Finally a spherical integral video that actually explains the boundaries. Integrating should be the thing that comes easily but the bounds have been tripping me up. Thank you sir I probably won’t do well on my test tomorrow but I’ll definitely do bettter now thanks!
@joaquinmattecamus3639 Жыл бұрын
Absolute goat, as the level In calculus increases, the harder it is to find videos and this one explained how to find the boundaries perfectly
@seniorshimhanda56903 жыл бұрын
This video incredibly enabled me to understand parametrization, a crucial step towards comprehending the electromagnetic theory. Now I can compute electric fields, electric potential and electrostatic energy with ease. HMP is basically the best math tutor online. Thank you for helping me overcome this hurdle: electromagnetism is the basis of my career!!!
@HoustonMathPrep3 жыл бұрын
This is outstanding to hear! Best of luck with EM theory! \o/
@menaceecho6790 Жыл бұрын
prepping for calc 3 final, huge help
@syahfA13 жыл бұрын
Finally I know why I need to learn this thing. Before this, I just calculate it without knowing the purpose. Thank youu sir. Good and clear explanation.
@の雪-m5f3 жыл бұрын
Luckily I found your video before the exam... I totally can't understand what's Rho and everything before watching your video... thanks!!!
@HoustonMathPrep3 жыл бұрын
You got this!
@isisyasmim6394 жыл бұрын
I really like the progression of the lesson. Very helpful!
@HoustonMathPrep4 жыл бұрын
Glad to hear that!
@mukhtarabdi4443 Жыл бұрын
Thank you so much. I go to through all your videos about double and triple integrals I really appreciate the simple and understandable way that you explained. Thanks again
@aSoulJourner3 жыл бұрын
Thanks, very clear explanations and good exemples.
@jordanfreidel17514 жыл бұрын
Just one question, when setting the integral limits for dfi why do you only go half way around(pi) the sphere and not all the way around(2pi)?
@HoustonMathPrep4 жыл бұрын
Remember that phi is measured from the positive axis downward. So if phi is from 0 to pi, that will give us a slice that is a semicircle in shape (in the xz-plane). If we take that semicircle and revolve it about the z-axis (which is the theta from 0 to 2pi part), we get the entire sphere. If we used phi from 0 to 2pi, our slice would be an entire circle. This means we have two of the slices mentioned above both revolving about the z-axis to generate a sphere, and each of those slices would generate a sphere by itself which would give us double the sphere we want.
@jordanfreidel17514 жыл бұрын
@@HoustonMathPrep thank you so much!
@harshanasenevirathna66773 жыл бұрын
You saved my day ❤❤ semester credits goes to you☝
@HoustonMathPrep3 жыл бұрын
The credit is all yours! We just provided a little help 😁
@aarthiarulabi33313 жыл бұрын
Thank you very much, sir. Awesome video.
@HoustonMathPrep3 жыл бұрын
You are welcome! Thank you for your kind words.
@krishanbhalsod47503 жыл бұрын
Question, when you were setting the triple integral for the last problem, why couldn't we solve for p and make that the upper bound, when we were given z=3 and phi=pi/3? Might be a dumb question.