Understanding plasticity theory (for Mises UMAT)

[@linghaokong4396]

thanks a lot for the vedio! But in 13:08, it should be subtract sign in stead of add sign in the maternal

[@pablocb3529]

Congratulations for your video. Very well explained. It is difficult to find so good and professional plasticity explanations in internet. I’ve found out that the p-q diagram is very useful to visualize pressure dependency and to progress to Drucker-Prager models for example with tension-compression asymmetries.We are using more and more pressure dependent plastic models for metals in car crash finite element simulations. We need pressure dependent models to build up accurate fracture models.

[@DineshKumar-bz1lg]

Good Explanation. Appreciate the efforts to explain so nicely.

[@selvamraj11]

@ 7.21 Why we are calculating the effective plastic strain rate tensor instead of effective plastic strain?

[@engineering_software]

plastic deformation depends on loading history therefore the problem is solved incrementally.

[@arash4232]

Hi, the equation of the linear hardening (time 2:44) does not match with the figure; the intercept of the line is less than sigma y.

[@engineering_software]

Please note that in the formula plastic strain is used while in the curve horizontal axis shows total strain.

[@azz650]

in 11:28 , when calculating the normal (n), why did we divide by 2*sqrt(3/2 sigma':sigma') ?

[@engineering_software]

Please note that we are making a derivation from sigma-e, which its definition contains square root.

[@azz650]

@@engineering_software oh yes, thank you so much :)

[@vignarajahkm4462]

good one

[@hamedrahmatavar4397]

great great

[@albinbenny2384]

Thankyou

[@shahbazshzzi]

Good explanation

[@Jehosafath]

excellent

[@selvamraj11]

Excellent Video I understand the concept of effective stress for various cases. how do you write effective stress equal to Sqrt(2/3 sigma':sigma'), any derivation is available?

[@engineering_software]

2/3 can be found by this fact: In simple tension effective stress is equal to applied stress.

[@selvamraj11]

@@engineering_software Thank you very much, This is my long-time doubt, it is clear Now. Still, I am wondering how they introduce the factor!

[@hoseinabedi3448]

👍