Hofmann Elimination via Exhaustive Methylation of Amines

We know how to do elimination reactions when something like a halogen is the leaving group. But we can we do this kind of chemistry to eliminate an amino group? We can! We have to do something called exhaustive methylation, and once you see how that works, you'll understand why we call it that. One more strategy for the tool kit coming up!
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[@alial-haideri]

thanks Dr. for interesting explain. However, could you express why Zaitsev ELIMINATION doesn't occur while it gives more substituent and more stable alkene? With best regards.

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@@PunmasterSTP Well I have about 4 more months to go and I will be done :D

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@@PunmasterSTP I've been in hospitals and done the full inspections of patients. It's not residency per se, but it's practically the same thing.

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@@whodis799 Are you referring to the last two, clinical years, as opposed to the first two academic?

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Niraj Kumar he became a father recently, so to look like a father, he did cut down his long hairs .

[@azadprasad856]

No need to thanks me

[@cliffordwilliams9597]

Thanks Professor Dave! Your comparison of the alkylation of amines to the protonation of alcohols made everything make sense! So much appreciation!

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Thankyou Professor Dave. I hope you get more recognition.

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Great explanation 👍

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[@michaelathens953]

Cool video! Have y'all done one about alcohols/aldehydes/ketones and reduction of alcohols to either of the other two? Pretty basic topic but I think a lot of people who watch this kind of content would find it interesting.

[@ProfessorDaveExplains]

yep i have a few on redox in this playlist!

[@michaelathens953]

@@ProfessorDaveExplains Thanks for replying! I just subscribed about a week ago and haven't even made a dent in your library yet. Got to look harder I suppose.

[@musiccarvan]

@@michaelathens953 Hey you just need to reduce aldehydes and ketones in the presence of LiAlH4 or NaBH4 and you'll get your alcohols and if you want to make aldehydes/ketones from alcohols you just need to oxidize First degree alcohol with PCC to get aldehyde and and react a secondary alcohol with PCC to form a ketone Note: You can also use K2Cr2O7 or KMnO4 has oxidizing agents in conversion of alcohols in aldehydes ad ketones Hope it helps and if you have reached here would you mind checking out my channel as well

[@ingevdf]

Thank you Dave!

[@denbarb3]

Not a chemist but a similar process is used for Simvastatin Ammonium Salt for Zocor.

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[@glacius]

thanks for this. i didn't get the mechanism no matter at what angle i viewed my highschool textbook. now i got it😊

[@fakhrulnawawi9681]

Thanks for your videos. Can I substitute the silver oxide solution with something basic like cyanide ion or hco3-?

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Nice haircut, great lesson. Thank you.

[@pareshsanghani9780]

suggest process of O methylation of Amide Group (CONH2)

[@kirtichuchra1339]

hi proff Dave, i was wondering if you could help me with newman projection amine how does that amine group reacted in this hoffman reaction .

[@benYaakov]

I don't understand that why bulky ammonium part is responsible for hoffmann product

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you explain very well :) and you look very handsome with new hair cut by the way...

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I think he looked handsome both before and after.

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Thanks for sharing.

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check my algebra tutorials

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Professor Dave Explains thanks for starting IIT-JEE tutorials , God bless your newborn son/daughter. Keep shining always Dave, you made me learn a lots of organic chemistry, I have a huge debt, offer me opportunities to repay it. Thaaanks a lot , staaaay blessed .

[@fahimkhan3866]

So the ammonium salt is a good leaving group?

[@ProfessorDaveExplains]

yep! gets neutralized to form ammonia when it leaves.

[@othmanal-bayati2013]

Thanks :)

[@shubhankarsinha9084]

why is zaitsev product not formed ?

[@ProfessorDaveExplains]

sterics

[@shubhankarsinha9084]

@@ProfessorDaveExplains Thank you sir

[@PunmasterSTP]

Exhaustive methylation? More like "With the time someone saves from studying, I think they could go on a vacation!" Thanks again for all these wonderful videos.

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yeah that N better not talk to me about exhaustion

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@@NewWesternFront Oh yeah for sure; I remember those days.

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Is this possible with acid catalyst?

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how to find empirical formula of compounds?

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Prof Dave explains to other Avengers how to defeat Hofmann

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Sir, plz explain metallurgy process especially poling, Van arkel process. Plz Sir.

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[@priyalneekhra5418]

Tip : it is an anti elimination

[@spacevspitch4028]

Anyone else feeling a bit methylated?

[@FGuilt]

I'm feeling exhaustive...

[@PunmasterSTP]

@@FGuilt Oh (Hoff)man, I feel like I've been eliminated...

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[@ProfessorDaveExplains]

Neat! I say just go ahead and run it and I'll pop my head in once in a while.

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Cool! If you’d like you could add it in your video descriptions so people can see it and start subscribing, but if you’re not comfortable with that I understand.

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[@uniquegirl313]

Is it only me whose more interested in starting music then my queries. I repeatedly listen it.😂