How to calculate "Empirical Formula" || Super Trick Method with Q&A | Mole concept || NEET JEE

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[@sellermahi2172]

If you really want to know the trick to how to find emprical formula when percentage is given then start from 12:35

[@mayday1457]

thanks really time is very precious

[@abdullahsaif6864]

Thankx

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👍🏻👍🏻🙏

[@cdt.parveshjoshi2780]

Why didn't I see your comment . 😞😞

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Thxx

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You are really a ray of hope for poor students who can't afford institute fee.May God bless you!

[@naziyamalik3871]

Hello Good evening sir. 😄😄🌹🌹🌷🌷🌺🌺🌺 Lecture completed 👍👍

[@kiranpandey555]

Ek no explanation❤❤ Katehii jehrrr😘😘

[@sumanasharma7251]

Sir, your way of teaching is extremely amazing

[@Utkarsh_Singh_Hrithik2024]

Sir from where U R Such a Great 👍🏻 Explanation 😃 First time I understand It Everything 😊

[@owaisosman6703]

Thanks allot sir and made ejee team going to complete this....

[@anjleenkaur65]

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[@mousam8719]

Thank you. ...u are really doing very good job ...may god bless you with good health ......😊

[@cyborggaming2021]

Hi 😁😁😁😁

[@cyborggaming2021]

Hi

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[@sirmeribaatsunlo2910]

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[@PUBG-PLAYER.-]

Fantastic video i got everything related to E.F and M.F. thnku sir🙏🙏🙏👍👍☺

[@anandshete9170]

%composition of H in H2O is 11.11 not 11.79 and %composition of O is 88.88 not 88.21 according to your calculations

[@alphaofficial914]

Yes man I am also confused

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Mera bhi 🙋🙋

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Itna hi pta ah too yaha kyu aaya ha

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You are right Bro 😇

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I can' t know that the lecture is over. I was so deeply involved . Thanks for helping poor who can't afford money 🙏🙏🙏🙏🙏

[@meeta_ramaiya]

Good evening sir Thank-you for lecture👍👍👍C=52.17% H=13.04% O=34.78%

[@namratapanem4232]

You are just awsome sir😃😀☺😊🤟👍

[@akankshalakhera3774]

C=52.17% ,H=13.04,O=34.34% Thank you so much sir 👍👍👍👍👍👍👍👍👍👍👍👍

[@akankshachoudhary690]

You are the best..I just love it sir💞💞💞💞

[@cyborggaming2021]

Hi

[@kanishkmeena6737]

51.17 13.04 34.78 Thank you so much sir 😊😊😊😊 Love you sir 😘😘 so mucha

[@suhailmanzoor6999]

Allah aapko salamat rakhe hamesha..with ur family...u r helping the students..Allah will never let u down..anywhere...insha allah

[@InDrayanI_Chavhan]

Thanku So Much Sir....🙏🏻🙏🏻🙏🏻❤ Sir Aapke jaisa na to koi padha sakta hai aur na hi koi padhayega....👌🏻👍🏻👍🏻👍🏻 You Are The Besttttt Teacher & besttttt Person Sir......🤗🤗🤗❤ Love You So Much Sir & Team...❤❤❤ Thanks A Lot For Everything....🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

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Sir.. ur teaching is superb

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Absolutely fine lecture for easy understanding thanks for such a excellent video.❤️❤️

[@voiceofuttarakhand7]

Sir bhut ji jayada accha explanation thanks sir or vedios banaye

[@sirvilive2935]

Completed...... Thankyou so much Sir ji

[@tabassumfatima4154]

Good evening sir😄😄

[@bhavnayadav6796]

Thank u sir.....🤗🤗🤗🤗🤗

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Sir ye second video h jo Mene dekhi h ap ne boot ache se samjhaya h 👌👍

[@harshitakanaujia5686]

Sir you are best teacher

[@shyamsarkar7994]

Sir In C2H5OH % of carbon =52.17 % of hydrogen =13.04 % of oxygen = 34.78

[@ankitachaturvedi5994]

Kse smjh ni aaya 24 carbon or 6 hydrogen kse kha se aaya??

[@Jethalalsigma231]

@@ankitachaturvedi5994 Isme carbon ke 2 atom hai 1 atom ka mass 12 two atom = 12×2 = 24 Hydrogen ke 6 atom 1 atom ka mass = 1 U 1U × 6 = 6u

[@happypandit5266]

बहुत बहुत शुक्रिया आदरणीय सर।।।।।।।।🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🏻🙏🏼🙏🏼🙏🏽🙏🏾👀🙏🏿

[@officialmedia8141]

Thank you sir yours obediently ,….….……….💯💯🙏🏻

[@rajeshvaid3141]

c-52.17,H-13.04 and o-34.78

[@dhruvdhruv9496]

sir please tell me how to solve the question " determine the emperical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass

[@sanjuverma2539]

Its an Example in Book

[@FunTime-tg7ki]

Take notes

[@unknownxyz2353]

Bhai Tera ans aayega fe2o3

[@unknownxyz2353]

Phele 69.9 ko approx 70 g = given mass man then divide by the atomic mass of fe that's 56 u will get 70 /56 = 20/16 or 5/4 . Now take 30.1 as given mass for oxygen / divide this by 16 g which is the atomic mass for oxygen . So u will get 30 /16 here I have approxed 30.1 to 30 now since 20 /16 is smaller divide 30 /16 by it and u will get 3 :2 = moles of o :moles of fe . Compare and get the formula Fe2O3 and also mf = ef ( Here the simplest ratio is 2:3 itself )

[@sushmapansari2465]

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[@Ruhi1919]

C℅=52.17 %H=14.60 %O=34.7 These are % composition of C2H5OH

[@physicschemistry7448]

Percentage of hydrogen is wrong

[@physicschemistry7448]

Its 13.04

[@devendrashetty2266]

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[@acristal243]

Thank u so much sir for this help.😭😭your help had make my doubts crystal clear.

[@humzashaikh4041]

Thank u Sir ur the best teacher of chemistry. ....😊 Answer c=52.1% H=13.4% O=34.7%👍👍👍

[@poojarajput4481]

H 13.04 hoga

[@anjalimishra4192]

13.04%

[@manavthevar2132]

Yes H is 13.04 but still good you tried and succeeded

[@meer-e-karvaan.6070]

ans:) C=52.17 H=13.04 O=34.78

[@musurao]

U r master teacher sir👌✌️👌

[@netranjali6235]

Nice explained sir🤩

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[@gamerbabu5947]

good lecture

[@jagritiyadav4077]

Thank sir you made easy to learn this which i never understood

[@Its_beauty_of_nature]

10;53 percent of carbon=24/46x100=52.21percent percent of hydrogen=6/46x100=12.12percent percent of oxygen=16/46x100=35.67percent....

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Bhut Acha smjhia Hy sir ap na bhut easy way ma❤

[@ruchikayadav3844]

Thanks sir 🙏🙏🙏🙏🙏.....

[@adarshmudgal8241]

% of c =52 , % of H =13 ,% of O =34 .

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*THANKU SIR AND MADE EJEE TEAM* 👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👌👌👌👌👌👌👌👌👌🎉🎆🎆🎊🎆🎊👏👏👏👌✔❤✔❤❤❤✔✔❤❤❤❤❤❤❤❤

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In a day two video. Just sufficient. Still want more😍😍

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[@SWETAKUMARI-xr8ox]

C-52;17 H-13;04 O-34 present

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My mole concept is completely clear because of you.Thanks sir😊😊☺️☺️

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[@1MinTakeAway]

Mass percentage of C - 26.08 percentage H- 13.04 percentage O- 34.78 percentage

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Thanks sir aaj pata chala h empirical formula ka important or iska pata chalte h class karne mai or maza aya h 🙃🙃🙃 thanks sir 😘😘😘

[@madhavharish2575]

Thank you so much Sir, You make our concepts really EJEE !!!!

[@dadaraonathbhajan]

Ans is c=52.17 h=13.04 o=34.78 and thanks sir

[@InDrayanI_Chavhan]

Completed Sir....👍🏻👍🏻👍🏻👍🏻 Ans is...C = 52.17%, H = 13.04%, O = 34.78% Thanku Sir...🙏🏻🙏🏻🙏🏻😊

[@darshikakushwaha7644]

Indrayani Chavhan Give me ans....moles concept kha h...NCERT me...

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[@naturesbeauty9877]

%of c =52.16, %of H=13.04, %of O=34.8=💯

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