How to Make a Buffer

  Рет қаралды 4,032

Old School Chemistry

Old School Chemistry

Күн бұрын

Пікірлер: 11
@zach1978
@zach1978 18 күн бұрын
Prof. Laub, I want to thank you for all of the time and energy you put into making this entire playlist! I'm so grateful to you, you've helped me so much this year in Gen Chem 2!
@OldSchoolChemistry
@OldSchoolChemistry 17 күн бұрын
Hi Zach, that makes me so happy that it has been helpful. Thank you for letting me know. CHEM 2 is a tough class. I am proud of your extra work:) God bless you!
@maxsalzer2561
@maxsalzer2561 4 жыл бұрын
Very easy to follow! Excellent video!
@angieg7257
@angieg7257 3 ай бұрын
Great video! Thank you, It was very helpful.
@OldSchoolChemistry
@OldSchoolChemistry 3 ай бұрын
Hi Angie, I am so glad it was helpful. Thank you for your comment!
@everythingbuthair
@everythingbuthair 3 жыл бұрын
this is so incredibly helpful thank you!!!!!
@OldSchoolChemistry
@OldSchoolChemistry 3 жыл бұрын
Hi Tess, I’m so glad I hope your class class well!😊
@OldSchoolChemistry
@OldSchoolChemistry 3 жыл бұрын
Hi Tess, first find the ratio of CB to A using Henderson Hasselbalch. The pka is 9.26. I got .1413 moles CB to 1 mole acid. Find the moles of base. I got .444 moles base in the solution. Using the previous ratio determine the moles of acid needed. I got 3.14 moles acid. Use molar mass to find grams. I got 308g. I hope that helps!!
@everythingbuthair
@everythingbuthair 3 жыл бұрын
​@@OldSchoolChemistry I see my error was plugging in the 0.444 into the HA half of the ratio instead of the A-. thank you so much for responding !!! What about if it was asking for strong acid/base instead of g salt? "How many moles of sodium hydroxide would have to be added to 250 mL of a 0.477 M acetic acid solution, in order to prepare a buffer with a pH of 4.770?" would the work be relatively the same as this video, but instead of the ratio/1, ratio/0.5?
@OldSchoolChemistry
@OldSchoolChemistry 3 жыл бұрын
Hi Tess, do initial/final moles. From the final moles plug the acid and conjugate base amounts into Henderson Hasselbalch. Here is a video, just the first part, to do initial/final moles. kzbin.info/aero/PL0xN_H1gE3VeFFvhiRF8HiR26vMLu9qgq
@everythingbuthair
@everythingbuthair 3 жыл бұрын
@@OldSchoolChemistry you are so kind, thank you for your time! i wish watch them all!!
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