How to find Square Root of Complex Number

[@susanseverance5999]

Your explanation was extremely clear and easy to follow. Thank you for taking the time to make such a fine video. I will be looking for others that you have done.

[@tcs20264]

At 1:45 how b²i² is equal to -b²??

[@neutronzz3543]

@@tcs20264 hopefully your question has been answered but I^2 = sqrt(-1) so if i square a square root it cancels so it's just negative 1 so b^2i^2 =b^2(-1) = -b^2

[@CancerousBlueberry]

This explaination was better than the ones they gave at school zzz

[@jethior]

you are really helping us. thanks sir!

[@MathematicsTutor]

Thanks for appreciation

[@vishwasarora7490]

You have explained very well in comparison to other you tubers. . I liked this way a lot.. THANKING YOU 😎

[@agbortambeferinhoo2807]

thanks much Sir. I'm confused about the second equation in question 1. I thought it is supposed to be. 2ab=-12? please I'm begging you to clarify me how the - sign disappeared in front of 12.

[@juizybabyy]

Exactly why I'm reading the comments, I don't know what made the sign to disappear

[@crystal-hk4dv]

thank you this was very helpful!

[@benjones7059]

Fantastic explanation. I am trying to help my niece with her maths tests. This is really going to help. Thank you so much for posting.

[@MathematicsTutor]

Thanks. Here is related Playlist: kzbin.info/www/bejne/pqOraWV_ish_nKs

[@isaaconyach9401]

love your voice. Great teacher

[@Manish-Goel]

Very good explanation thanks for clearing doubts

[@sciencexanime1020]

this is so cool!!! thank you for making this video!

[@tajammalhussain6605]

Thank you Prof. Anil Kumar. I was a little bit confused about taking square root of a complex number , but now it is clear to me.

[@evandharmasena8688]

explained this lesson in perfection. thank you very much and yes the result with the imaginary number being substituted is very interesting

[@MathematicsTutor]

Thanks a lot for appreciation

[@yuusufyuuman]

Thanks teacher iam very happy now😀, Acroding to before watching this vedio I get i get iget

[@toormalueth513]

Great explanation prof. Thanks

[@AnthonyGudu]

Thank you so much you have helped me alot

[@ugnug]

yo this was a perfect lesson! Thanks so much bro

[@sirdelord02]

thanks that was very very helpful to me

[@purnachandrapatra8298]

Nicely explained.... Thank you sir.

[@MathematicsTutor]

Thanks. Playlist on Complex Numbers: kzbin.info/www/bejne/pqOraWV_ish_nKs

[@cookwithexpressions682]

Thank you, its beneficial for complex analysis

[@yeetyskeety6039]

this was an amazing explanation, thank u so much anil!!!

[@rishabhraj8249]

Sir at 4:45 , square of (a) cannot be equal to (-4), as square of any no. cannot be equal to any negative no.

[@jonathanelmoznino3995]

Thank you, very clear and concise video !!

[@logancardoso6772]

where did the i go from abi when u separated the two equations at 2:13

[@ansukumariece]

Nice explanation🥰🥰🥰🥰

[@k.chriscaldwell4141]

Superb! Thank you.

[@ghotifish1838]

Thank you so much sir, I was at a loss with why the square root of complex numbers have 2 values, when real numbers only have one. Thank you so much sir

[@tcs20264]

At 1:45 how b²i² is equal to -b²??

[@ghotifish1838]

@@tcs20264i is the square root of negative one so if you have i^2 that's equal to negative one

[@tcs20264]

@@ghotifish1838 oh. Thnkz

[@sewwhatsarah]

This was great! Can you do this using Euler’s formula?

[@Caller8194]

NNNNOOOOOOOO

[@subham3260]

Nahh it's a representation of a complex no.

[@marianmarian1091]

amazing explanation and very calming voice! :)

[@MathematicsTutor]

Thanks

[@guillaume6373]

perfect, cheers

[@tcs20264]

At 1:45 how b²i² is equal to -b²??

[@LuanaSilva-rs5yd]

Thank you!

[@mFurb988]

Thank you very much sir, your explanations are clear and concise. I comprehend the relation between imaginary and real numbers better now.

[@trkingdavid4943]

well explained

[@Baummann1]

Although the result may be interesting, isn’t the reasoning up until you sub in values of (a) to get values of (b) only valid if (a) and (b) are real? In other words, a^2 +4 cannot be factorised over the real plane, and thus the other result although coincidentally correct, uses invalid logic to acquire it.

[@itzapeon4505]

you can also convert it to phasor form and find the square root of that then convert it back to complex

[@user-px7yp1yh9i]

We got a^2+4=0 a^2=-4 (as i^2=-1) We can replace a^2=4i^2 And a=+-2i. So we got imaginary number +-2i

[@priyomgogoi6575]

4:37 where is the square root symbol ? it should be a=+- squareroot 3

[@devendrasolanki5911]

nice and to the point explanation sir thank U

[@Iamvillagedestroyer]

How to find the square root of Andrew kolita ?

[@robin3357]

Helpful

[@aanandi726]

Thank you so much

[@archilzhvania6242]

Your written letters look more standard font than my typed ones.

[@juninho5439]

how do you find the absolute value of a complex number that has both a numerator and a denominator

[@pranaykumar5683]

Awesome

[@ranadebray5440]

How do we solve the question - Find All Roots of (1 - i)1/4?

[@priyankabardhan3767]

Sir I want to know the square root of 1-i in form of x+iy.. please teach

[@MathematicsTutor]

Try some questions from this video: kzbin.info/www/bejne/pqOraWV_ish_nKs Thanks

[@vijayvyas5075]

I saw on byjus, they told that +- in front of the bracket will not come.

[@stephanie-wj1th]

I have 5 minutes left in class of taking this test and this damn video is 9 minutes longggggg

[@jenkygoat]

Nice!

[@pitbull2498]

thank you sir

[@lunatic2now40]

2ab=-12??

[@devendrasolanki5911]

is there any short trick for this if it is then plz upload sir

[@SakshamArmstrong123]

yea there is just split the complex number in a perfect square as the square of a complex number can be represented as a^2 - b^2 +- 2abi the given complex number in the video 5 - 12i can be written as 9 - 4 +2(3)(2)i which is 3^2 - 2^2 - 2(3)(2)i which is (3-2i)^2 so you get the answer directly in like 15 seconds

[@Ashutoshkumar-wm2cv]

Thanxx sir,,, its so qualitative explanation,,,..🙏🙏🙏

[@bluebloo5574]

use Euler's formula

[@akmhd]

Very nice explanation. There's one doubt though. When you got the values for 'a' after solving the equation, how did you decide which value is complex and real? Because I get different answers when I did a = 3i and a = 2, instead of what you did.

[@tcs20264]

At 1:45 how b²i² is equal to -b²??

[@bred3620]

@@tcs20264 since I=√-1 so i^2 would be √-1×√-1 which is -1 so (bi)^2 =b^2×-1 =-b^2

[@arnavarora9290]

Which pen do you use???

[@MathematicsTutor]

Will share with you soon. Thanks

[@MathematicsTutor]

Here you can see the Pens: kzbin.info/www/bejne/aHmYZoNsorJ1gpI Thanks

[@arnavarora9290]

@@MathematicsTutor Thanks alot !!!!

[@theindianpublicschoolbabug5532]

How did you directly found out that sir. 😅😅 I have to write factors and then find. Please reply.

[@MathematicsTutor]

a^2 - 9 = 0, you may factor and then get the answer or you can use -3 and +3 with experience. Soon yo will also write it directly. Thanks

[@theindianpublicschoolbabug5532]

Ok sir. Thanks.

[@saravanans581]

Well explained. I like it.

[@Prasen1729]

Technically we do not need to considerthe imaginary solutions of a=2i and a = -2I as z = sqrt(5-12i) = a+bi, where a and b are real numbers.

[@bananadas833]

find the square root of (a to the power 2) +(1/a to the power 2) + 4 i (a+1/a)-2

[@isabelle2873]

Wow u saved me thanks

[@MathematicsTutor]

Check few more questions on this: kzbin.info/www/bejne/pqOraWV_ish_nKs&list=PLJ-ma5dJyAqqImxqXhid9SQxjMyTOx4zj&index=4 Thanks

[@tobiaschapinda6771]

Solve the equation w^2=1+i............how do i solve this question.thank you

[@hfzsymr]

Cant i use the (a^2 + 4 = 0)? give me some explaination

[@neutronzz3543]

he did a^2+4 =0 can factor into (a+2i)(a-2i) which he did use

[@pranaykumar5683]

Nice

[@TriggeredElmo69]

Thank you sir.love your work

[@BhosaleSukant]

I have a confusion sir Is it nessesary to take the first value of a as real number and if yes so the second value is always a imaginary number isit?

[@MathematicsTutor]

We started with a + bi, so b is the imaginary part and a is the real part. a = 3 or -3; Find b for these values. to get the result. Later half is showing that the result will not change even if you use a as 2i. Ignore it, if it creates confusion. Thanks

[@emu-by1zd]

I don't get it how u find a and b

[@Christmas-chan]

Lol

[@BhosaleSukant]

Sir why did u took a=2i why not a=3i

[@MathematicsTutor]

a^2 + 4 = 0 gives that result. Thanks

[@shreyas7749]

Because it's square root of -4

[@BhosaleSukant]

No sir i want ask that how to choose the value between a=+-3 and a=+-2 for futher calculation after factorization of the equation

[@MathematicsTutor]

Thanks, will make a video for you in this regard. Thanks

[@meghanamanjima]

Thank you so much Sir!😃😇

[@khoado3539]

I think it should be 2ab=-12.

[@agbortambeferinhoo2807]

That's my worry too. thank God you also saw this....

[@cedriclow28]

he corrected it later in the video

[@khoado3539]

@@cedriclow28 oh okkkk

[@khoado3539]

@@cedriclow28 thanksss

[@vincentmuchiri5315]

Thank you

[@zekzimbappe5311]

how he did it at 4:18

[@AyushSingh-sg5st]

Take a^4 as k^2 and a^2 as k which forms a quadratic equation. After you solve it input the original values..

[@adirox9595]

2ab=-12 not 12

[@MathematicsTutor]

I have used 2ab = -12 only. Hope that is ok Thanks

[@252-soumyabhattacharjee8]

Find the sqroot of (1+i) without using quadratic formula?

[@alokitaverma5613]

How you got a=+_2i? Its real part

[@pranaykumar5683]

👌👌👌👌👌👌👌👌

[@Keith031]

I’m in 6th grade and doing this lol

[@beautifulaffliction1742]

Keith Carden same, it's easy

[@albertelectron3961]

ans: {+ - (3+2i) , (-3-2i)} is that correct?

[@rupeshwagh5589]

find the square root of complex number \sqrt{8 + 6i}8+6i​

[@Mathefun]

False

[@sierrafairbanks7776]

😭😭😭😭 this helped so much but my answer is still wrong. I officially quit. 😂😂😂😂

[@anshshah8893]

Sierra Fairbanks don’t give up keep trying you will get it eventually

[@shadow-multimedia8098]

Thank you sir

[@MathematicsTutor]

Thanks for appreciation

[@user-xo2hy3wd5x]

thank you