How to find the centroid of simple composite shapes

This engineering statics tutorial goes over how to find the centroid of simple composite shapes. In this case, its a composite shape made up of a triangle, rectangle, and semicircle. We find the overall centroid of this composite shape.
If you found this video helpful, please consider supporting my work on Patreon:
/ engineer4free
Looking for more statics tutorials? Check out all of the videos that I made:
KZbin: • Dynamics
Website: www.engineer4free.com/statics
Looking for practice problems with solutions? I also created a whole set of fully solved statics problems with step-by-step hand calculations:
www.engineer4free.com/statics...
Looking for software? I highly recommend checking out SkyCiv. They make a full suite of online structural analysis software and tools that are useful for both students and professionals, including calculators for beams, trusses, frames, moment of inertia and more. It’s great for checking your work:
bit.ly/skyciv-e4f
Lastly, don’t forget to subscribe on KZbin and join the Engineer4Free mail list:
Subscribe: / @engineer4free
Mail List: www.engineer4free.com/newsletter
Thanks for watching, I hope it helps!

[@MacAlmighty]

This 9 minute video was better than the 3 hours worth of lectures in my statics class. Thank you!

[@Engineer4Free]

Thanks bruh. You can check out all the free statics videos I made at engineer4free.com/statics cheers!

[@magaganemohlekeseedi3093]

@@Engineer4Free understandable

[@Skystrike70]

Thanks dude. Explained it better than the education I'm PAYING for.

[@Engineer4Free]

KZbin University FTW :)

[@Milkisu_u]

wow same. I'm currently studying all the modules the night before my midterms. And I can say i learned a lot more than months worth at school

[@bhimashankarkattimani7074]

@@Engineer4Free hii

[@Luka_c123]

Jesus private highshools suck that bad?

[@yaotlzodoxis9893]

@@Luka_c123 colleg ;(

[@JesusMartinez-zu3xl]

Wow!! I was able to watch the proofs and examples in less time than one lecture. Thank U!!

[@Engineer4Free]

Glad it was helpful!!! =)

[@jamesrand9778]

A lovely little tutorial. Very well explained, good example used. Ten out of ten. Thank you.

[@Engineer4Free]

Thanks a lot James =) =)

[@biblesaurus6862]

First off I appreciate the audio and video quality, and thanks for making it so simple!

[@Engineer4Free]

Hey thanks! I do try to keep it professional 👌👌

[@anthonykolenda6998]

wow great explanation, i guess i can become an engineer on youtube instead of in school

[@Engineer4Free]

hahaha basically... KZbin University FTW

[@anthonykolenda6998]

I think your website is great too, its real nice looking and really easy to use and follow, great job

[@Engineer4Free]

Thanks! :)

[@atulabid5029]

well said

[@mr.j6677]

This was a ton of help! Thank you!

[@Engineer4Free]

Cheers dude, glad to hear it!

[@Riri-qq1bc]

You are literally a lifesaver, thank you so much!

[@Engineer4Free]

Happy to help!! You can also see a few more videos on the topic here: engineer4free.com/statics see videos 58-65 =)

[@contentyouneed7381]

There is special place in heaven for such teachers....

[@Engineer4Free]

Thanks Sohaib 🙌

[@victoryroyal4372]

thanks man you've helped clarify things

[@user-jz8fp3su7c]

this is the best physics lesson i never had b4

[@shosho7067]

your explanation is spot on

[@Engineer4Free]

Thanks!! =)

[@luismoreno5311]

Another great video thank you!

[@Engineer4Free]

Thanks Luis!! 🙂

[@turdshack4228]

48 people DIDN’T find this helpful??? This is what will help me pass the test tomorrow.

[@Tony-ij4kd]

Same here 😂

[@Engineer4Free]

Hope it went well!!!

[@MOATHALSHIBLIvfx]

that was useful .. thank you Mr.

[@Engineer4Free]

Thanks for watching and letting me know :)

[@rajasingh9898]

Now I am your scriber dude... Love from india thank-you

[@Engineer4Free]

Glad to have you Raja! Tell some friends 🙂🙂

[@siteramodel7414]

greatttttt thanx MR this is helpful

[@Engineer4Free]

Awesomeee thanks for the comment!

[@cadorarenielm.9980]

Thankyou idol its Helpful clear explanation than my teacher

[@Engineer4Free]

Happy to help =) the full playlist is here: engineer4fee.com/statics

[@cadorarenielm.9980]

@@Engineer4Free waoh thanks a lot idol👍🤞❤

[@milesthacker2994]

in 9th grade doing this it’s so stressful but you came in clutch

[@Engineer4Free]

9th grade, wow! Thats a record I think.🤜🤛

[@trevorbrooke9946]

9th grade? Bro where you going to school at? MIT high school?

[@wiz10152]

So if (5.08, y) is the centroid, how can the y-coordinate be found? Love your videos by the way, they're saving my life this semester!

[@Engineer4Free]

You can find the y coordinate by doing the exact same process, just switching every instance of "x" with "y"

[@1000billzv]

Hi! Thanks for making these informative videos !! They really help. But I am getting stuck on one concept. How do we know when to use which centroid formula for a triangle ? Why didn't we use the 1/3 b for the centroid as opposed to the 2/3b? What is the main difference? Thanks for all your help.

[@MrMegaomer]

the smaller side I believe you use the 1/3 and the bigger one you use 2/3 when you divide the triangle from the middle

[@Engineer4Free]

Jahh ✌️

[@manishapatel2078]

Could you please upload y-axis video as well. Thanks

[@e...........6293]

sir can you do a video on getting y bar?

[@Vikashkumar-mc3ll]

the centroid of semi circle is 0.63 so the x3 will be 2+6+0.63=8.63

[@sharadkumar8353]

i Came .. i Saw .. i Subscribed ! 😇

[@Engineer4Free]

Awesome, thanks Sharad!!! =)

[@nx6803]

Which software is it that you use to make this video? It looks really nice

[@Engineer4Free]

Hey thanks, I have a full list of software and hardware that I use at engineer4free.com/tools check it out!

[@marcochamba8780]

great explanation, but it would have been better if you do the y bar as well.

[@Engineer4Free]

Thanks, but yeah that was my bad. I didn't bother because at the time when I made this it was a just precursor to simple distributed loading problems wihh vertical loads in which the y bar is never needed, but it could be for sloped members or wind/pressure loading etc... So whoops sorry!

[@zaehdilidili116]

Sir, when will xbar or ybar for the centroid of a shape be equal to zero?

[@Engineer4Free]

X bar will be zero if the centroid lays on the y axis. Y bar will be zero if the centroid lays on the x axis.

[@zaehdilidili116]

Thank you Sir :)

[@motovnc19]

i have a question bro if i want to get the y-bar is it just y-bar=sum(YiAi)/sum(A )

[@Engineer4Free]

yeah

[@Backflipmarine]

Is the y(bar) the sam method except using y values?

[@Engineer4Free]

Yeah, sorry in hindsight I should have also calculated it in this example. See videos 58 and 59 here: engineer4free.com/statics for more info ✌️

[@PC-rl1xe]

Probably late but is the Ybar equal to 0.1630?

[@nurulanisshahira8753]

Hello. I have a question. about to find the x bar for triangle. Im confused wether to use 1/3 or 2/3 . TQ

[@Engineer4Free]

The centroid is 1/3 of the way away from the tall side, and 2/3 of the way away from the short side 😊

[@professional_silent_trumpe1540]

The dislikes are from all the teachers and professors who are obsolete because of you

[@Engineer4Free]

😂 maybeee

[@harithizaham5819]

hye if the triangle is upside down. for y bar i need to use 2(b)/3 again? because it will start from the shortest one?

[@Engineer4Free]

If the triangle was flipped vertically, the short side would still be on the left, so the calculation would be the same.

[@harithizaham5819]

@@Engineer4Free thank u so much

[@sinhikad8325]

What will be the y coordinate of the Center of mass of semicircle

[@Engineer4Free]

The the centroid of a semicircle is 4r/3π away from the flat edge, and halfway between the top and bottom when it's oriented like this. y coordinate is therefore r away from both the top and the bottom

[@baconpancakes8899]

what I want to know is when do I use 2/3 or 1/3 for triangles

[@Engineer4Free]

the centroid is 1/3 of the way from the tall side, and 2/3 of the way from the short side, for right angle triangles in this orientation

[@baconpancakes8899]

@@Engineer4Free Alright thank you

[@otifavour8325]

Why isn't the x of the semi circle 0 here?

[@Engineer4Free]

The center of area of a full circle is in "the middle." Just draw a semicircle by itself and try to locate the "middle." You wouldn't draw the middle touching an edge, it would be about where I have drawn it in this video. Make sense? circles and semicircles are different shapes.

[@leodelameck5725]

Small advice on u is dat the colour that u are using is not well visible how about to use black or red colour?

[@Engineer4Free]

Hey yeah, I made this video quite a long time ago, and have since tried to make the pen stokes more visible. Thanks for the feedback!!

[@nazaningr9970]

10/10

[@waterdrinker7958]

My teacher “taught” me this in 90 minutes when she could have done it in 9!

[@Engineer4Free]

😏

[@charlesdevera6665]

Why is it the x component of the triangle is 2(b)/3?

[@kodygrieve4972]

because hes taking all the measurements from the origin of the graph. the component is 2/3rds from the origin or 1/3 from the nearest side.

[@Engineer4Free]

Yeah thanks for being a bro Kody.

[@charlesdevera6665]

Woahh thanks this helped me a lot in my statics exam. 😁

[@Engineer4Free]

Glad to hear it!!!

[@kodygrieve4972]

absolutely lit fam

[@louisseamistoso1643]

What about the y for the triangle?

[@Engineer4Free]

for a triangle in this orientation, centroid is 1/3 base away from the bottom right corner, and 1/3 height away from the bottom right corner.

[@kinmoto6096]

8 units away form the origin??? so thats start from zero Right??

[@Engineer4Free]

Yea

[@AG-bb3yw]

Great video but so disappointed u didn't do y bar😢

[@marimarrica8240]

What about for y?

[@Engineer4Free]

Yes whoops, I should have also demonstrated ybar. I didn't, because in most statics problems like this, you only need xbar, but ybar is the same, just swap all the x's for y's. so ybar=ΣyiAi/ΣAi

[@kinmoto6096]

So for y I have to use 1/3 ??

[@Engineer4Free]

Yeah, for the triangular section, it ybar is 1/3 of the way up the triangle vs height, from y=0

[@LunaSyren]

I don't get where you found ??1.5??

[@Engineer4Free]

The shape on the right is a semi circle. It is 3 units tall (see y axis). That means the diameter of the (would be full circle) semicircle is 3. Radius is 1/2 diameter, = 3/2 =1.5

[@salimnour]

does any one did, the (y) i have 1.44

[@Engineer4Free]

Yup that is correct!

[@marwaannindheerbirtacalank1485]

salim nour Haa sxp

[@justblaze4707]

Who's bad professor is the reason they are here in 2021!? XD

[@Engineer4Free]

Me 😂

[@somowais.s7240]

Sir pls ask in hindi

[@KenteDominion]

You're not that audible though

[@mehedyhasantanim]

Is the sector of a circle is 2/3 r sinƁ/Ɓ