How to calculate normmality in chemistry?

[@joginpelli]

First comment pin me please

[@Nishchitha_Hegde]

Only a few minutes ago I discovered this channel ,and honestly searched for normality video after watching molarity and molality ,THANK YOU SOOO MUCH SIR 🙏🙏

[@NAJAMACADEMY]

Welcome 👍 💗 🙏

[@muzamilnazir624]

Najam-the star You deserve 5 star rating

[@Lanakalana]

Omg I can’t thank u enough 😭 best explanation i had in three years

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[@shrishkishore1618]

I can definitely say that this is the best channel for clearing doubts and understanding concepts in chemistry! I am really grateful to you sir! Sir definitely deserves more subscribers.

[@pushendrapatel5500]

Amazing I liked this video and share also.and advise others also.

[@NAJAMACADEMY]

Welcome 👍 💗

[@navdeep7346]

I don't know that how do i thank you this is the best video which i have never ever seen before ❤️ thanks alot sir for make concept of normality soo easy

[@adityabhambhani207]

Alhamdulillah such a great explanation! cannot thank you enough sir! cleared all concepts

[@probitesstudy3612]

thank you soo much bro i was strugling with his for 2 years you cleared it thank youuuu

[@surjyapradhan5369]

Crystal clear...concept sir... Thank you very much...

[@BinuriUththaraRanasinghe]

Crystal clear explanation. Thank you so much! Keep up the good work!!

[@PravallikaDasu-c9f]

Anyone in 2024-2025.Its amazing u cleared all my doubts of normality really it was useful tq so much sir

[@omanieshpandiyan84]

Thank you for this video sir, i asked you to upload video about equivalent mass few month before and you uploaded it sir,thank you for your sincere work sir

[@acid2518]

Have my JEE Mains tomorrow, Thanks a lot for this... It will help me a lot to do Electrochemical Questions... Like Molal and Equivalent Conductivity questions ... :)❤

[@drsid369]

Bro has exam the next day and still has the time to post this comment 😂

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[@devilshaurya576]

In chemistry, equivalent weight (also known as gram equivalent or equivalent mass) is the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance

[@Writer.ji_0]

Very good explanation sir nobody can explain like you sir i appreciate your work keep it up 👍🏻

[@elizabethtjahjadarmawan22]

Yeaahhh yesss i need this. Thanks Prof🙏😍

[@NAJAMACADEMY]

Welcome 👍 💗 🙏

[@somii1312]

Sir I'm so happy to find a channel like yours where I could clear my doubts especially in chemistry.. But sir wanna suggest to reduce advertisement a bit since it's a nuisances while watching the video for the students sometimes..No offence but if you could consider my request I'll be so glad... Much love

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Good suggestion!!! It is the only source of our earning. We wouldn't be able to survive if we decrease it... Sorry!!! 🙏❤️😊

[@aleenavineeth6582]

​@@NAJAMACADEMYsir how to calculate normality of 0.12m CuSO4 solution

[@mysterygirl5659]

Why I found you so late 😩 really need this kind of teaching 🙂✨

[@MakoriGlenn]

like the way you arrange your work and the explanation is clear. im definetly coming back to watch more of your videos

[@JHKL68-K]

Thanks Sir U have made chemistry better with Ur steps

[@laibatalib3877]

Thank you Soo much tomorrow is my practical and I was very confused because I don't know how to calculate normality but after your lec my all doubts are clear thanks ❤❤❤

[@yusratahir6293]

❤️ finally found the real teacher

[@khaledPortgas]

This is the best explanation i've even seen for normality, 🎉🎉🎉🎉🎉

[@nitinbidhan2337]

Thank you sir for clearing my doubts . plz one heart sir ❤️🙏🙏

[@nitinbidhan2337]

Thanku soo much sir

[@aarifyounas9181]

Assalam O Alaikum Sir please make 1st year class biology, physics and chemistry lectures topic wise your lectures are very helpful for umderstanding concepts. Thanks for your lectures. God bless you!!!

[@gametech8010]

Literally it's an amazing lecture

[@chakshukamboj3557]

After watching this video my all concept clear very very thankyou

[@avijitbarat6287]

Thanks sir explain everything very easily & conceptual

[@Chirag2007Bc]

thank you bro, u helped me solve my problem. really appriciate it. it feels happy to solve a sum i was stuck on for 2 hours. may god bless you homie

[@alphasaffi9230]

Great thanks a lot i wondering why most of them here commenting negative.what wrong with this explanations eh

[@pprameela3518]

Sir thank u so much 😭😭❤️❤️ I was dying with this topic ..u cleared all my doubts so easily

[@FullCodedAlchemist]

thank you so much. very thorough. i feel like you could find the cure of cancer

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najam academy is always the best

[@sakambaripatra6744]

Thank you God bless u and your family ❤

[@MuhammadAmeen-xu9ux]

Lovely outstanding my dear teacher Allah bless you with happiness and success

[@jyotishridhar4095]

Very good explanation of the concept 😊 This video is of great help to all the students preparing for the test of this chapter.

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dear sir, u just earned my respect and subscription and like on this video. may lord help u as u helping us all.

[@gaurichaudhari1848]

Very helpful video

[@nourhannebouziane8899]

The best explanation ever thank u so much teacher 👏👏👏👏

[@anbusivaeduhub2582]

Thank u sir , this is very understandable 🎉

[@jagjitsingh1265]

Beautiful method of teaching

[@sahil_khann]

Provide more knowledge in less time☺️

[@NAJAMACADEMY]

Thank you 😊 💓 ☺️

[@harshdubey8382]

Sir you are literally teaching good

[@MutegekiJohnBosco]

I like ' let me repeat it 😊 thank you very much for this 🙏

[@kaayumurgeshwari4885]

Excellent teaching sir..thank you so much

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Thanks a lot sir your video lectures is awesome

[@LokeswariAsapana]

Super Explanation Sir! ❤❤❤🎉🎉🎉🎉😊

[@nuftananabenet8888]

I learnt in class but I didn't now the concept until I see this video thanks

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Thank u thank u thank u thank u Sooooo muchhhhh sirrr

[@sekhar6154]

It helped me soo much in exams🎉🎉🎉

[@abhinavbhargav8]

Thank you So Much Sir For This easy explanation ❤️🙏

[@liyalena4146]

cleared my doubts sir ur amazinggg

[@sukritisingh6385]

superb explanation very helpful all concepts clear!

[@rayasamkiran]

Ideal explanation should start from balancing the equation of H2SO4 reacting with NAOH. For every one molecule of H2SO4 we need two molecules of NAOH. So 1/2 mole weight of H2SO4 is enough to completely react with one mole weight of NAOH. From here starts the purpose of finding equivalent weight. But in this video it was told time and again that out of 98 grams only 49 grams has potential to react which is a total wrong direction. My son got confused and misunderstood the concept and after that I had to verify all the textbooks and explain him this way.

[@AshithaGani]

Thank u sir ...u made it so easy 😊

[@allfriendsgaming7163]

Thank you so much for your explanation sir 🎉

[@Srtechwala]

Thanks sir ❤ I concept clear😊 and i like your languages in English because esliye understand languages❤🎉🎉

[@Et_sapien]

Thank you this is really helpful

[@AditiJadhao-m5z]

Thank you so much, This video is really helpful

[@SivaKumar-wu9jq]

Thank u sir . Very clear explaination

[@samyukthaprem8969]

Thank you so much for making this wonderful video❤❤

[@itso999]

Best video I found!

[@easy-peasy9906]

2:46 mass of 1 molecule of h2sp4 is 98 grams....sir u siad this which is wrong plz correct. Other than that the video is a masterpiece. Hats off to you.

[@Physics-j6c]

Ciristal clear man thank you so so much my brother ❤

[@lifeofgods3895]

Very helpful video sir ❤❤❤❤❤

[@respectforever8974]

This is very simple gram equivalent means the amount of substance that can accept or donate a mole of electrons therefore the normality can be defined as the number of moles of electrons that can be donated or accepted in a one litre solution. Like if this helps.

[@sajidaqaiser3293]

Really appreciable,keep it up sir.

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These lecture is great! Can you please add your video's in sequence in playlist's so it becomes easy for us to find video according to our current chapter

[@mamtamalhotra3780]

I am watching you since my 11th class now i am in 12th 😌🙂

[@2121TMK]

Very helpful sir! Thank you so much🙏🏻

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Salute 🫡 to you sir 🙏

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excellent teaching

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Excellent explanation!

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You are genius 👍

[@b.padmini8288]

Thank you sir

[@NAJAMACADEMY]

Welcome 👍 💗

[@appalanaidujada6131]

Thank you sir nice explanation

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[@sunithakumari9753]

Thank you sir 😊😊

[@Blewmellow]

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[@maharamir5221]

best plateform ❤

[@shiva_the_authentic]

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Thank you so much sir ☺️😊😊

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[@aimanedits]

Very well done sir g 👍

[@shriyabhattacharya1889]

Molar mass should be the mass of 1 mole of h2so4 and that's why it is in g otherwise it would be 98 amu(atomic mass unit) if it is taken as molecule.

[@jyothishivaputrappa9505]

Thanku Sir

[@jyothishivaputrappa9505]

🎉

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mujy pahly hi pta tha sir agr thoda Aur kiyana sir1❤❤❤❤❤ class chod k bagh gaya gy😂❤

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Thanks. Good lecture.😊

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Great job brother

[@KennedyMuwandi-l1m]

Its quite helpful

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Thank you so much.!!!!

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Thankyou Soo Much bro/Sir

[@Fantzy_boy]

Thanks sir😊

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nice explanation🎉🎉

[@klltsun_2576]

Thank you so much

[@tapanofficial4044]

Thanks you so much sir

[@ComeBack-s1g]

Amazing🤩🤩