LeChatelier Principle: Change Pressure

[@snook1150]

all i needed was the thought process to truly understand it instead of just memorizing, no one else provided it with such clarity, very grateful

[@OldSchoolChemistry]

Hi Snook, that makes me so pleased it was helpful. I am proud of you for wanting to UNDERSTAND and not just memorize. Well done! :)

[@pranavborse91]

thank you, you explained it so much better than the textbook!

[@OldSchoolChemistry]

Hi Pranav, I am so glad! Thank you for your comment:)

[@MsNisar-u8f]

This was the best among all the KZbin lessons..❤

[@OldSchoolChemistry]

Hi Ms. Nisar, thank you so much! I appreciate you watching. :)

[@aerdis3814]

This channel should have millions of subscribers. Great video.

[@OldSchoolChemistry]

Hi Erdis - thank you! I hope so😃 Thanks again!

[@baraskparas]

Essential chemistry, explained clearly. Thanks.

[@EvanTang-g8f]

omg thank you so much. I was struggling before just reviewing my notes and reading the book. Its not just this video, but your other equllibrium videos, and other videos in general has helped me so much! Thank you!!

[@OldSchoolChemistry]

Hi Evan, I am SO glad. Thank you for letting me know. I hope your class goes well.

[@EvanTang-g8f]

@@OldSchoolChemistry I ended up getting a 90 on the final and ended with an A. Thank you so much!!!!

[@OldSchoolChemistry]

@@EvanTang-g8f Evan! Way to go!!! I am so proud of you. Your extra effort and hard work paid off. Well done:)

[@johnnubari8469]

Learning effect of conc n pressure today has taken me almost the whole day untill i met your video, thank you very much love you

[@OldSchoolChemistry]

Hi John, wonderful! That makes me so happy. Thank you for your comment:)

[@rayowork]

Thanks from kurdistan🇹🇯 for your great vedio with best explained❤🎉

[@OldSchoolChemistry]

Hi Rayowork, Greetings to you in Kurdistan! I am proud of your hard work. Thank you for your kind comment:)

[@EmmaTharman-ws4vv]

I love you mom. You’ve helped me much ❤

[@OldSchoolChemistry]

Hi Emma, I'll take you any time! I have 5 daughters. You would fit right in:)💗

[@lleuwfps]

thank you teacher (This thank you comes directly from Brazil)

[@OldSchoolChemistry]

Hi lleuwfsp, You are welcome:) Greetings to you in Brazil!

[@TarushiSah]

This great teacher❤ Love from India 🇮🇳

[@OldSchoolChemistry]

Hi Tarushi, thank you for your kind comment! Sending love to you from the USA💗

[@samarth1698]

I am from india preparing for my medical exam …. I was struggling in this thanks for helping

[@OldSchoolChemistry]

Hi Samarth, I am glad it was helpful. I am so proud of your hard work. God bless you on your exam!

[@lassejrgensen9956]

have an exam in chem tomorrow, this channel clutched it, tysm

[@OldSchoolChemistry]

Hi Lasse, Wonderful! I am so proud of your extra effort and work. Good luck on the test:)

[@nalabrown4839]

You truly are heaven sent thank you so much !

[@OldSchoolChemistry]

Hi Nala, You are so kind. I am glad it was helpful. Thanks:)

[@dhilanamin6018]

yo this made it clear to understand, thank you!

[@OldSchoolChemistry]

Hi Dhilan, I am so glad! Thank you for your comment:)

[@gameblitz202]

You explained very well as compared to others ❤

[@OldSchoolChemistry]

Hi Pocky, I am so glad you think so. Thank you for commenting!

[@gameblitz202]

@@OldSchoolChemistry Most welcome and best of luck

[@sneha66a49]

This is is a really helpful video. Thanks so much, also I just subscribed :)

[@OldSchoolChemistry]

Oh, great!! Thanks so much🎉🎉

[@yousrayousri4190]

Will there be a change in equilibrium if you add a catalyst?

[@OldSchoolChemistry]

No:) The reaction will achieve equilibrium faster but equilibrium does not shift. Great question!

[@wycliffenyandika9017]

Love your videos ! Do you still make more ?

[@OldSchoolChemistry]

Hi Wycliffenyandika, Thank you for the comment. I only made a couple of videos the past year. In the fall I will begin making videos with homework problems. Thanks!

[@OldSchoolChemistry]

@@EmaanIqbal-bb1yy Thank you for your comments Emaan! I hope you have a good chemistry class experience:)

[@gio3798]

My queen, i love you 🥲

[@yeorimpark]

Hello, thank you for this informative video! For the reaction written below, H2 + Cl2 --> 2HCl, which way would the equilibrium shift if pressure was increased? Or would it change at all, since they both have 2 moles on each side.

[@OldSchoolChemistry]

Hi Yeorimpark, you are correct! If you have the same number of gas moles on the reactant and product sides of the reaction, there is no shift in equilibrium with a change of pressure or volume. Thanks! :)

[@mohdsajid5629]

Amazing explanation

[@OldSchoolChemistry]

Hi Mohd, I am glad you think so. Thank you!

[@prachisharma457]

Thank you very much for this Ma'am, It was very helpful. I had a question that if we introduce an inert gas during the reaction, do we take the change in pressure in that case as well??

[@OldSchoolChemistry]

Hi Prachisharma, here is a great explanation from Chemistry Libre Texts: Add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: This will increase the total pressure of the system, but will have no effect on the equilibrium condition. That is, there will be no effect on the concentrations or the partial pressures of reactants or products. Thanks!

[@prachisharma457]

@@OldSchoolChemistryThanks for your explanation Ma'am, I'm sorry but I think I'm still not really sure about why will the reaction not move towards the side with lesser no. of moles. Does that have to do with the volume being constant?

[@OldSchoolChemistry]

@@prachisharma457 I am sorry, I do not understand the question. Are you referring to one of the examples in the video?

[@prachisharma457]

@@OldSchoolChemistry No, I was considering the addition of inert gas in a given reaction.

[@OldSchoolChemistry]

@@prachisharma457 The inert gas will not change the partial pressures of the gases in the container. The overall pressure of the container will increase. I hope that helps! Thanks:)

[@ED-gq1ds]

Thanks for the video is so helpful. but I have a question what if is in endothermic or exothermic reaction

[@OldSchoolChemistry]

Then you have two impacts at once. Consider both. It takes advanced knowledge and math to predict the shift if you change both temperature and pressure.

[@ED-gq1ds]

@@OldSchoolChemistry do you have a video on that so I can watch please

[@OldSchoolChemistry]

@@ED-gq1ds I am sorry I do not :/

[@오가연-t4m]

Thank you so much!!

[@OldSchoolChemistry]

You are very welcome:) Thank you for your comment!

[@mahmoudwahidi8873]

a blessing

[@OldSchoolChemistry]

Hi Mahmoud, what a great comment. Thank you. God bless you!

[@ShivamMaisuriya-io1vi]

Thx really helpful

[@OldSchoolChemistry]

Hi Shivam, I am so glad! I hope your class goes well:)

[@lubegamathias3862]

ilike ur explanation

[@OldSchoolChemistry]

Hi Lubega, I am so glad! Thank you for your response:)

[@Wvwwvwvve]

I wish you were my teacher

[@OldSchoolChemistry]

Hi H7, I wish you were my student! I hope your class goes well:)

[@Alkimachos]

Watching this 8 min before lab quiz

[@OldSchoolChemistry]

I hope it went well!!

[@Alexis.j3nni]

Thank you!!

[@OldSchoolChemistry]

Hi Jenni, you are so welcome. I hope chemistry goes well for you. Please subscribe if you have not already. Thanks!

[@Alexis.j3nni]

@@OldSchoolChemistry already did :))

[@OldSchoolChemistry]

You’re awesome. Thanks😊

[@luciddoggo5094]

Super helpful

[@OldSchoolChemistry]

Hi Lucid, I'm so glad. I hope chemistry goes well for you. Please subscribe if you have not already.😊

[@Aisha-gd6dq]

Thank you❤❤❤❤

[@OldSchoolChemistry]

Hi Aisha, You are welcome!! :)

[@herreraherrera4462]

Sorry am dumb ,but how do you know how many moles each side have ?

[@OldSchoolChemistry]

Hi Herrera Herrera, that is not a dumb question. It is a great question! You add the molar coefficients (those are the large numbers in front of the compounds) on the reactants side and product side. For example every species in this chemical equation is a gas: 1 N2 + 3 O2 -> 2 NH3. There are 2 moles on the product side and 4 moles on the reactants side. I hope that helps!

[@herreraherrera4462]

@@OldSchoolChemistry thank you!! It helped

[@OscarJuvera]

Thank you so much for the lovely explanation! Super side note, have you ever been told you look like Dakota Johnson, or maybe I should say, Dakota Johnson looks like you lol. Either way, thank you again!

[@OldSchoolChemistry]

Hi Oscar, I am glad it was helpful. Thank you for the kind compliment:)

[@SonuKumar-kh4wl]

Great

[@OldSchoolChemistry]

Hi Sonu, thank you! I appreciate your comment:)

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The most beautiful woman I wish to enter heaven ❤️

[@ande5090]

Can I just say that u r really really beautiful 😊

[@lukuwazzow9553]

H20 is a liquid not a gas but you counted it

[@OldSchoolChemistry]

Hi Lukuwazzow, water is counted because it has the (g) phase written next to it. I hope that helps. Thanks!

[@itsyeboiandrew]

came for help in equilibria, now i’m in love with this teacher🫠

[@OldSchoolChemistry]

Hi @isyeboiandrew, I am so glad it was helpful. Thank you for watching!