How do you derive the period of oscillation for a pendulum?

Рет қаралды 61,406

Dot Physics

Күн бұрын

Пікірлер: 38

@cerealbowI 8 ай бұрын

This video just makes the entire thing more confusing lol

@philos22 3 ай бұрын

you're just dumb and not prepared yet to this

@iceiceisaac 2 жыл бұрын

When you go to the next blank page, always keep the equation from last one visible. Love these videos btw!

@sameerdumne6965 6 ай бұрын

I second that

@fizixx 2 жыл бұрын

I'll have to do this one. I don't remember how I use to do this from scratch, but it'll be a great refresher. :)

@neelanjansarkar7412 7 ай бұрын

Physics was easy but greek letters ruined it

@omnigod7624 6 ай бұрын

True

@kazukawasaki97 Ай бұрын

I like them,looks cool

@poetryinUrdu-r5g 28 күн бұрын

I agree with you .physics is not difficult.It is easy but people make it deffcult.Ignorant people know more than us .They can make genrator Msc student can't make

@YenchieLee 7 ай бұрын

I was so confused with this before. thank you

@ezxd5192 8 ай бұрын

when you said θ(t) = Acosωt + Bsinωt, why did you decide to put omega inside the sine and cosine?

@rohith5062 5 ай бұрын

look up on how to solve a second order linear differential equation

@Noahpie20 Жыл бұрын

Thank you I finally understand this! I didn’t anticipate that it would involve a little Taylor series action!

@Cloud1-tn6ti 3 ай бұрын

why are u not considering the component of tension that also acts ,if we take angle theta with the vertical then tsin(theta) provides force for the circular motion ??

@Jeff-zc6rr 6 ай бұрын

If you really want to understand this.. you need to know how to solve linear differential equations with constant coefficients and complex numbers. Requires more than just physics.

@hosh1313 Жыл бұрын

General Relativity has a lot of explaining to do! :)

@HigorMadeira97 2 жыл бұрын

hey professor, could you teach us how to solve extreme distance free fall problems?

@DotPhysics 2 жыл бұрын

What is an example of an "extreme distance free fall" problem?

@HigorMadeira97 2 жыл бұрын

like when should consider the gradient of gravity, like a tennis ball falling the same distance from the moon to earh, since the gravity will change in some rate, and obviously the acceleration will not be as the same as earth surface. i think would be very nice see how it is done.

@shivanach45 Жыл бұрын

@@HigorMadeira97 You'd need to use differential equations and g (now a variable) would be GM / R where G is the universal gravitation constant, M is the mass of the earth and R is the distance between the point mass (assume tennis ball to be a point mass) and Earth's centre . Essentially, we are having g to vary with distance here.

@toby2031 Жыл бұрын

Thank you for this video. At 3:25, isn't the acceleration always directed towards the centre in circular motion? Surely therefore there is no component in the direction of s to plug into F=ma?

@DotPhysics Жыл бұрын

The tension does indeed pull in the center direction, but not the gravitational force. This means the net force is not in the r-hat direction.

@kaeez 4 ай бұрын

What you're referring to here is the centripetal force which facilitates circular motion. The centripetal force here is provided by the tension in the string. The gravitational acceleration is provided by the gravitational force.

@OluwoleJunior 7 ай бұрын

I don't see how x(t) = Acos(wt).

@trickyepithet9122 Жыл бұрын

I found a different way to derive, but im not sure if its correct. force of gravity = centripetal force? mg = mw^2 L w^2 = g/L w = (g/L)^1/2 is it a correct way to derive?

@DotPhysics Жыл бұрын

But the gravitational force is down and the acceleration is up. This doesn't work.

@trickyepithet9122 Жыл бұрын

@@DotPhysics ahh alr

@herrroin6867 9 ай бұрын

Why can we say w=2*pi*f?

@kathode1 9 ай бұрын

angular frequency (ω) is defined as the amount of radians an oscillator undergoes per second, which would be 2πf because frequency is the amount of cycles and there are 2π radians/cycle

@samridhsharma5028 Ай бұрын

Since f is 1/T, so basically f is denoting the time here. It is one and the same thing, just in different notation

@Heartgamercher Жыл бұрын

Could I ask why you have to let theta is small before the next step?

@DotPhysics Жыл бұрын

If theta is small, then you can let sin(theta) = theta. That makes the differential equation solvable by guessing a solution. It will look just like a simple harmonic oscillator.

@Heartgamercher Жыл бұрын

Why the θ(t) = Acosωt + Bsinωt ?

@DotPhysics Жыл бұрын

not theta(t), but f(t) - right? It's a function that satisfies the differential equation. If you take the derivative twice, you get the same function with a negative constant out front.