How to Find Real Zeros of Any Polynomial Function

  Рет қаралды 12,356

Mr H Tutoring

Mr H Tutoring

Күн бұрын

Пікірлер: 21
@JadeLivao
@JadeLivao 21 күн бұрын
finding real zeros of a polynomial with synthetic division in a super approachable way. The step-by-step walkthrough makes the process clear and easy to follow, perfect for anyone tackling this topic!
@yassertariqvideo
@yassertariqvideo 29 күн бұрын
Thank you the refresher. I am glad I started 2025 with your video, happy new year.
@Calculas4physics
@Calculas4physics 4 ай бұрын
Make a series on calculs please sir
@jacobbelury3417
@jacobbelury3417 4 ай бұрын
This was in algebra 2 for like 1 week barely a day lmao
@steveschmidt5156
@steveschmidt5156 4 ай бұрын
Outstanding. Thank you.
@Unkown-Identity-h4u
@Unkown-Identity-h4u 3 ай бұрын
Thank you for this task. If you reduced it to a quadratic funktion, the abc-formula is also an option.
@kenda-o3o
@kenda-o3o 2 ай бұрын
I am an Arab student and I have benefited a lot
@anestismoutafidis4575
@anestismoutafidis4575 4 ай бұрын
2•1^3 +11•1^2- 7•1 -6 =0 First zero-number=1 (2x-7/x)•(x^2+5,5x)+32,5 => (2x-7/x) 2•1,87 -7/1,87=3,74 -3,74=0 Second zero-number: 1,87 (x^2+5,5x) (-5,5)^2 +5,5 • (-5,5)=0 Third zero-number= -5,5 Zero numbers{ -5,5; 1; 1,87}ℝ
@kileyslife7541
@kileyslife7541 Ай бұрын
Thanks very much. I missed class so I was super confused on the hw
@charlesrobinson3977
@charlesrobinson3977 4 ай бұрын
You say this method works for "any polynomial function", but don't you mean "any polynomial function with integral coefficient"?
@gregnixon1296
@gregnixon1296 4 ай бұрын
My school system kicked the rational root theorem to the curb last year. Sad days.
@rokrok27
@rokrok27 2 ай бұрын
This is rational root theorem , no ?
@josephshaff5194
@josephshaff5194 4 ай бұрын
👍
@davidnewell3232
@davidnewell3232 4 ай бұрын
Mind your "p"s and "q"s.
@NameFirst-jv9gj
@NameFirst-jv9gj 4 ай бұрын
😂😂😂
@geremymuccleswood307
@geremymuccleswood307 4 ай бұрын
imagine p is 100 and q is 16…
@carultch
@carultch 4 ай бұрын
In that case, your candidates for roots would be: 1/16, 1/8, 1/4, 1/2, 5/16, 5/8, 5/4, 5/2, 1, 2, 4, 5, 10, 20, and 100 And the negatives of all of the above. Usually, you try to use other clues as well, such as Descartes' rule of signs, and the sum and product of the roots, which can be directly determined from the b-term, the final constant term, the a-term, and whether the degree of the polynomial is odd or even. This allows you to narrow down your search for possible roots. Polynomial roots in general, will add to -b/a, and will multiply to k/a for even-ordered polynomials, and multiply to -k/a for odd-ordered polynomials.
@Mathgoddesssupports
@Mathgoddesssupports 4 ай бұрын
❓🙋‍♂️❓Why in the synthetic division do you multiply and then *add*? I see that it works but don’t understand why it does since division generally involves multiplying and then subtracting. TIA for anyone’s clarification.
@carultch
@carultch 4 ай бұрын
What synthetic division does, is replace operations such as subtracting a negative, with adding a positive. It recognizes the self-cancellation of the negative signs, and replaces it with the more intuitive operation of simple addition, and simple multiplication. It makes it so you don't need to guess terms, but sets them up in a more straight-forward method of calculating them
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