

[@mhsamhsa5456]

i hope translate for arabic

[@tusharjeena7081]

It is wrong method

[@naveenbabusunkoju6068]

With respect i want to let you know for ney 353 341 605 but may be some editing error 348 84 48 displayed calculations

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@ashazra2559]

The cipher text for pay is LNS, why is yours different?

[@sammymendis475]

Thank you so much!

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭

[@itz_my_planet4202]

Sir plz continue the series of discrete mathematics 😭😭😭😭😭😭