Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation

[@oscarludwinmalaveranarcaya7080]

At last, somone who explains it... Thank u!!!

[@DdoubleB03]

it's an ok explanation. He doesn't explain where the "second derivative" comes from.

[@liverpoolfan-8198]

Unbelievable.! You taught the topic very easily within a few minutes.

[@aymaneoulahyane6803]

I saw other videos but this one mad most sense to me

[@ellenchilawa4858]

Very good at explaining ,,,

[@theA731N]

How is this easier than adding? You teach well. Thank you.

[@ege_027]

Would someone explain me that how square of the angular frequency gets to be equal as -k/m ? I mean we defined the k to be the proportion constant which is understandable and I get it but considering that we don't know what exactly the k is, how can we use it?

[@arnavbrawls9586]

0:40 Isnt x away from the equilibrium position

[@over-scrupulous]

It is best on you tube 🎉

[@FChaudhary]

4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?

[@salva1519]

No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c

[@dioutoroo]

At 03:20, he mentioned about the chain rule. Which part is it? Why dv/dt = dv/dx*dx/dt? Can someone explain?

[@eugene97]

Part of chain rule the dx and dx cancel out and we get dv/dt

[@ChisomOnu-gx1pv]

Nice explanation bro

[@amirtayib9178]

Good learning from continu

[@Tahirsabo11]

Please sir which software did you used to record your videos🙏

[@danielunuagah9337]

Please in the course of finding the integral why didn't you integrate (w)?,

[@yusrilalfarizy5595]

I think because the integration only depends on x and t, then ω becomes constant that can be placed outside of integral

[@suchitawasnik3633]

He integrated w but with respect to t so w becomes a constant and gets multiplied by it and if you take its derivative it becomes w hence lhs equal to rhs

[@anushkasharma7334]

ω here is a constant watch video again he takes ω=sqrt(k/m)

[@Colibrinegro]

😮Thank you so much

[@rpg1997]

At which case shm equation will be in cosine and when it will be in Sine ?? Please clarify

[@Luxuryhitler]

Sin will be in displacement and acceleration while cosin is in velocity

[@Venu_GD]

@@Luxuryhitler not necessary...sin and cosine functions can be converted to each other interchangeably..

[@Luxuryhitler]

@@Venu_GD yaeh ofc I've speaking abt general form

[@AfrojShah-vw5hy]

Hi

[@JosephParker7]

It doesn't matter. Sin and Cos can be used interchangeably if you change the phase constant. So if phi is 90 degrees, then it becomes cos and phi becomes 0

[@amorelela]

omg this was so helpful thank you.

[@philiplamar]

isnt it suppose to be Acos(wt+Ö)

[@suchitawasnik3633]

If the particle starts from its mean position we take sine as position is 0 but when the particle in shm starts from its maximum displacement A then we say it as cos

[@aymaneoulahyane6803]

​@@suchitawasnik3633thanks

[@ege_027]

Depends of the initial point. They're actually the same thing

[@anushkasharma7334]

How ω² = k/m , can anyone explain

[@eymendediler5357]

the w itself is root of k/m then k/m equals to the ω²

[@mailingbox]

@@eymendediler5357but how do you derive w = k/m? is this purely definitional?

[@axramsta]

@@mailingbox F = mw^2x = kx

[@icebeartwo]

@@mailingboxIt is purely definitional.

[@sirilbhimala]

To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m

[@blerimhaxhiu7338]

Im amazed by this form, thanks a lot bro !

[@theantimatter4742]

Thanks dude

[@badboysuraj7035]

Thanks you sir in this concept is completed 😀 simple harmonic motion

[@manichandrapukhrambam509]

How c= 1/2 A^2w^2

[@ege_027]

If you choose the moment where the velocity is 0, you can find the exact value of c by eliminating the v variable

[@archiemanuel504]

A=amplitude X=Amplitude X=A Sqrt(A^2 - X^2) Sqrt(0)?????

[@ege_027]

X is a variable which we are analysing its behaviour as the time goes. So it is not always the same thing as the Amplitude. If they're same at a point, it means that the object moved as far as possible from the starting point which have now became as big as the position vector of the amplitude. So yeah it would be 0 in this case but you're forgetting that this term is inside of the cos function, so cos(0) would be 1 and x = A (Amplitude) as intented to be.

[@nazmul9546]

This tutorial need another tutorial

[@farahhafez8482]

TOP G

[@DdoubleB03]

this video doesn't even make sense.

[@farahhafez8482]

@@DdoubleB03 it helped me thu, i do not know about u

[@benjamino.b5305]

Nice

[@FatmaShomari]

What’s c mean

[@physixdaily6223]

That's an integration constant

[@aymaneoulahyane6803]

Isn't it cos

[@physixdaily6223]

you can use cos or use sine. Both works.

[@unexpected1948]

your channel need to make SEO

[@bazylikempczynski8068]

sin(sin^-1(x/A)) =/= x/A ??

[@elionsakshith3508]

It is

[@leon.deepujohn9073]

Sin*(Sin^-1) is Sin*(1/Sin) by considering basic maths , you will get the rest X/A .