How to Calculate The day of the week from the Date in Seconds.(Calendar Problem). Mental Maths- 11

In This video we will learn the famous Calendar Problem trick that a Human Calculator guy performed in Asia's got talent , In which we can swiftly calculate the day of the week from a date.
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[@mathOgenius]

Have fun with this cool Trick!

[@LandonRTLE]

Thank you 😺

[@mathOgenius]

@Ansh pandey that channel is the one in which I just give voice over, my team mate is really busy so I was unable to upload there . Also We are thinking to upload in english too beacuse of demand .

[@abhigamer2907]

Your voice is best

[@kriya5723]

I have tried calculating 19 aug 2000 using this trick im getting friday , but it is saturday .

[@mathOgenius]

@@kriya5723 see august code is 1 , date is 19 so total is 20 , year code is 0 so, 20/7 gives remainder 4 , which is for saturday.

[@chopeeehusseinfj]

You are a really really smart person, most of my math problems are solved by you , Love from Fiji Islands , Thank you and stay Safe.

[@mathOgenius]

glad to help !

[@sehjat595]

Thank you so much! I just started watching 5 mins ago and I love your content its so help full to me especially because I suck at maths and I hate it but you explain so so so so well it makes everything so so so so much clear than before!! you deserve a sub and like! I think we need more people like you! keep up the good work! :)

[@vedanshabcdefghiklmnopqrstuv]

very cool trick, thanks mathOgenius, you are actually a math genius :D

[@thecalendarninja]

The easiest way to do this is to prememorize all 100 year values from 00 to 99. Then I just add that to the century code and reduce mod7 and finally add that to a prememorized value for each of the possible 366 dates. For example, June 15, 2012 would simply be: 2+2+1=5, so Friday! June 15 always has a value of 2 (prememorized) 2000's has a century code of 2 and, year 12 always has a value of 1 (prememorized) 2+2+1=5, Friday! Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same! I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.

[@skobeloff4477]

Sir, You are the one of the finest math's teacher on KZbin... :)

[@mathOgenius]

Thanks you !

[@mugaruraronald7684]

How do you do for 12 August 2004

[@poojakushwah6641]

@@mugaruraronald7684 Thursday

[@deeptidivya2459]

♥️

[@Joker5_]

From where we get 25%

[@rajkaran3798]

Your flow of video is got damn good now! ;)

[@yugathdewdisa64]

You are amazing!! TYSM!! Lots of love from SL

[@iffatnawaz665]

You are doing a great job 👍 keep it up 🙂

[@CosmicPhoenix]

This channel is a gem 💎

[@divyanshtewari6277]

I honestly think that u shud go to any of the TV program where maths is given importance❤️ Go 100K Brudah...!!

[@Onespica]

This is deceptively simple. Definitely gonna impress my friends with this. Thank you!

[@RaldinCasidar]

Oh, I accidentally viewed this video and Im a software developer and this trick/algorithm can help me a lot in the future. I didn't know this exists. Thank you so much!

[@kishorecoelho3186]

You are a genius. Great work

[@utubesaha]

Every 28 years the calendar repeat itself. Hence the first step for year should be to subtract 28, 56 or 84 from the last 2 digits of the year. Adding 25% to get extra numbers is amazing. Wish I knew why it works

[@gardeningwithhamzaandmuaz9385]

It's simple, really. See, a normal year has 1 odd day, and a leap year has 2 odd days. So, let's take the example of a period of 4 years. In those four years, one is bound to be a leap one. (Note that 25% of 4 is 1.) So, we have to add 2 odd days for that leap year. (But we have already counted 1 of those 2 days in the main 4 years.) So, we will take 4+1 (25%) = 5.

[@gardeningwithhamzaandmuaz9385]

Basically, 25% of a period of years are leap years, which have 2 odd days, so we have to add those extra odd days, which we can add by calculating 25% of the years.

[@helenbirhane5537]

You are the best maths trick teacher in youtube thank you

[@timothybai-nielsen7728]

you are by far the easiest to understand math teacher!

[@maureenjohnson3053]

Show day of week on March 12 1975

[@user-ix1bt3ox4s]

個人認為，你們是目前世界上最好的數學天才。多謝分享。多謝。

[@mathOgenius]

Thank you !

[@yuvnag.3047]

I have recently found your channel have to say You are dammmmm amazing 👏😉😀

[@mathOgenius]

Thank you !

[@manoranjansahoo2916]

gr8 input. i like the most .keep posting

[@padfootkriss5373]

YOUU ARE A GENIUS. THANKYOU SO MUCH

[@firozahossen8307]

Shall try to do stay blessed thank you for sharing from Sri Lanka

[@rinkusaha2891]

Congrats on 100k bro

[@abhitojsingh1888]

Amazing trick sir thanks 😊

[@nagaluvijaya3232]

Exellent trick thanku so much

[@user-vo2oq9dl2j]

This is so powerful Thanks sir

[@umabitr8157]

Superb calucation thank you

[@ShreyanshDixit8]

Your voice Is so relaxing and you explain so calmly. When I watch Your videos I feel like I am meditating and I learn so much

[@TRENDINGinPODCASTS]

You are the best in mental math

[@Letsbecurious29]

Solving math in mind is make us feel cool.

[@fashionista_2009]

Maja aa gya😁 Bhut maja aa rha hai ase tricks sekh k Mehrbangi sir ase bedio upload karna k lee a🙂

[@thecalendarninja]

Jan 1, 2030. My method requires a bit more memorization but the payoff is super fast and easy calculations like sometimes less than one second maximum 2 seconds! For me a date like Jan 1 is a prememorized value of -2, 2000-2099 has a century code value of 2, and the year 30 always has a value of 2. So, in any order i add -2+2+2=2, or even more advanced, looking ahead that the -2 cancels out with any one of the other the values of 2, so just 0+2=2, or simply 2 without considering the cancelled values, so Tuesday! And whenever leap year, no need to worry about odd days or anything special just subtract 1 from the final answer if January or February, March thru December no changes are necessary.

[@thewanderers7208]

Great.Keep it up😊😊

[@umarchetty1]

i love rhis video...thanks bro

[@nazmusshakibmuhurto9494]

Thank you sir ❤

[@pythoneer8787]

Good stufff man

[@harikrishnan-iw8vv]

Good work sir 😍

[@victorbiswas7820]

You are just awsome

[@chaitanyachintabattina972]

Superb man

[@facto_hub8412]

Thanks man😊🎉❤❤

[@sirigirisairam3472]

Salute to you sir....

[@thecalendarninja]

I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century. Example: Which month or months did Friday the 13th fall on in 1899? 1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th. So, 2+13+x=5 (Friday) x=4 because 15+(-10)=5 -10+14=4 Mod7 arithmetic Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October. If the question changed to what were all of the Fridays in January and October for example in 1899? We can say "the 6th, 13th, 20th, and 27th" If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen? We can say "only in 1893 and 1899" In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.

[@m09527]

Name checks out

[@ravitejacoolboy881]

Nice mr Paryag Sharma sir ❤

[@wokwokwokwokwok]

this man is a genius himself

[@user-hk7pu7ti6u]

Wow awesome good idea 💡!!!

[@yan-rp5sq]

Thankyou sir 😊

[@fortheloveofmathsandphysic9749]

OMMS ( Oh My Maths and Science) it is literally amazing trick ( your trick dude)

[@leavemealone5683]

I had been learning this from cls 8 in my Mental Ability Test (MAT) in my coaching institute.

[@sushantamallik3080]

Amazing sir

[@kaiji2542]

I wanna ask if there is a fast method for multiplying, adding, and subtracting decimals

[@humanz222]

Bhaiya :Math is everything !!!! Me : same ..... We love maths 🙏🙏🙏

[@lonely-girl920]

Yeah army😁

[@humanz222]

@@lonely-girl920 😂😂😂 yups 💜

[@blessingezeani756]

you are so good

[@ansar311]

Thank you very much sir we need for 21st century only cuz we may not be alive for and further calculation😂😂 very well explained ❤

[@reiinarzinyday2259]

amazing ! thats all i may say

[@mprasanna6939]

Thanks

[@gobinadhsreyas]

Dec 26 2020..first method.. Reminder is 4..but in calender its different

[@dhruveshjaithwar7927]

December code is 4 and the date is 26 so the total is 30. Now 25% of 20 will give 5.25 which is 5, so 20+5=25/7 gives 4. The total is 30+4=34/7 gives a remainder of 6 which is a Saturday

[@abhinavkumar._.08]

Plz make a series on reasoning

[@sweetaniket]

may i say one thing (if u don't mind)?... hey MR what r u doing here!!!!??? u must go to participate the upcoming international mental competition, not just to win but also to show your fantastic ability of memorizing...

[@aayushmanupadhyay6837]

Shut up

[@naaamerleyamartey7026]

You're indeed Superhuman 🥰😃😀👍👍

[@bnwgaming5076]

Nice video

[@sunitamishra8783]

You are super OP

[@yvandaniel8050]

Thanks!

[@mathOgenius]

Thank you for the super thanks !

[@narasimhasolinghur3390]

Sir, Your skill is Awesome.Appreciations. I have still an easier method by which we can calculate 20 queries in just 5 minutes all by mental calculations. How much time you will take by your method? Please reply. Thank you.

[@thecalendarninja]

I just simply memorized all 366 possible dates as a value from -3 to 3. Then I just add that to one of 4 possible century codes of 2,0,-2, or 3 and finally add that to a prememorized value for each of the 100 years from 00 to 99. For example, my birthdate of March 19, 1982 goes: -2+3-3=-2 so Friday! Or shortcutting, i just cancel the 3 and -3, and -2 is Friday!

[@marrefmagic]

i wanna learn you way

[@DeepakisDemigod]

You Legend

[@anjusharma7583]

UR amazing

[@ultimategaming8873]

Hello bro nice video

[@chandrahasreddy1729]

Can you give some tips tricks for fast multiplication and division of point numbers (like 1/99=?)

[@yuvrajgarg8691]

1/99 is so easy it's----0.0101

[@parveshsehgal901]

You can do this easily by taking 1 as 0.9 repeating

[@rituparnabc2024]

Yessssssssssss

[@EAGLEXOP]

I like that how you talk English it is like quitely speaking English

[@icebear9427]

Oh My Goodness This Guy Is A God For Me Cuz I Used to Hate Math​ and now I love it. Thanks! My guy

[@LalitKapoor1]

So how do you calculate the day before 1752? How do you adjust for 11 days as you mentioned?

[@abingaming4274]

Add 11 to the final answer you got it

[@shekharchowdhary]

❤

[@vaanshlohia4480]

Basic Method: 2012 for eexample. 12 x 0.25 = 3. Leap year so 2. 2 + 12 = 14. 14/7 =2. 2 is code for tuesday. But calnder for jan 1st 2012 shows sudnay?

[@meyerlundeng1574]

How do you get the REM value

[@daviddobosz7418]

How do you know what year is a leap year just be looking at the date?

[@jagdishkarande474]

Too much to memorize. About 65 years ago this is what I had learnt in school. Today’s Tuesday June 13, 2023. We want to know the day in 2015. Step 1. 2023-2015=8 Step 2 number of leap years: Take the year before 2015 which is 2012. 2020-2012=8 8/4=2 leap years Add to step1. 2+8=10 10/7 =1 and remainder 3. Go back 3 days from today Tuesday. Answer is Saturday. I’ve done this for the viewers. Hope this helps.

[@kazawolf]

Hi great video. What do I do when numbers are very low, like 2000-2005? I get fractions when I divide by 7 at the end

[@12vibhor34]

Do not divide just take the exact number. Like take 5 from 2005 and add the month code and date in it.

[@chinmayaprakash]

@@12vibhor34 you forgot to add 25 percent, rounded off to the lower integer.

[@animalshowwithhimank7397]

Wow

[@soulsounds5975]

Sharma ji ka ladka maths mei awwal hai!!

[@dhruveshjaithwar7927]

How to find dates before 1752 considering the eleven day lag?

[@danieltavera1748]

@mathOgenius hi i love your videos! verry cool but im trying to do one of my siblings dates which is july 20, 2010 but im getting monday but the calender says its tuesday could you please see if im doing something wrong thank you!

[@mathOgenius]

year code is 5,month code is 5, date is 20 so sum is 30 and dividing by 7 gives remainder 2 for Tuesday.

[@yacinebob4639]

@@mathOgenius what about 18 december 2003? Is the year code 0?

[@NalenGamez]

@@yacinebob4639 its 3

[@Milkman4279]

I learned this in 1997. But the month numbers are different. I think maybe it's because this way is based on the 2000's, and the way I learned is based on the 1900's.

[@creatorPadmanaban]

According to Gregorian calendar... The same calendar repeats every 28 years not 400 years once. Check them.

[@sasukeuchia4316]

Can you explain 27 September 1992,it doesn't work for me. It shows Thursday repeatedly

[@sarahanderson165]

How are you so good at math

[@kishorecoelho3186]

How would I calculate the day on 1 February 2080 when all codes add up to less than 7

[@glockglock2820]

Can you do July 4, 2024. It's a leap year, so based on your computation, you have to deduct 1. So 24 x 1.25 = 30, then subtract 1 which is = 29. Then 29+5+4 = 38. 38 divided by 7 = 5 with a remainder of 3. So it should be Wednesday. But actually, looking at the calendar, it is actually Thursday. Can you explain further? Thanks!

[@krystlea5210]

do u have ways to solve linear simultaneous equations ?

[@mathOgenius]

yes there is a video on this channel on word problems , look at that

[@PanSokhom]

💖💖💝

[@jobenpats]

Sir, how about years ending in 00 - 03 such as 2000 - 2003?

[@cash_t0192]

how do i know if its a leap year?

[@mathandpubg]

So should we do no Know??

[@kishorecoelho3186]

How do we calculate the day when all codes add up to less than 7. Ex: 1 Jan 2080. Thanks

[@sarahanderson165]

😊

[@samayasaadhakarus757]

For Year Code And For Example 2061, You Just Found 25% Of 61, And You Didn't Divide It By 4... 25% Of 61 = 15 and 61/4 = 1 61 + 15 + 1 =30 77/7 = 0 0 Will Be CODE For 2061

[@dhruveshjaithwar7927]

Finding 25% of a number is the same as dividing the number by 4 because 25% is 25/100 which when simplified is 1/4 which is dividing a number by 4. So, 25% of 61 or 61 divided by 4 is 15.25 which is 15 so so 61+15= 76/7 gives the remainder of 6 so the year code for 2061 is 6

[@DanielGonzalez-yo4wn]

The gregorian calendar was actually created on 1582

[@gayfrogsociety]

Do you always -1 on the day when its a leap year? I was trying my friends bday and kept getting a day off, it was a leap year.

[@fazle47]

I am guessing the month table already accounts for -1. And I think -1 applies for jan and Feb according to the table

[@fazle47]

In the example he used January 1st 2032, there he had to subtract -1. You would also need to do it for 1st of February 2032. Basically for any date on January and February in 2032 you would need to subtract -1. Now move on to the rest of the months for example March or April or May in 2032, you will notice that you don't need to subtract -1 anymore. So I think if you are using the month table table shown in the video you don't need to worry about -1 as the -1 is mentioned in the table

[@KittuDinogaming008]

Happy

[@spideyonboard]

i love you