How to prepare 0.1 N H2SO4 solution| 0.5N H2SO4 solution| 1N h2SO4 solution # sulphuric acid

[@usmanqurashi4596]

nice work

[@chrissamano-wy3sf]

Thank you very helpful

[@miteshram9902]

🎉

[@SnowtanJon]

Your first video, Molar, Normal solution preparation and this video.. What’s the difference between those two? Why calculation is different? Very beneficial video, Thanks.

[@pharmacheminsights]

In first video of molarity and normality... I had given direct formula to calculate molarity and normality for solids and liquids... In second video I had explained in detail how to prepare 0.1N H2S04 using N1V1= N2V2 formula. You can use first video formula also to prepare 0.1N H2SO4... You will get same answer. Both are correct

[@SnowtanJon]

@@pharmacheminsights Thank you

[@HadjarBenyoucef-db6hd]

Please answer me (How can we prepare a solution of H,SO, at 0.1 N, we give H,SO, (98%, 1.83), in a volume of 500 ml knowing that the molar mass of H,SO, 98.079 g/mol?)

[@pharmacheminsights]

98% conc. H2SO4 having a density of 1.83 is 36.8 N (refer to video for calculations) To prepare 500 ml (volume) of 0.1N H2SO4 we have the formula N1V1 (Conc H2SO4) = N2V2 (Required solution) 36.8 x V1 = 0.1 x 500 V1 = 1.36 ml So, 1.36 ml of conc. H2SO4 diluted to 500 ml with water gives 0.1 N H2SO4

[@HadjarBenyoucef-db6hd]

@@pharmacheminsights thank you 😊