How to calculate support Reactions on beams (Fixed, propped beam, SS beam)

100K VIEWS #Mechanics#VirtualWork#FreeBodyDiagram#AshishPurohit Video shows concept of different loading, beam supports and reactions. Inclined roller support.
Complete Lecture series:
Engineering Mechanics || Theory and Numerical || Lecture Series
• Engineering Mechanics ...
Equilibrium of particles: Static of concurrent forces, Sine law, Lemi’s Theorem, Examples
Equilibrium of Rigid Body: Moment and torque, Free body diagram, pin support/roller support, pulley system, uniform loading, variable loading, Force couple system, Resultant moment,
Trusses and Frames : Method of section, Method of Joints, Zero force members
Centroid of complex shapes, Second Moment of Area: parallel axis theorem
Virtual Work Principle: Explanation of concept and numerical practice problem
Friction: Screw Friction example, Wedge Friction problem, Belt and Pulley Friction
Shear Force and Bending Moment diagram (SFD BMD): Cantilever beam, simply supported beam over hanged beam
DAlembert Principle: Basic Introduction Numerical example

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[@ashishpurohit9138]

Please note that at the end 19.50 sec, Ay should be 33.3 N instead of 86.6 as ( 120-100sin60) ,,please correct.

[@iocivildesignstech1186]

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[@kartikeyaphale7553]

sir why didnt u consider Ay while solving moment

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[@PhilosophySaga]

do roller joints support horizontal movements if they are inclined?

[@ashishpurohit9138]

Hi, I couldn't follow your query..can you elaborate.

[@anshulwasnik6224]

koi nit raipur wale ye dekh rahe ho to bta du ye question pyq me aaya tha

[@rakeshmohan3966]

Why for inclined support we use derivatives of cos° and sin* can u explain pls

[@ashishpurohit9138]

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[@derangedartist7740]

CW is Negative and CCW is positive ! Thats what we learned to our teacher.

[@ashishpurohit9138]

Actually conventions are decided by us, so it does not affeslct end result. As one will be positive and other will be negative so complete equation will always be balanced. The only thing we must follow is consistancy, whatever convention we fixed in the start must follow throught the question.

[@manojnarayan1229]

7:34

[@marindimitrov4045]

The second example is wrong ,because you have 5 suport reaction and 3 equilibrium equations .Second example is undetermined you can do it like that. i might be wrong .i will be very happy if you explain me .

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9cly thanks a lot

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[@shubhbhandari169]

Sir how to find E I can not understand that plz help me

[@ashishpurohit9138]

Can you please indicate time instance....

[@marykareenfayeabellar105]

How did you get a 100 for reaction at E? (the last problem)

[@ashishpurohit9138]

Hello, in the question the maximum load at the roller support is given as 100 N, this is nothing but the reaction at E, which is available. It it would not be given, the problem will become statically indeterminant as number of unknown will become 4.

[@marykareenfayeabellar105]

@@ashishpurohit9138 ah okay, I did not see that. Thank you!

[@marykareenfayeabellar105]

@@ashishpurohit9138 I think the reaction at Ay=33.4 N from (120-100sin60)

[@ashishpurohit9138]

@@marykareenfayeabellar105 yes, it is calculation error, I have put a comment . thank you very much.

[@devojunaganandinidevojunag6867]

Sir I have a doubt .. How should I write moment if the couple is 40kN/m in clock wise direction? Like if I change the units of the couple

[@ashishpurohit9138]

Hi dear, I have a doubt in your query, unit of couple is N-m, if it is kN/m means either UDL or variable load. please explain more and if possible please indicate time instance where you got doubt.

[@devojunaganandinidevojunag6867]

@@ashishpurohit9138 sir I have a doubt that if I change the units of couple like kN/m then what will be the moment (In case of over hanging beam)

[@ashishpurohit9138]

kzbin.info/aero/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ

[@sanjanamailagani]

we get Ay=33.39 N

[@ashishpurohit9138]

Dear Sanjana you are correct..it's calculation error...I have already given in comments but can not correct in video as KZbin doesn't allow.

[@faizalpogivlog8738]

Sir please help why does roller support at E has horizontal force?

[@ashishpurohit9138]

please specify the time instance

[@ashishpurohit9138]

kzbin.info/aero/PLi0hoi2vOpnQ1wu7w4CMSUobzKuWIEThQ

[@ashishpurohit9138]

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[@dhiirageliyahanolosha5510]

How did you get 7 because we have 8?????????

[@rolandoquispebasualdo6546]

Ay ? =120-100sin60° = 33.40N

[@ashishpurohit9138]

Yes it is a calculation error in the video. Thank you

[@HarshitKumar-bu7oo]

how did you get the answer as 86 for Ay .Its clear not.

[@ashishpurohit9138]

Plz mentioned time Instance

[@aimalmulla773]

14:36 problem is having a problem🤣🙏...happens

[@ashishpurohit9138]

can you please elaborate..what prob you observed

[@sanjaychopra9789]

How the angle is 60 degree?

[@ashishpurohit9138]

Dear Sanjay, Can you mention the time instance

[@sanjaychopra9789]

@@ashishpurohit9138 sir at 16:38

[@sakshamchopra7666]

Sir at 16:41 how the angle is 90 -30 = 60 ?

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[@ashishpurohit9138]

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[@DSCH-SupriyaG]

Sir 5+3 is 8 not 7

[@dellpi3911]

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[@psycholover3191]

Moment liye to horizontal force nhi liye kyo horizontal force liya jata kya

[@ashishpurohit9138]

Dear Saif, What I understood is, horizontal force ka moment kyo nahi liya...actually, usaka line of action point of momont se pass ho raha hai so perpendicular distance zero hoga...if still it is not the answer of your query.. please mention time instance at that you have confusion

[@usmanali-ze1vg]

Summation of forces in y direction upwards forces positive downwards forces negative you did not day it

[@ashishpurohit9138]

Can you please specify time instance where I missed it...

[@haleyruble364]

The sign does not matter for the way he is doing it, he put all downward forces on one side and upward forces on the other side of the = sign. He did Ay+ Ey= 120N+100N+90N+190sin60 if you were summing all y forces equal to zero then the signs would matter and it would look like such: Ey+Ay-120N-100N-90N-120sin60=0 the you move the negatives to the other side, and you would get the same formula he used, so the signs don't matter. - = + is the same as + = - so you don't need the sign of the forces unless you are setting them equal to zero. As long as you put all upward forces on the same side and all downward forces on the same side.

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Very bad bro try in different ways

[@ashishpurohit9138]

Thanks dear, can you point out area to be improved

[@KCESANDHYAKAYEDIYA]

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