On the C have infinite solution because, period of i, but on the R no solution.

There's no solution if we assuming that x is real number. Anaway if x is complex number therse's solution.

When you square the two sides you always have to check result, and in this case is wrong...therefore NO SOLUTION

I forgot math

No real solution

A

For values of x greater than is valid so no solution

No real solitions.

Just differentiate A(x) and you will find that x=1000 when it's derivative is zero ...

X=1/2

No solution. √a is defined as the non-negative b∈ℝ for which b²=a. mrhtutoring proved that if a solution exists, it must be -1. Substituting x by -1 on the left hand side of the equation yields √(3×(-1)) = √(-3). There is no b∈ℝ for which b²=-3. That's why the equation has no solution. Complex numbers do not even enter the scene.

À. -1

its 1i

When graph touches 2 points will be Function or not function?

Technically its root3 i

B

A, it should solve out to (forgive me I have no radical/root signs in my keyboard) root3 i = root3 i

Isn't a easier way to do this, sin(22)= x/6.3, 6.3sin22=x

difficulty level american m

The answer should be negative 1.

So i * sqrt(3) ?

10.2

It depends on if you allow your solutions to be in the complex plane.

-1 is the answer no matter whether you allow C or not. Why not square both sides and get real answers?

B

In its broadest context, i.e. complex numbers, it does have -1 as a solution.

I would say; x=-1 is fine,.. regardless considerations about complex numbers. The solution x=-1 satisfies the only relevant criterion about the equation, being equal on both sides of the equal-sign. That someones become nervous about negative roots is only a problem for this person, not for this equation.

A

That's a really cool way to do it

Missed a chance to call the video "Complex Problem"

-1, since 3i=3i

Answer is (a) X=-1 because the question is if both sides are equal. If the question was to solve then the answer would be (b) no solution.

I'm still like wait, you can just get rid of one x and decrement the coefficient of the other through SUBTRACTION? I've been thinking about it and I still don't see why not, but part of my brain is going "coefficients are resolved through division; terms separated by addition or subtraction must be added or subtracted. All else is _verboten."_ Someone must have put that there. The further I get from actively practicing algebra, the weirder it gets. Just plain old, small a algebra. Although leaving aside the complex plane, I did notice instructor was AWFULLY breezy about the +/- aspect of even radicals and exponents.

when you square root the two sides of the equation, the next line must be absolute value on both sides

Both of them are correct answers, because sinx = 0.5 at both of these.

A

The answer would probably be -1

No solution.

No solution if real, -1 if imaginary

When we square both sides, we can change the sign of the LHS or RHS. Like here, He does √(x-2)² but (x-2)² is equal to (2-x)² so we can solve it like this: √3x=√(x-2) √(3x)²=√(x-2)² 3x=√(2-x)² 3x=2-x 4x=2 x=½ But if we plug in a value of x, we see that it is an imcorrect solution. We can do the same with 3x and write (3x)² as (-3x)². Hope this helps! (Edit:I made a mistake thanks to the comments for correcting it lol)

Since the question has no restrictions, therefore its A.

-1 as this fits,…….in my Ass !

Solving tricky problems like this always makes me appreciate the value of having reliable resources for practice. When I needed help with tough problems, I turned to online platforms like SolutionInn. Their study tools helped me break down complex concepts into more manageable pieces. It’s definitely a game-changer for anyone tackling challenging subjects.

x = -1. The concept of imaginary numbers is a thing. Doesn't matter that you're in middle school or high school where you're not allowed to take the square root of imaginary numbers

No *Real* solutions

maybe a dumb question, but is 0 to the 0 power also 1?

extraneous solution

It’s no solution. By definition of the square root function, the domain is that 3x >= 0 and x - 2 >= 0, meaning that x >= 2. x = -1 falls outside of the domain, making it an invalid solution.

If x=-1, then isn’t it √3i = √3i? So, x=-1 is the solution.

It’s obvious no solution , because there isn’t imaginary number on the line number.