How to Find Theoretical Yield (2023)

* Convert all amounts to Moles
* Divide all moles by the COEFFICIENT of balanced chemical reaction
* Whichever of those results is lowest corresponds to your LIMITING reactant
* Use that reactant's number of moles and a MOLE RATIO to figure out amount of product made
* Convert to grams if necessary

[@daisydog4251]

Explained this better in 5 minutes than my professor did in an hour

[@Kavin-S]

So true

[@VertexAnimations]

I watched 10+ tuts, and din't get any shit out of them, this explained the concept in less than 6 minutes, W professor.

[@charrhylis]

for some reason theoretical yield is a concept i was NEVER able to wrap my head around no matter how many times it was explained to me. after literal and actual weeks, THIS is the video that's finally managed to drum it into my thick skull. Thanks man

[@VelHazai]

It's the day before the last day of school. I've been stuck on the last problem on my portfolio assignment for hours. I couldn't figure out theoretical yield. I watch this video and in 5 minutes and 21 seconds I finally understand. Thank you very much for this video and teaching me a problem that closely resembles the one I have to do. Thanks again!

[@abcdefg-hv2ks]

I don't know what to say, but thank you SOOO much!! You have NO idea how stressed I was because of chemistry. I couldn't study the entire year and i had only a month left till my exams and i binge watched all your videos and I absolutely aced my chem exam! THANK YOU!!!! You're so underrated, no one else explains topics and solves chem problems like you do. Your way of teaching helped keep focused. You also don't out all your knowledge behind a paywall like most people do.God bless you ♥️ Im an A-level AQA triple science student, so you can guess just how grievous my situation was ahaha.

[@honeydew1411]

How did it go?

[@abcdefg-hv2ks]

@@honeydew1411 Passed 🥳🥳 top of my class.

[@laithtouman1040]

@@abcdefg-hv2ksgood for u my guy. Glad ur finally stress free 👍

[@annakohl2955]

What a great KZbin find. 💯 Thank you for your services

[@giselle3351]

you explained this SO clearly, i finally understand THANK YOU !!

[@adrielisaacs1998]

Thanks dude! I was confused by this for years and you made it so simple.

[@naedagomez9101]

I watched so many videos and could not understand how to do this until I found this one! Thank you so much!

[@adityapatel7577]

Understanding the yield calculation was so easy. I never even thought about it before.

[@GreenMantis27]

You can't belive how much did your video help me... This subject has too many videos explaining too many different useless ways of solving something as simple as you just put it. Great job, you saved me! EDIT: I have a quiestion though... what do I do if I am not given the masses of not the reactants but only of the product?

[@tamarkikvidze]

Perfectly clear, thank you.

[@zeroanime4076]

Thanks sir for uploading such an amazing vid

[@Zenoestequia]

Thank you!!best of luck!

[@toporisnash1324]

Really great explanation!! Thanks so much❤

[@ynnna21]

Thank you so much!!!!

[@albertaawuku6989]

Thank you sooo much Uve really helped me tnx a lot

[@Egghead_12]

You may have just saved my grade, and for that I thank you ✨

[@rim2675]

thank you!

[@TomasKalvach-mb9ti]

Thank you man😊

[@abdulshah4419]

very useful! Thanks a lot

[@oscarwressmark4945]

❤good video

[@IsaacBorland-cv4zi]

Thank you thank you thank you👍👍👍👍👍

[@qualisha5643]

Great explanation this is the only video that’s helpful for me

[@yomeeyu7073]

Thank you!!!:)))

[@idunno...2179]

Very helpful thank youuu

[@nadia3824]

very well explained!!

[@MikeSpizzirri]

genious!

[@madisonsargent6146]

Thank you

[@camillecalma9598]

Angas gagi HAHAHAHA

[@vage_abod6764]

love it

[@kingjoyryan1356]

Good video, bit wanted to ask that what if we don't know the mass of one reactant

[@user-hg4qo4hs4d]

The explanation was great, I finally understand it. Thank You. BUUUT, where did you get the initial 3.0g for 2H2 and the 29.0g of O2. Can you please explain? Thank You,

[@idrisrasak9445]

It's part of the question

[@jademccormick5407]

what if you not given the mases of the reactants only one?

[@mohamedhuseein2626]

Then your screwed

[@weridaxelot9217]

Damn that was faster than the other formula and much easier

[@user-kk1yv2xz5s]

Among the reaction which reactant are we suppose to use for us to find theoretical yield

[@marvellover1015]

How would I find the percent yield with this kind of equation, where neither PY or actual Yield is given. Would the AY be molar mass of a product - the amount of product lost?

[@opufy]

I tried doing this with the net ionic eqn but it didn't give the same mass of product in the end. Strange It's for a quiz retake im doing with the reaction between 0.040 moles of Silver I Nitrate and 50.0 ml of 0.60 M Calcium Chloride.

[@Bangalorian2005]

Hey guys don't think deeply, people who work in pharmaceutical it's very easy to find.. Molecular Weight of your product/Molecular Weight of Starting Material*Batch input(Theoretical yeild), Batch input/Theoretical yeild*100= Percentage of yeild

[@temwanimwika6726]

You might have just saved my chemistry exam😭

[@RebeccaPhiri-ti2yh]

❤🎉

[@honeydew1411]

Isn’t the molar mass 2H2 4?

[@honeydew1411]

Or are we ignoring the mole?

[@JustinKohlberg]

W mans

[@OluwaseunFALANA-sw8yo]

❤❤

[@thobekasilika442]

@chemistNate what happens when you three products

[@user-hk7md1dd4q]

But why dindnt you multiplythe 2 of H2O by the 1.5 of h2

[@sheabutterandroses]

Yes! Wonder why this wasn't the case?

[@isaidmo]

Couldn't understand better

[@MishelWhant-dj7rl]

❤❤❤🇵🇬🇵🇬🇵🇬🇵🇬🇵🇬

[@ttkg6999]

where the hell did you get 18.0 grams from?

[@nabioooooo]

The molar mess of H2O

[@haydenbishop549]

Wa Ter