Thank you so much, Sir! It really helped to understand where the formula came from.
@G9Gupta7 ай бұрын
One question: @7:33 Can we just combine the formulas like this? I think we played it save as results matches but ideally it should be solved taking mothion of both observer and source But again this will ha0pen if superposition principle can be applied here because of linear nature of equations But ya thats a good way to solve equations if you good intuition thanks 😅
@robertsimpson44123 жыл бұрын
Nice video but I think you need to add some more explanation about why you keep the wavelength constant in the 2nd case. It's quite common to see students mix up the two cases.
@sebcodestheweb9385 Жыл бұрын
Now this is a teacher I follow
@diatribeeverything4 жыл бұрын
Great video. You only lost me at one point. Can you please explain how you combined your two equations, in white, because it looks like you didn't set them equal to each other... as that would cancel frequency. It's like you only multiplied a part of them. Can you give me an example of this move that is simpler? Thanks! Awesome shirt btw!
@PhysicsHigh4 жыл бұрын
Thank for the feedback. In answer to your question...It's not so much that they add numerically. Instead the final formula can show both situations at the same time. In fact, the two are multiplied, as you suggest Think of this way.... Let's make EQo is the equation where observer is moving and EQs is the equation the source is moving. f' = f(EQo) but the source is moving too f'' = f'(EQs) So you have f'' = f (EQo)(EQs) Hope that makes sense
@andrewc39374 жыл бұрын
@@PhysicsHigh This will make sense if you use f'' instead of f' in your second equation.
@user-jh3kz7dp2z3 жыл бұрын
@@andrewc3937 well that's kinda not how it works because both formulas are applied simultaneously
@bernardolinares41623 жыл бұрын
@@PhysicsHigh I understand how the result is achieved mathematically, but I don't see the motivation behind combining the equations. I'm teaching this in high school, and I have a physics degree, but every once in a while I need a refresher. From my understanding, the observed frequency with respect to the observer (f') ends up being the observed frequency with respect to the source (f''). From there the solution is obvious, algebraically. However, I want to come up with a good and simple explanation as to why f'' is the one that is important. This is clearly a significant result because it can be applied in all situations involving the Doppler effect.
@MrYahya01013 жыл бұрын
Combining them in this way: f' = v/wavelength' = v/(v*T - vs*Ts - v'*T') gives => f' = fs*(v+v')/(v-vs). In other words, you have to account for the observer moving and the source moving using f' = v/wavelength'. As you said, multiplying them doesn't give the final equation.
@felistus34392 жыл бұрын
you the man I'm ready for my test tomorrow morning❤
@lvenE-kx4dq6 ай бұрын
I have a question about converting Vsource *time /λ to Vsource / Vwave, as the time might not equal the time taken for the wave to move for 1 period, so can it be converted?
@jakeaustria5445 Жыл бұрын
Thank you so much for this. I need it for a contest.
@MrYahya01013 жыл бұрын
I don't see why in one part it's f' = v/wavelength' and in the second it's f' = (v + v')/wavelength (I'll use v to denote velocity of the wave). Basically. the second equation indicates there will be no change in the perceived wavelength, just a change in the velocity. And I'm not sure if that's accurate. If you use f' = v/wavelength' for both, you still get the same equations. For the first one f' = v/ (v*T - vs*T) (which is what you have) and for the second one f' = v/(v*T - v'*T') => f' = fs*(1+v'/v).
@ayasaki.pb_7873 жыл бұрын
wavelength was constant in second case because the source stationary. The moving observer preceive faster wave speed over the same distance.
@alfinbarouq552 жыл бұрын
Thank you sir, it really helps me out
@preparingforundergraduatep42564 жыл бұрын
why process frequency is = velocity of wave / process lambda (why velocity of wave?)
@verysimplephysicsinthamil14362 жыл бұрын
Sir,your class is fantastic..sir I am a taecher of physics teaching class 11 and 12 ,I am also using digital pentablet for recording videos for presentation,could you tell me what are all the hardwares and software you use for recording...
@mirtacota Жыл бұрын
Thank u, excellent explanation!
@joshuachama84 жыл бұрын
This was helpful. Thank you.
@PhysicsHigh4 жыл бұрын
Glad it was helpful!
@robertvandegraaff22602 жыл бұрын
Thank you very much, Sir. Very clear.
@stevecorlew71872 жыл бұрын
Would be interested in what app you use. Would like to hear the doppler effect on geometric shape, speculation an elipse. Great video 👍🏽👍🏽
@truth302 жыл бұрын
why we say t =T in d=vst because it is time taken for source to cover some d,not for wave to cover lamda
@georgekordas61843 ай бұрын
Make the same analysis for both. Not beginning from for λ' in the first case and from the T' in the second
@TheFixer6933 жыл бұрын
I do not understand why you divided for the final stage, the coefficients of the frequency of the wave.
@DdoubleB033 ай бұрын
me neither
@kashifuddinahmed83833 жыл бұрын
I used to love doing physics in high school but it's been too long now don't remember much heck even my basic math is messed up.