How to Identify Spectator Ions: Definitions, Examples, & Practice

[@karman1377]

THANK YOU!! my chem teacher just crossed out the spectator ions in her video and I was so confused as to how she knew which were the spectators and you explained it to me in literally a minute!!!

[@wbreslyn]

Glad I could help with spectator ions!

[@lelandgrapes3636]

You went above and beyond with the solubility rules too, I was abt to search another video for that.

[@sofiarayon2252]

Great video as always king! 👑

[@madhurilatadas8632]

Thank you so much.I was very confused about the topic but now everything is clear

[@Aalijah_Matyevna]

I answered my exm question correctly by watching this vid the previous day. Tyy. You are a rlly good teacher.

[@thetripp8489]

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[@davidrichie7130]

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[@reetarahmet6869]

Liked, already subscribed, and bell turned on! Thanks a lot you will get me through my classes with awesome grades! Enjoy watching these for fun in self-isolation. Ur an excellent teacher 😀

[@wbreslyn]

Thank you for the kind words, they are most appercited!

[@vis9273]

I passed my test because of u thank you

[@wbreslyn]

That's great!

[@jonsnoff5369]

Splendid video! Thank you for the help!

[@hananstudies]

You just made it much easier thank you so much

[@pann05]

OMG, thank you so muchhhh. I spent so may hours looking for a good explanation. Liked and subbed. Way better than my room teacher.

[@wbreslyn]

Thanks for the sub!

[@remarkablething5874]

thank you sir- really helpful especially with the solubility rules as well

[@soyongdiptoghosh8753]

finally// finally my sister's doubt has been cleared Thank you doctor

[@wbreslyn]

Excellent!

[@soyongdiptoghosh8753]

@@wbreslyn chemicellent!

[@jessicadu6103]

thank you thank you! The part that confused me was are the spectator ions not changed in the reaction? Or Maybe ions that are left over after a precipitate is formed?

[@yunachoi8465]

I have the same question😭

[@mr.mukherjee5838]

Thank you for the brilliant explanation!🙏

[@raziyabadat7468]

Good video! I liked it and I have got to learn what spectator ions are🙏

[@wbreslyn]

Thanks for watching and liking!

[@ربيعةفاتمة]

Understood this topic finally

[@wbreslyn]

Thanks, that is good to hear!

[@junaidabbas9741]

Thank u my doubt is cleared now I didnt understand it by my school and tuition teachers . thank u

[@bmzaron713]

Dude you're the man

[@user-xb3cy2tg1w]

I literally love you

[@wbreslyn]

Thank you!

[@chezs9847]

Thank you so much! This was very helpful!!

[@hassanpirzada8955]

Thanks so much this helped alot

[@wbreslyn]

No problem!

[@thestudyroom9058]

sir if in a reaction h2o is mentioned do we have to remove it while removing spectator ions? please reply

[@emmanuelorie8260]

You are the best. I've been looking for explanations on ionic charge. Thanks alot

[@wbreslyn]

You are welcome!

[@akumahakainoha7444]

Good understanding

[@wbreslyn]

Thanks!

[@jem1195]

This was soooo helpful thank you

[@wbreslyn]

Glad it was helpful!

[@saudahmed694]

Nice video sir!!! Really helpful

[@wbreslyn]

Glad it was helpful!

[@ashishanand9629]

Love from India sir...... 🙂🙂🙂🙂

[@jiyatyagi8775]

thank you for such a nice explanation!!!

[@wbreslyn]

You are welcome!

[@KikiTeeh]

Love you dad

[@mythicalgamer9014]

Thank you so much man

[@applewine7886]

Thank you sooooo much🫡

[@SstarSiriusA]

Thank you! :D

[@gideoncook7216]

How do you tell what state of matter the molecules are in if it is not listed

[@mohammadhaseeb7392]

Thanks a lot. By the way, I've subscribed way before .

[@wbreslyn]

Awesome, thanks for the sub!

[@midulamahjabin9470]

Hello! Does that mean we do not seperate solid compounds?

[@jacobhelton3985]

Very helpful

[@hishambadrelgammal8271]

Amazing ❤

[@wbreslyn]

Thanks 😄

[@muhammadibraheemali5453]

nice one this video.

[@wbreslyn]

Thanks!

[@mehedihasannobin2151]

Thanks a lot Sir😍

[@wbreslyn]

Most welcome!

[@FAWADKHAN-dj4mc]

HCl plus Naoh....plz explain this on this way

[@maksimklimok4005]

Bro you helped more than my teacher lol

[@wbreslyn]

No problem!

[@mohamedhasanpatel882]

Could you please make a video on how to get the half equations?

[@wbreslyn]

I'll put it on my list, that is a good idea.

[@CodAddict324]

good video

[@sunpreetbajwa8910]

Hey what would the net ionic equation be for Al2(SO4)3 + Ca3(PO4)2 = AlPO4 + CaSO4, I think what I get is wrong but I don't know. Someone help please.

[@wbreslyn]

First you have to balance the molecular equation: kzbin.info/www/bejne/r365iI2qf6x9iqs Interestingly the AlPO4 is insoluble and the CaSO4 is only slightly soluble. So they both would be solids in the product. en.wikipedia.org/wiki/Solubility_chart These videos might help... Introduction to Net Ionic Equations: kzbin.info/www/bejne/hom1eZJ_p7NkZ7s Net Ionic Equations Practice: kzbin.info/www/bejne/nnXWkn1ora5ob9k

[@Suzuchikuma]

4:03 in the of PbI2 ,experimentally I observed, heating PbI2,PbI2 will be dissolved in aquos solution, even if I dont heat the PbI2 , condition of labs, it will also dissociate(less than heat) in half of hours.

[@wbreslyn]

Interesting. Looking at the solubility data for PbI2: Solubility in water 0.044 g/100 mL (0 °C) 0.0756 g/100 mL (20 °C)[1] 0.41 g/100 mL (100 °C)[2] I would agree that some would dissolve (which is the case for all soluble compounds). But that amount would be very, very small, even at 100C. . For the purpose of net ionic equations and solubility we consider this to be insoluble. Source: en.wikipedia.org/wiki/Lead(II)_iodide

[@Suzuchikuma]

@@wbreslyn just little portion of test tube, yeah, maybe that's really low dissociation even with 100°C aprox, but it's observable and significant kinetically

[@wbreslyn]

@@Suzuchikuma Absolutely significant!

[@rosecomet18]

so everything thats the same is a spectator ion?

[@elijahfunk2710]

What are non-spectator ions called?

[@wbreslyn]

I'd call them participating ions. These are the ions that actually participate in the chemical reaction, forming new products.

[@Catkid]

7:53 you wrote the 3 for the nitrate as part of the charge.

[@Catkid]

on the left side

[@karlavillanueva2493]

Why was the BaSO4 not split up like the others ?

[@samanthalucien2826]

I think that's because its a solid so you don't split it up.

[@kapilsharma8902]

Thanks

[@wbreslyn]

Welcome!

[@hashtagunderscore8551]

Why pb +2 not -4

[@bhavikayadav2626]

What if both the reactants and products are aqueous, will there be no spectator ions? Like, NaCH3COO (aq) + HCl (aq) = NaCl (aq) + HCH3C00 (aq)

[@wbreslyn]

Since CH3COOH (also written HC2H3O2) is a weak acid we say it would not dissociate into ions (only a small amount would). So the spectator ions would be Na+ and Cl- since NaCH3COO and NaCl are soluble (these ions would be on both sides of the equation and therefore spectator ions).

[@tkhue3296]

02:50 the arrow points to the wrong ions, 3NaOh should point to 3Ns+ and 3Oh- .

[@wbreslyn]

Thanks for the quick eye! I'll fix when I have a chance.

[@tkhue3296]

@@wbreslyn appreciate your video, it helps a lot .

[@oshim2912]

Why wasn’t barium sulphate split apart into its ions

[@wbreslyn]

Because it is insoluble. We don't split insoluble compounds apart in net ionic equations.

[@oshim2912]

@@wbreslyn ohhh thank you I understand now :)

[@franksaronge1922]

@@wbreslyn what about the reaction between CaCO3 and Hcl,? Help me with the net ionic equation please

[@franksaronge1922]

@@wbreslyn what about the reaction between CaCO3 and Hcl,? Help me with the net ionic equation please

[@wbreslyn]

@@franksaronge1922 Here you go: kzbin.info/www/bejne/b3XCYYFof6akea8 Note, CaCO3 should not be split apart in the reaction since it is a solid. The final net ionic equation should have CaCO3 (s).

[@shaziafayyaz1213]

Hello sir Do you have instagram cuz I want to send you a picture(question I am having trouble with)

[@wbreslyn]

Sorry, I do not. KZbin keeps me busy enought!

[@quackk4763]

King

[@FAWADKHAN-dj4mc]

U r wrong bro

[@wbreslyn]

Could you explain why? Always happy to fix things if there are problems!

[@silverlyder]

Thanks