Hill48 anisotropic yield parameter optimization for simulation (Get MATLAB code)

[@muhammadadeel3434]

Thanks for explanation, could you please tell me how did you decide the F = 0.8404; G = 0.7324 H = 0.2677 N = 1.9814 as the optimum values you needed in the first place?

[@LucasPaiva96]

Great explanation. Could you tell where is the reference for the equation for R(theta) and the coefficients Rij? In Abaqus documentation those equations are different, and the result is not the same. With your R(theta) function I could correctly match experimental and simulation results

[@jorgelizarazu2013]

Excellent video, thanks a lot! I may ask you: Why R13 = R23 = 1? What is the source of the equation you used, which relates R45 to the parameters F, G, H and N? Sorry for being redundant with these questions that might be already posed.

[@ijsklontje]

Amazing Video, with great explanation! I was wondering how you where able to transform the Hill Yield criterion to the Sin(theta) and Cos(theta) like you show at 1:10. How did you manage to do this or do you maybe have any sources on how this is achieved? I wish to expand it to 3 Dimensions.

[@suryateja3460]

Sir, hill 48 yield criteria subroutine used to solve 1d element b31? Do we get plastic deformation for 1d element?

[@10Minuters]

Yes, there can be plastic deformation in 1D element

[@MrPurnashis]

Sir can make a video on how to optimize the parameter of Barlat2004 from the r values and stress ratios along different directions.

[@jihadnaofal2825]

hi , do you have any answer؟ i am very interested

[@corni6501]

If we assume R13 = R23 = 1 that would mean that there is no anisotropy in the 13 and 23 Dicection for shear stresses right? Is there any possybility to further estimate those to values withoud having to do any additional Experiments?

[@DEEPAKkumar-rd6ey]

dude! You've got your answer. You know how to calculate it using any method. please explain it. I also have same confusion.