How to find a number of bars in column | column'ல் எத்தனை கம்பி போடுவது என்று கண்டுபிடிப்பது எப்படி?

[@nottoday9014]

Vera level la teach panringa sir.ivlo naal unga videos lam KZbin la recommend eh pannala

[@civilonlycivil]

Thanks for the feedback my dear friend 🥳

[@varunkarthik6024]

Arivu kanna Theranthudenga ivloooo Yelimaiya ...Thank you brother keep Teaching always...na ungala en master ah select panniten 😅♥️🙌🙌🫂🔥🔥🔥🔥🔥

[@bharathrambabu]

Supera solli kuduthinga gurunatha nee valga

[@ashoksethupathy2189]

Kindly do videos related to rebar drawings, like how to draw rebar in pile cap, pier, etc

[@civilonlycivil]

Sure we will discuss about pile and pile cap soon☺

[@vigneshbalaji591]

Good explanation bro..oru building manual ah structural design panni podunga bro

[@rathishb4849]

Bro....Elevation low budget la super ah irukanum athuku ethuna tips video podunga

[@sharanr1569]

💆‍♀️finally i got your videos

[@fgasathish288]

Andha load calculation pathiyum podunga bro .........detail ah explain panni

[@civilonlycivil]

Sure sure 🥰🥰.

[@fgasathish288]

Tq bro

[@dhileepan8706]

Super bro Load calculation podunka

[@civilonlycivil]

🥰🥰

[@KumaranMuthaiya]

Clg la kuda ipdi explain pannala. 👏👏👏

[@laadulabakkudossmemes1360]

Roof concrete podrathu...Ready mix concrete(RMC) best'ah illa Hand mix concrete best'ah. Which is economical??? Video podunga bro...its usefull to everyone

[@civilonlycivil]

Sure 🥰🥰

[@SathishKumar-th3bl]

Bro both cost will be similar only 5k difference will come. Manual mixing is best from my view

[@samvignesh620]

Super explain bro thank you so much

[@ramaaravinth004]

spr bro very useful keep posting these kind of quality contents

[@civilonlycivil]

Thanks for the feedback my dear friend 💞

[@ashoksethupathy2189]

Great brother

[@sendilpadu5072]

Very very useful vedio sir thanks how we can find the loud in the colum

[@civilonlycivil]

I will explain in another video 🥰

[@SamuvelK]

Centre line method estimate video podunga bro

[@fgasathish288]

Bro super bro

[@subramaniyanshanmugam6186]

Thanks bro hru 🎉❤ kovilpatti garpender❤

[@rameshmmr4848]

Bro 800kn load eppudi one column ku varuthunu oru video podunga bro

[@mohana3983]

நன்றி தம்பி

[@nisha536]

Structural drawing epdi podanum nu A to Z fulla solli kuduga anna

[@civilonlycivil]

Kandippa try panren bro 🥰

[@Manidhan-om2ih]

Bro 6* 9* inches column podalamnu sollirukanga appadi podalama illa 6* 12 podalama 6 rod sollirukanga (4x12mm 2x10mm ) Hollow bricks la katturom

[@civilonlycivil]

Illa, puriyala..

[@Manidhan-om2ih]

1/2 * 3/4 size column podalamnu mester solluranga appadi podala illa 3/4 * 1 feet podalama column la 4*12mm rod 2*10mm rod podalamnu sollirukanga

[@SathishKumar-th3bl]

@@Manidhan-om2ih minimum column size 9"x 9" ithuku keela poga kudathu.

[@SathishKumar-th3bl]

@@Manidhan-om2ih athey maari column ku minimum vertical bar 12mm provide pananum.

[@SathishKumar-th3bl]

@@Manidhan-om2ih Mullion ku matum 10mm use panalam athu wall length 3m ku mela pogum pothu Mulion provide panuvanga. Athu column illa but appdi act aagum for additional support.

[@Keerthi-nt2ko]

Bro same steel design beam ku oru video podunga bro

[@nagendranradhakrishnan4764]

Storage of building roll in column pl explain.

[@learncivilengineering2927]

bro estimation series video podunga bro neraiya bbs laam pathi solli kudunga bro

[@civilonlycivil]

Kandipa bro.. 🥰🥰🥰🥰

[@PradeepPradeeppitchai-xd9sh]

Tq you bro.

[@rockyrajesh317]

Bro complete structural design for residential building notes...pdf..book .... Ethachu iruka bro..?

[@manikandanmani-zb1tl]

ப்ரோ , காலத்தில் stirrups கொடுக்கும்போது நடுப்பகுதியில் அதிகமான spacing,கீழ் மற்றும் மேல் பகுதியில் குறைவான spacing ஏன் கொடுக்கிறார்கள்

[@civilonlycivil]

Shear force supports la adhingavum, mid space la kammiyavum irrukum so apdi tharanga..

[@manikandanmani-zb1tl]

Ok bro, அந்த stirrups இடைவெளியை எவ்வாறு கணக்கிடுவது?

[@civilonlycivil]

13:06

[@SathishKumar-th3bl]

@@manikandanmani-zb1tl roof height la irrunthu l/4 split pannikonga antha length ku mattum stirrups spacing 100mm maintain panunga both floor and roof L/4 la balance area la stirrups spacing maximum aa irukalam but not exceeding 200mm.

[@SathishKumar-th3bl]

Example floor to roof height 3m 3/4 is 0.75metre So floor bottom to 0.75metre ku close spacing of stirrups provide pannanum. Same roof side also.

[@vijaycivil3987]

Super teach

[@risvanahamed9113]

Oru slab oda dead load yeppudy calculate pandrathu athuku column yeppudy Design pandrathu

[@saravananbe1830]

Super bro Footing design videos podunga

[@civilonlycivil]

Kandippa

[@dhanushkodi7861]

Bro 12"×9" column la 15 feet distance vidalama..?

[@civilonlycivil]

15" x9" safe ha irrukum bro!

[@Ravismadurai]

Bro chat gpt la intha answer varuthu bro kongam clarification Pannu ga bro Steel reinforcement for column  Calculate the diameter and number of steel reinforcement required for a column size 230 × 300mm carrying an ultimate axial load 800 kN and the great of the concrete is m20 and Fe550d To calculate the diameter and number of steel reinforcement required for the given column size and load, we need to perform the following steps: Step 1: Calculate the cross-sectional area of the column. The cross-sectional area of the column can be calculated as follows: Area = Width x Depth Area = 230 mm x 300 mm Area = 69,000 mm² Step 2: Determine the compressive strength of the concrete. The grade of concrete given is M20. According to the IS 456:2000, the characteristic compressive strength of M20 grade concrete is 20 N/mm². Step 3: Determine the yield strength of the steel reinforcement. The grade of steel reinforcement given is Fe550d. According to the IS 1786:2008, the characteristic yield strength of Fe550d grade steel reinforcement is 550 N/mm². Step 4: Calculate the area of steel required to resist the given axial load. The area of steel required to resist the given axial load can be calculated using the following formula: Ast = (Pu x 1000)/(0.87 x fy) Where, Ast = Area of steel required (mm²) Pu = Ultimate axial load (kN) fy = Characteristic yield strength of steel reinforcement (N/mm²) Plugging in the values, we get: Ast = (800 x 1000)/(0.87 x 550) Ast = 1687.29 mm² Step 5: Calculate the diameter and number of steel bars required. Assuming that we will use only one steel bar, we can calculate the diameter of the steel bar required as follows: Area of one steel bar = (π/4) x d² where d is the diameter of the steel bar. Plugging in the values, we get: Area of one steel bar = (π/4) x d² 1687.29 = (π/4) x d² d² = (4 x 1687.29)/π d² = 2151.05 d = 46.37 mm (approx.) Therefore, we can use a steel bar with a diameter of 46 mm. Now, we can calculate the number of such steel bars required as follows: Number of steel bars = Ast/Area of one steel bar Plugging in the values, we get: Number of steel bars = 1687.29/((π/4) x 46²) Number of steel bars = 3.52 Since we cannot use fractional steel bars, we need to use 4 numbers of steel bars. Therefore, the diameter of steel reinforcement required for the given column size and load is 46 mm and the number of steel bars required is 4.  Calculate the 12mm diameter and number of steel reinforcement required for a column size 230 × 300mm carrying an ultimate axial load 800 kN and the great of the concrete is m20 and Fe550Sd 2 / 3 To calculate the number of 12mm diameter steel reinforcement required for the given column size and load, we need to perform the following steps: Step 1: Calculate the cross-sectional area of the column. The cross-sectional area of the column can be calculated as follows: Area = Width x Depth Area = 230 mm x 300 mm Area = 69,000 mm² Step 2: Determine the compressive strength of the concrete. The grade of concrete given is M20. According to the IS 456:2000, the characteristic compressive strength of M20 grade concrete is 20 N/mm². Step 3: Determine the yield strength of the steel reinforcement. The grade of steel reinforcement given is Fe550Sd. According to the IS 1786:2008, the characteristic yield strength of Fe550Sd grade steel reinforcement is 550 N/mm². Step 4: Calculate the area of steel required to resist the given axial load. The area of steel required to resist the given axial load can be calculated using the following formula: Ast = (Pu x 1000)/(0.87 x fy) Where, Ast = Area of steel required (mm²) Pu = Ultimate axial load (kN) fy = Characteristic yield strength of steel reinforcement (N/mm²) Plugging in the values, we get: Ast = (800 x 1000)/(0.87 x 550) Ast = 1687.29 mm² Step 5: Calculate the number of 12mm diameter steel bars required. We can calculate the area of one 12mm diameter steel bar as follows: Area of one 12mm diameter steel bar = (π/4) x d² Area of one 12mm diameter steel bar = (π/4) x 12² Area of one 12mm diameter steel bar = 113.1 mm² Now, we can calculate the number of 12mm diameter steel bars required as follows: Number of 12mm diameter steel bars = Ast/Area of one 12mm diameter steel bar Plugging in the values, we get: Number of 12mm diameter steel bars = 1687.29/113.1 Number of 12mm diameter steel bars = 14.92 Since we cannot use fractional steel bars, we need to use 15 numbers of 12mm diameter steel bars. Therefore, the number of 12mm diameter steel reinforcement required for the given column size and load is 15.

[@civilonlycivil]

in video what did i explain sample the AI Repeats. 1. The load acting on the column, 2.Area of column you will get ast. with the help of ast 3. area of bar using. proved the bar as per ast requirement

[@yasaramanisha6285]

Spacing for beam also same method bro????

[@civilonlycivil]

column ly spacing kandupudika innum silla methods irruku heavy structures vera mathiri dhan spacing provide pannanum.

[@spmanicivil001]

How to calculate p value

[@ramasamyv7697]

Bro main rod ahh column la entha direction la kudukanumnu sollunga bro.. Example ahh ippo oru 1x.75 post kku 6number of 12 mm kudukuromna atha 0.75 pakkam kudukanuma illa.... 1 pakkam 3 rod kudukanuma sollunga bro... Plz

[@civilonlycivil]

Perpendicular to Longer span (unsupported length). 4 side la entha side la support oda distance adhigamo athuku perpendicular ah Rebar vara mathiri pathukalam.

[@ramasamyv7697]

Bro atha pathiyum detailahh video podunga bro....

[@civilonlycivil]

@@ramasamyv7697 sure sure

[@ramasamyv7697]

@@civilonlycivil thank u bro

[@manigandan2016]

Bro job vacancy eruntha solunga

[@rajavinothkumar1960]

Sir teach column position

[@civilonlycivil]

sure

[@Thamaraiselvan-jm2ze]

Do more videos

[@shalomp1861]

One KN என்பது எத்தனை கிலோ

[@ramasamyv7697]

Ninga use pannirukka formula axial loaded column kku mattum than use akuma

[@civilonlycivil]

Apdi illa, ella column ku ore formula dhan, but corner illa side la vara column ku unga load la irrunthu some % of the amount load increase pannaum. 4 corner column mella vara load kooda, athanodala irrunthu 15 to 20 % load oda add panikanum , side la vara column ku mella vara load kooda athanoda load la irrunthu 11 to 15% ungaloda load kooda add panni kanum. Then atha P (load) ah unga formula la use pannanum.

[@vigneshbalaji591]

@@civilonlycivil bro center la vara columnku thana load athikam varum corner la irukara columnku kammiyathana varum?

[@civilonlycivil]

@@vigneshbalaji591 most of the case la apdi la dhan, but water tank la vara apo corner column hum athigamana load ah handle panna vendi irrukum. Corner column ku moment aagra thamai athigama irrukum adhanala antha load oda antha percentage of loads ah addition pannanrom.

[@vigneshbalaji591]

@@civilonlycivil nice explanation bro .. detailing ungala maari solla mudiyaathu..oru building manual ah load calculation panni video podunga bro

[@civilonlycivil]

@@vigneshbalaji591 thank for the feedback bro i try my best. 🥳

[@fakrudinahmed5141]

Boss i will pay ur fees can u teach me design

[@civilonlycivil]

Actually I was making a course, soon I will announce. 💓