Polyalphabetic Cipher (Vigenère Cipher)

[@mohamadzaytoun4566]

you are the best educative channel on KZbin . I am really thankful for this great work in your many courses .

[@chibutakayashi4744]

That was very simple explanation... Thank you for making it easy to understand....

[@sheshankumarasinghe9116]

Clearly understood. Appreciate. Great service

[@RJSR_1234]

superbly explained bro thanks a lot for providing this knowledge to us

[@Krishna-z1g5r]

I am really thankful for this great work in your many courses .

[@kresh1619]

Good to go within 10 mins ! Thx yea

[@josephmbote4167]

Great , easily explained

[@radhikatalokar3002]

Sir you r the best

[@geovanecandidoievenes6703]

Thank you for this incredible explanation!

[@ravalimanchala8170]

Great work thank u. Keep doing

[@dhaneshpt8641]

Great work.. thank you

[@sawpaingchitmin8848]

Thank you!

[@SiphathiseneNothileMthimkhulu]

Thank You ❤❤❤

[@zerox5596]

wow thank you so much brother

[@Edwina1D]

Very interesting subject ,thank you for your video! I have a question, are we the ones who determine the keyword as well?

[@dariocline]

yup, pretty sure you do

[@UltimateOpportunist123]

Sender

[@Habibullahgero]

Lets say i wanna encrypt "Meet me after the party we have to discuss the isolation" and my key is "description" so now if i m using auto key system the key will be "descriptionmeetmeafterthepartywehavetodis" so isn't it completely understandable for the attackers?

[@arjungaming2706]

Bro don't worry These are way old techniques Cryptanalysis will die but never use this technique We got more advance techniques than this. Chilll

[@infoworld9106]

We wil use the key as descriptiondescriptiondescriptiondescriptiondescription

[@namjimenez]

hi, good afternoon. Do you have a video on how to decipher the Vigenère?

[@hamshihamsu5461]

Thank you very much 💓💟

[@devmahad]

Done, thanks :)

[@ramyapriyadharshinitg9972]

Admired your teaching❤❤

[@satya8190]

I didn't find any difference between cesar and vigenar cipher. Could tell it

[@mouneydonuru2769]

in ceasar, key is always 3 i.e. we always add 3 to p.t, but here the key changes and the number to be added also changes

[@svrsunkara1728]

It means you arw a fool😂

[@aswinmanmathans6837]

@13:24 The example you provided is wrong , even though you just explained the same thing in the entire video , here the concatentation refers to the fact that we are adding each key to a letter in the plain text hence we are getting a running key . I'm mentioning this for someone who read this for the same doubt . Thank you

[@kartikforwork]

can you explain better what he expain wrong

[@shahanajakter-kb2ux]

​@@kartikforworkAlphabet 0-25

[@jagdishsingh9741]

How to predict length of key if we have cipher text? Length of test which is being repeated?

[@abhishekmane3144]

What is mod m

[@rearozu29]

mod means Modulo

[@abhishekmane3144]

@@rearozu29 I completed my engineering and now working as a SDE 1 😂 But thanks finally someone replied

[@worldofgaming748]

​@@abhishekmane3144this is soo funny 😂 btw what was your college?

[@techgeeks0807]

Sir can you add lessons on assembly language programming for microcontrollers please

[@Shaharyar101k]

Pls sir make video on modern algorithms

[@HanumeshvBurli]

How to do decryption for Autokey System

[@jonasuusiku4959]

video the explains mod operation?

[@guduleharrisonya8426]

Nice video! What is that mod m subscript on the key bit??

[@Soupman7]

I got different for the last 2 characters, ZICVTWQNGRZGVTWAVZHCQYGLMZS Note the Z and S in place of the M and the G. O=14,L=11 14+11=25 mod 26=25 = Z N=13, F=5 18 (mod 26) = 18 =S. Do you see my error?

[@julesruzindana-rukundo6254]

my ciphered text was zmstsymjgrymjgrnemibrcjusgj

[@chiarazoccolan6105]

For the last 2 character: •(Key) V= 21 and E= 4 •(PT) L=11 and F = 5 So for CT you have to sum: • 21+11= 32, that is position 6 (letter G). Because you have to start to count from zero, so Z is 25, A is 26 (=0). • 4 + 5 = 9, that is letter J Hope it can help you 😊

[@novicecoder5753]

When the question asked about vigenere cipher which key type i need to use to solve the problem either repeating key method or autokey system method can any body solve my doubt?

[@Shaharyar101k]

Nice question i think whatever asked in question

[@me-ashacker233]

Key is same for any palintext like 3

[@alinajaved2165]

how we can take key?

[@bakeery]

25 mod 25 = 25??? It's not 0?

[@Muhammad_Shoukat]

Its equal to 0. Mod is the reminder value.

[@aswinp2135]

its equal to 1 and reminder is 0

[@smilealways7344]

Sender and Receiver

[@prahashpurbey3678]

lovely

[@watchnext2334]

Please update the whole portionn

[@chiarazoccolan6105]

If I have to encryption the word "cryptographic" with the given key from my teacher "eng". My final keyword will be "engengengenge" ?? Because they have to be the same length... Thank you 🥰

[@scarlettwoods6013]

This isn't vigenere cipher! It's vernam cipher.

[@labanidas4318]

Yes I noticed the same

[@mister_meatloaf]

It is vignere only. Vernam is simple XOR op.

[@JatinSinghMehra-q1u]

it is vignere...

[@satvikmudgal9062]

You're wrong

[@Triggerbaba6]

Sasta Nasha karke aaya hai kya bhai😅😅😅😅

[@ARSAGAMING69]

❤❤❤

[@ajithkarthikeyathota3874]

2:30

[@ar.lakshmanan8746]

kryptos!!

[@inakollumouryavardhanreddy1189]

1k like for this video 😁👍

[@sushiladhikari4975]

qbasic program to using vigenere Chipher CLS INPUT "Enter your plain text character"; q$ input "Enter your key word" ; l$ q$=lcase$(q$) for p = 1 to len (q$) p$=mid$(q$,p,1) if p$= "a" then a=0 elseif p$="b" then a=1 elseif p$="c" then a=2 elseif p$="d" then a=3 elseif p$="e" then a=4 elseif p$="f" then a=5 elseif p$="g" then a=6 elseif p$="h" then a=7 elseif p$="i" then a=8 elseif p$="j" then a=9 elseif p$="k" then a=10 elseif p$="l" then a=11 elseif p$="m" then a=12 elseif p$="n" then a=13 elseif p$="o" then a=14 elseif p$="p" then a=15 elseif p$="q" then a=16 elseif p$="r" then a=17 elseif p$="s" then a=18 elseif p$="t" then a=19 elseif p$="u" then a=20 elseif p$="v" then a=21 elseif p$="w" then a=22 elseif p$="x" then a=23 elseif p$="y" then a=24 else a=25 end if next p l$=lcase$(l$) for p= 1 to len (l$) k$=mid$(l$,p,1) if k$= "b" then b=0 elseif k$="b" then b=1 elseif k$="c" then b=2 elseif k$="d" then b=3 elseif k$="e" then b=4 elseif k$="f" then b=5 elseif k$="g" then b=6 elseif k$="h" then b=7 elseif k$="i" then b=8 elseif k$="j" then b=9 elseif k$="k" then b=10 elseif k$="l" then b=11 elseif k$="m" then b=12 elseif k$="n" then b=13 elseif k$="o" then b=14 elseif k$="p" then b=15 elseif k$="q" then b=16 elseif k$="r" then b=17 elseif k$="s" then b=18 elseif k$="t" then b=19 elseif k$="u" then b=20 elseif k$="v" then b=21 elseif k$="w" then b=22 elseif k$="x" then b=23 elseif k$="y" then b=24 else b=25 end if next p for p = 1 to len (l$) sum = a + b ci = sum MOD 26 IF ci = 0 THEN PRINT "a" ELSEIF ci = 1 THEN PRINT "b" ELSEIF ci = 2 THEN PRINT "c" ELSEIF ci = 3 THEN PRINT "c" ELSEIF ci = 4 THEN PRINT "d" ELSEIF ci = 5 THEN PRINT "e" ELSEIF ci = 6 THEN PRINT "f" ELSEIF ci = 7 THEN PRINT "g" ELSEIF ci = 8 THEN PRINT "h" ELSEIF ci = 9 THEN PRINT "i" ELSEIF ci = 10 THEN PRINT "j" ELSEIF ci = 11 THEN PRINT "k" ELSEIF ci = 12 THEN PRINT "l" ELSEIF ci = 13 THEN PRINT "m" ELSEIF ci = 14 THEN PRINT "n" ELSEIF ci = 15 THEN PRINT "o" ELSEIF ci = 16 THEN PRINT "p" ELSEIF ci = 17 THEN PRINT "q" ELSEIF ci = 18 THEN PRINT "r" ELSEIF ci = 19 THEN PRINT "s" ELSEIF ci = 20 THEN PRINT "u" ELSEIF ci = 21 THEN PRINT "v" ELSEIF ci = 22 THEN PRINT "w" ELSEIF ci = 23 THEN PRINT "x" ELSEIF ci = 24 THEN PRINT "y" ELSE ci = 25 PRINT "z" END IF next p